(a)
Interpretation:
The moles of
Concept Introduction:
Titration: It is a quantitative analysis method used to express the concentration of acid or base present in the solution.
For an
That is,
Molarity: The concentration for solutions is expressed in terms of molarity as follows,
Moles: One mole is equivalent to the mass of the substance consists of same number of units equal to the atoms present in
The normality for any acid or base equals the molarity times of the number of
Equivalent of Acid: Generally, 1 equivalent of ion is the number of ions which has charge of one mole.
(b)
Interpretation:
The molarity for
Concept Introduction:
Titration: It is a quantitative analysis method used to express the concentration of acid or base present in the solution.
For an acid-base titration
That is,
Molarity: The concentration for solutions is expressed in terms of molarity as follows,
Moles: One mole is equivalent to the mass of the substance consists of same number of units equal to the atoms present in
The normality for any acid or base equals the molarity times of the number of
Want to see the full answer?
Check out a sample textbook solutionChapter 10 Solutions
Fundamentals of General, Organic, and Biological Chemistry (8th Edition)
- Thimerosal Tincture USP contains 0.1% w/v thimerosal and 50% v/v ethyl alcohol. If the cap is left off of a 15-mL bottle of the tincture, and the ethyl alcohol evaporates leaving a final volume of 9.5 mL, what is the concentration of thimerosal in the evaporated solution expressed as a ratio strength?arrow_forwardYou need to prepare an acetate buffer of pH 5.43 from a 0.621 M acetic acid solution and a 2.95 M KOH solution. If you have 730 mL of the acetic acid solution, how many milliliters of the KOH solution do you need to add to make a buffer of pH 5.43? The pKa of acetic acid is 4.76. Be sure to use appropriate significant figures.arrow_forwardWhat is the final volume of NaOH solution prepared from 100.0 mL of 0.500 M NaOH if you wanted the final concentration to be 0.150 M?arrow_forward
- Determine the weight/volume of the chemicals needed to prepare the following solutions: a) 100 ml of 0.9% (w/v) saline (NaCl) b) 30 ml of 50% glycerol (v/v) c) Electrophoresis requires TAE, which is a specific mixture of Tris base, acetic acid, and EDTA. TAE is normally made as a 50X concentrated stock. Provide a recipe to make 40 ml of 50X TAE. The recipe for one liter of 50X TAE is as follows: 242g Tris base, 57.1 ml glacial acetic acid, 100 ml 0.5 M EDTAarrow_forwardWhat would be the working stock concentration (in molarity) if you diluted 250 uL of a stock concentration of 10 uM in a total volume of 1 mL?arrow_forwardWhat mass of sodium glycolate (NaC2H3O3) should be added to 400.0 mL of 1.00 M glycolic acid to produce a buffer solution with a pH of 4.00? Ka = 1.47 x 10-4arrow_forward
- 1) Calculate the required gram of Tris-Hcl to prepare 1M, 100 ml Tris-HCl (Tris Stock) with mol and Molarity formula. 2)Calculate the required gram of EDTA to prepare O.5M, 100 ml EDTA (EDTA stock) mol and Molarity formula. 3.) Calculate the required volume of Tris Stock to prepare buffer A which contains 25 mM Tris-Hcl with final volume is 100 ml by using M1V1 =M2V2 formula 4) Calculate the required volume of EDTA stock to prepare buffer A which contains 10 mM EDTA with final volume is 100 ml by using M1V1 =M2V2 formula 5)Do the same for Buffer B calculationsarrow_forward50X TBE is 87 mM Tris-borate and 4 mM EDTA at pH 8.3. What is the molarity of each of the chemicals in 1X TBE buffer?arrow_forwardA volumetric flask made of Pyrex glass is calibrated at 20 °C.It is filled to the 100 mL mark with 35 °C acetone. After the flask is filled the acetone cools and the flask warms so that the combination of acetone and flask reaches a uniform temperature of 32 °C. The combination is then cooled to 20 °C. a) What is the volume of the acetone when it is at 20 °C? b)At the temperature of 32 °C, does the level of acetone lie above or below the 100 mL mark?arrow_forward
- To make up a solution of phosphate buffered saline (PBS), you need 10 mM Na2HPO4 (anhydrous) (FW: 141.96 g/mol), 3 M NaCl (FW: 58.44 g/mol), and 5mM KH2PO4 (FW: 136.09 g/mol). How many grams of each will you need to make up 850 mL of PBS?arrow_forward200 microliters of a standard solution of 0.200 mg/mL caffeine was mixed with 4.8 mL of 50 mM sodium phosphate buffer, pH 3: methanol (60:40 v/v). What is the concentration of caffeine, in mg/mL, in this solution? Give your answer to two significant figures.arrow_forwardHow could you prepare 500 mL of a 6.0 M NaOH solution using solid NaOH pellets? What is the percent (m/v) concentration of a 6.0 M NaOH solution?arrow_forward