Materials Science And Engineering Properties
1st Edition
ISBN: 9781111988609
Author: Charles Gilmore
Publisher: Cengage Learning
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Chapter 11, Problem 18CQ
To determine
The technique by which the crack is detected by ultrasonic pulse-echo technique.
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A thin plate of a ceramic material with E = 225 GPa is loaded in tension, developing a stress of 450 MPa. Is the specimen likely to fail if the most severe flaw present is an internal crack oriented perpendicular to the load axis that has a total length 0.25 mm and a crack tip radius of curvature equal to 1 μm?
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A structural component in the form of a wide plate is to be fabricated from a steel alloy that has a plane strain fracture toughness of 98.9 MPa sqrt(m) (90 ksi sqrt(in.)) and a yield strength of 860 MPa (125,000 psi). The flaw size resolution limit of the flaw detection apparatus is 3.0 mm (0.12 in.). If the design stress is one-half of the yield strength and the value of Y is 1.0, determine whether or not a critical flaw for this plate is subject to detection.
State five(5) practical consideration in its application type of material property that is found during test noticed a progressive crack formation which was fine and of microscopic size.
Chapter 11 Solutions
Materials Science And Engineering Properties
Ch. 11 - Prob. 1CQCh. 11 - Prob. 2CQCh. 11 - Prob. 3CQCh. 11 - Prob. 4CQCh. 11 - Prob. 5CQCh. 11 - Prob. 6CQCh. 11 - Prob. 7CQCh. 11 - Prob. 8CQCh. 11 - Prob. 9CQCh. 11 - Prob. 10CQ
Ch. 11 - Prob. 11CQCh. 11 - Prob. 12CQCh. 11 - Prob. 13CQCh. 11 - Prob. 14CQCh. 11 - Prob. 15CQCh. 11 - Prob. 16CQCh. 11 - Prob. 17CQCh. 11 - Prob. 18CQCh. 11 - Prob. 19CQCh. 11 - Prob. 20CQCh. 11 - Prob. 21CQCh. 11 - Prob. 22CQCh. 11 - Prob. 23CQCh. 11 - Prob. 24CQCh. 11 - Prob. 25CQCh. 11 - Prob. 26CQCh. 11 - Prob. 27CQCh. 11 - Prob. 28CQCh. 11 - Prob. 29CQCh. 11 - Prob. 30CQCh. 11 - Prob. 1ETSQCh. 11 - Prob. 2ETSQCh. 11 - Prob. 3ETSQCh. 11 - Prob. 4ETSQCh. 11 - Prob. 5ETSQCh. 11 - Prob. 6ETSQCh. 11 - Prob. 7ETSQCh. 11 - Prob. 8ETSQCh. 11 - Prob. 9ETSQCh. 11 - Prob. 10ETSQCh. 11 - Prob. 11.1PCh. 11 - Prob. 11.2PCh. 11 - Prob. 11.3PCh. 11 - Prob. 11.4PCh. 11 - Prob. 11.5PCh. 11 - Prob. 11.6PCh. 11 - Prob. 11.7PCh. 11 - Prob. 11.8PCh. 11 - Prob. 11.9PCh. 11 - Prob. 11.10PCh. 11 - Prob. 11.11PCh. 11 - Prob. 11.12PCh. 11 - Prob. 11.13PCh. 11 - Prob. 11.14P
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- According to Irwin plastic deformation at the crack tip results in an apparently longer crack Kl= o √(a + ry) where ry is the radius of the plastic zone, what will the Kl solution became if we realize that Kl affects the size of . ry while ry also affects the size of klarrow_forwardWhat is the advantage of bonding tabs to the ends of the FRP specimen when conducting tensile test?(150 minimum words)arrow_forwardA structural component in the shape of a flat plate 20.8 mm thick is to be made from a metal with yield strength of 533 MPa and a critical fracture toughness of 22.0 MPa-m!2. Assume a crack forms in the plate, and the geometry of the crack yields a Y value of 1.5. If the plate is designed to a design stress equivalent to 0.3 times the yield strength, what is the critical crack length? Equations: 1/2 () Om К = 2 σο K. = YocTa %3D Ptarrow_forward
- Which of the following statements regarding brittle failure and crack propagation is CORRECT? Elastic energy is consumed when a crack propagates, due to unloading of a volume of material. Energy is released when the surface area of a material increases, as a result of crack propagation. O The stress at the tip of a crack is less than the nominal stress (force over the cross-sectional area of the component) because the stress flows around the defect. O The fracture toughness of a material is its resistance to an increase in the radius of curvature of a crack. O A material will fail in brittle fashion when the stress intensity at the crack tip is greater than the fracture toughness of the material.arrow_forwardThe thin square plate shown is uniformly deformed such that E - +1425 µE, E, - -668 uE, and ygy - +1125 prad. Determine the normal strain &, in the plate. 60 mm O -255 uE O -233 uE O -202 uE Ο -220 με O -184 uEarrow_forwardFailure of engineering materials A specimen of a 4340 steel alloy with a plane strain fracture toughness of 54.8 MPa is exposed to a stress of 1766 MPa. Assume that the parameter Y has a value of 1.6.If the largest surface crack is 0.5236 mm long, determine the critical stress .arrow_forward
- The (G-E) diagram obtained in the tensile test performed on a metal sample with a diameter of 16 mm is as follows. The loads at points A, B and C and the elongation measured on l. 16 cm gauge length were determined as follows: B A B C Load (kgf) 4800 8400 7200 Elongation (mm) 0.192 28.8 38.4 c) Calculate the fracture work and the maximum elastic energy the metal rod can store. d) Find the cross-sectional area of a 6 m long rod made of this metal such that it can carry 12 tons of load with 2 times the safety of yield strength. How long does the rod extend under this load?arrow_forwardA ceramic part is used under a complete reverse cyclic stress with a stress amplitude (S) of 250 MPa. The yield strength and fracture toughness of materials is 550 MPa and 12.5 MPa*sqrt(m), respectively. Y is 1.4. What is the critical surface crack length?arrow_forwardWhat is the critical assumption made regarding the area of the particle-to-particle contacts in deriving effective stress?arrow_forward
- A Brinell hardness tester with a diameter of 10 mm and a load of 500 kg gives an impression with a diameter of 1.62 mm in a steel alloy. Calculate the Brinell hardness (HB) in the steel alloyarrow_forwardA chemicals company is looking to optimise the materials selection for their synthesis vessel with safety being the key priority. The tank can be treated as a small thin-walled spherical pressure vessel and the engineers are considering a 'yield before break' design concept. Given that a crack of length will propagate by fast fracture when the stress intensity factor reaches the fracture toughness of the material select the correct materials property index relevant to this design criterion. Fracture toughness K₁=Yo√na IC OM= OM= OM= KIC of OM= d OM= P K 2 IC K IC P o a M= K IC K 2 ICarrow_forward
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