Materials Science And Engineering Properties
1st Edition
ISBN: 9781111988609
Author: Charles Gilmore
Publisher: Cengage Learning
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Chapter 11, Problem 9ETSQ
To determine
The procedure not to be expected to increase the fatigue crack initiation life of plain low carbon steel.
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A high-strength steel has a yield strength of 1380 MPa and fracture toughness of 91 MPavm. A
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Chapter 11 Solutions
Materials Science And Engineering Properties
Ch. 11 - Prob. 1CQCh. 11 - Prob. 2CQCh. 11 - Prob. 3CQCh. 11 - Prob. 4CQCh. 11 - Prob. 5CQCh. 11 - Prob. 6CQCh. 11 - Prob. 7CQCh. 11 - Prob. 8CQCh. 11 - Prob. 9CQCh. 11 - Prob. 10CQ
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- After an inspection it is found that a structural ceramic part has no flaws greater than 100 micrometers in size, calculate the maximum service stress (in MPa) available with SiC. Assume that Y= 1arrow_forwardQuestion-5 The following engineering stress-strain data were obtained from the tensile test for a 0.2% plain carbon steel. (a) Plot the engineering stress-strain curve for these data. (b) Determine the 0.2 percent offset yield stress for this steel. (c) Determine the tensile elastic modulus of this steel. (d) Determine the ultimate tensile strength of the alloy. (e) Determine the percent elongation at fracture. Engineering stress (ksi) 0 30 55 60 68 72 74 75 Engineering strain (in./in.) 0 0.001 0.002 0.005 0.01 0.02 0.04 0.06 Engineering stress (ksi) 76 75 73 69 65 56 51 Engineering strain (in./in.) 0.08 0.10 0.12 0.14 0.16 0.18 (Fracture) 0.19 Question-6 A 20-cm-long rod with a diameter of 0.250 cm is loaded with a 5000 N weight. If the diameter decreases to 0.210 cm, determine (a) the engineering stress and strain at this load and (b) the true stress and strain at this load.arrow_forward(b) An aluminium plate (100 mm width x 300 mm height x 4 mm thick) with a centre-crack is subjected to a mode-l service load of 40 kN. Assume that the fracture toughness of the material is 24 MPa Vm and Y-1.0. (ii) What is the safety factor on crack length? Assume that the yield strength of aluminium is 425 MPa.arrow_forward
- A structural component in the shape of a flat plate 24.3 mm thick is to be fabricated from a metal alloy for which the yield strength and plane strain fracture toughness values are 533 MPa and 22.0 MPa-m1/2, respectively. For this particular geometry, the value of Y is 1.3. Assuming a design stress of 0.4 times the yield strength, calculate the critical length of a surface flaw. What formulas do i use ? And how do i use them?arrow_forwardFor a specimen of a steel alloy with a plane strain fracture toughness of 80 MPa√m, fracture results at a stress of 510 MPa when the maximum (or critical) internal crack length is 6 mm. For the same alloy, will fracture occur at a stress level of 380 MPa when the maximum internal crack is 9.0 mm? Why or why not? Select the most appropriate answer based on your calculation. Select one: a. It will not fracture b. Not enough information c. It will fracturearrow_forward
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