Chemistry: Principles and Practice
3rd Edition
ISBN: 9780534420123
Author: Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher: Cengage Learning
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Chapter 11, Problem 11.73QE
Interpretation Introduction
Interpretation:
The density of the nickel has to be given.
Concept Introduction:
The density of a substance is given by the ratio of its mass to its volume,
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Chapter 11 Solutions
Chemistry: Principles and Practice
Ch. 11 - Prob. 11.1QECh. 11 - Prob. 11.2QECh. 11 - Prob. 11.3QECh. 11 - Prob. 11.4QECh. 11 - Prob. 11.5QECh. 11 - Why does a perspiring body achieve greater cooling...Ch. 11 - Prob. 11.7QECh. 11 - Prob. 11.8QECh. 11 - Prob. 11.9QECh. 11 - Prob. 11.10QE
Ch. 11 - Prob. 11.11QECh. 11 - Prob. 11.12QECh. 11 - Prob. 11.13QECh. 11 - Prob. 11.14QECh. 11 - Prob. 11.15QECh. 11 - Prob. 11.16QECh. 11 - Prob. 11.17QECh. 11 - Prob. 11.18QECh. 11 - Prob. 11.19QECh. 11 - Prob. 11.20QECh. 11 - The compounds ethanol (C2H5OH) and dimethyl ether...Ch. 11 - Prob. 11.22QECh. 11 - Prob. 11.23QECh. 11 - An amorphous solid can sometimes be converted to a...Ch. 11 - Prob. 11.25QECh. 11 - Prob. 11.26QECh. 11 - Prob. 11.27QECh. 11 - Prob. 11.28QECh. 11 - Prob. 11.29QECh. 11 - Prob. 11.30QECh. 11 - Prob. 11.31QECh. 11 - Prob. 11.32QECh. 11 - Prob. 11.33QECh. 11 - Prob. 11.34QECh. 11 - Prob. 11.35QECh. 11 - Prob. 11.36QECh. 11 - Prob. 11.37QECh. 11 - Prob. 11.38QECh. 11 - What is the enthalpy change when a 1.00-kg block...Ch. 11 - Prob. 11.40QECh. 11 - Prob. 11.41QECh. 11 - Prob. 11.42QECh. 11 - Prob. 11.43QECh. 11 - Prob. 11.44QECh. 11 - Prob. 11.45QECh. 11 - Prob. 11.46QECh. 11 - Prob. 11.47QECh. 11 - Prob. 11.48QECh. 11 - Identify the kinds of intermolecular forces...Ch. 11 - Prob. 11.50QECh. 11 - Prob. 11.51QECh. 11 - Prob. 11.52QECh. 11 - Prob. 11.53QECh. 11 - Prob. 11.54QECh. 11 - Prob. 11.55QECh. 11 - Prob. 11.56QECh. 11 - Prob. 11.57QECh. 11 - Prob. 11.58QECh. 11 - Prob. 11.59QECh. 11 - Identify the kinds of forces that are most...Ch. 11 - Arrange the following substances in order of...Ch. 11 - Arrange the following substances in order of...Ch. 11 - Prob. 11.63QECh. 11 - Silicon carbide, SiC, is a very hard, high-melting...Ch. 11 - Prob. 11.65QECh. 11 - Calcium oxide consists of a face-centered cubic...Ch. 11 - Prob. 11.67QECh. 11 - Prob. 11.68QECh. 11 - Prob. 11.69QECh. 11 - Prob. 11.70QECh. 11 - Prob. 11.71QECh. 11 - Prob. 11.72QECh. 11 - Prob. 11.73QECh. 11 - Prob. 11.74QECh. 11 - Lithium hydride (LiH) has the sodium chloride...Ch. 11 - Cesium iodide crystallizes as a simple cubic array...Ch. 11 - Palladium has a cubic crystal structure in which...Ch. 11 - Prob. 11.78QECh. 11 - Prob. 11.79QECh. 11 - Prob. 11.80QECh. 11 - Prob. 11.81QECh. 11 - Prob. 11.82QECh. 11 - Prob. 11.83QECh. 11 - Prob. 11.84QECh. 11 - Prob. 11.85QECh. 11 - The coordination number of uniformly sized spheres...Ch. 11 - Prob. 11.87QECh. 11 - Prob. 11.88QECh. 11 - Prob. 11.89QECh. 11 - Prob. 11.90QECh. 11 - Prob. 11.91QECh. 11 - Prob. 11.93QECh. 11 - Prob. 11.94QECh. 11 - A 1.50-g sample of methanol (CH3OH) is placed in...Ch. 11 - Prob. 11.96QECh. 11 - Prob. 11.97QECh. 11 - Prob. 11.98QECh. 11 - Prob. 11.99QECh. 11 - Prob. 11.100QECh. 11 - Prob. 11.103QE
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- The coordination number of uniformly sized spheres in a cubic closest-packing (FCC) array is 12. Give the coordination number of each atom in (a) a simple cubic lattice. (b) a body-centered cubic lattice.arrow_forwardThe unit cell of silicon carbide, SiC, is illustrated below. (a) In what type of unit cell are the (dark gray) C atoms arranged? (b) If one edge of the silicon carbide unit cell is 436.0 pm, what is the calculated density of this compound? A portion of the solid-state structure of silicon carbide.arrow_forwardThe density of polonium metal is 9.2 g/cm3. If the extended lattice of polonium exhibits a simple cubic unit cell, estimate the atomic radius of polonium.arrow_forward
- Lithium hydride (LiH) has the sodium chloride structure, and the length of the edge of the unit cell is 4.086 108 cm. Calculate the density of this solid.arrow_forwardThe CsCl structure is a simple cubic array of chloride ions with a cesium ion at the center of each cubic array (see Exercise 69). Given that the density of cesium chloride is 3.97 g/cm3, and assuming that the chloride and cesium ions touch along the body diagonal of the cubic unit cell, calculate the distance between the centers of adjacent Cs+ and Cl ions in the solid. Compare this value with the expected distance based on the sizes of the ions. The ionic radius of Cs+ is 169 pm, and the ionic radius of Cl is 181 pm.arrow_forward(a) Determining an Atom Radius from Lattice Dimensions: Gold has a face-centered unit cell, and its density is 19.32 g/cm3. Calculate the radius of a gold atom. (b) The Structure of Solid Iron: Iron has a density of 7.8740 g/cm3, and the radius of an iron atom is 126 pm. Verify that solid iron has a body-centered cubic unit cell. (Be sure to note that the atoms in a body-centered cubic unit cell touch along the diagonal across the cell. They do not touch along the edges of the cell.) (Hint: The diagonal distance across the unit cell = edge 3.)arrow_forward
- Outline a two-dimensional unit cell for the pattern shown here. If the black squares are labeled A and the white squares are B, what is the simplest formula for a compound based on this pattern?arrow_forwardAt room temperature, the edge length of the cubic unit cell in elemental silicon is 5.431 Å, and the density of silicon at the same temperature is 2.328 g cm-3 . Each cubic unit cell contains eight silicon atoms. Using only these facts, perform the following operations.(a) Calculate the volume (in cubic centimeters) of one unit cell.(b) Calculate the mass (in grams) of silicon present in a unit cell.(c) Calculate the mass (in grams) of an atom of silicon.(d) The mass of an atom of silicon is 28.0855 u. Estimate Avogadro’s number to four significant figures.arrow_forwardplatinum crystallizes in a FCC lattice with all atoms at the lattice points It has a density 1338.905 lb/ft^3 and an atomic weight of 0.195108 kg/mol. From these data , calculate the length of a unit cell edge . Compare this with the value of 392.4 pm obtained from x - ray diffraction .arrow_forward
- NiO adopts the face-centered-cubic arrangement. Given that the density of NiO is 6.67 g/cm3, calculate the length of the edge of its unit cell (in pm).arrow_forwardThe element lead (Pb) crystallizes with a Face Centered Cubic unit cell. The density of lead is 11.3 g/cm3. Use this information to calculate the theoretical metallic radius of a lead atom in picometers. 1 pm = 1×10−12 meters [Note: The theoretical value for the metallic radius may be different from the experimentally determined value. Simply Googling the value of atomic radius may not yield the correct result]arrow_forwardNickel crystallizes in a face-centered cubic lattice. If the density of the metal is 8.908 g.cm3 and its atomic weight is 58.6934 g/mole, what is the mass of an atom of Ni? Volume in cell? Edge length? And radius?arrow_forward
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