(a)
Interpretation:
The
Concept Introduction:
If a base receives one proton, then the formed species is a conjugate acid whereas an acid lose one proton, then the formed species is a conjugated base.
(b)
Interpretation:
The grams of
Concept Introduction:
Ideal gas Equation:
Any gas can be described by using four terms namely pressure, volume, temperature and the amount of gas. It is referred as ideal gas equation.
Under some conditions gases don not behave like ideal gas that is they deviate from their ideal gas properties. At lower temperature and at high pressures the gas tends to deviate and behave like real gases.
Moles: One mole is equivalent to the mass of the substance consists of same number of units equal to the atoms present in
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Fundamentals of General, Organic, and Biological Chemistry (8th Edition)
- Calculate the normality of a solution that contains 4.5 g of (COOH)2 in 3000 mL of solution? (Assume the (COOH)2 is to be completely neutralized in an acid-base * reaction.) 0.033 N O 0.33 N O 0.166 N O 0.0166 N 0.45 N O 0.045 N 000.0 OOarrow_forward75 mL of 0.300 mol/L sodium phosphate solution is combined with 67.5 mL of 0.350 mol/L calcium bicarbonate. a)Before you begin your reaction, you must accurately produce 1.500 L of your sodium phosphate solution from sodium phosphate trihydrate solid. Write out a procedure to explain all the steps you will take in the lab when making the solution to ensure that your solution concentration is accurate. Please include calculations that show the required mass of solid. Also include the correct names of all equipment used. b)You have a super powerful microscope in your lab! You are able to zoom in on your sodium phosphate solution and take a picture at the molecular level. Label the diagram on the left with the correct choices from the box on the right. You may use arrows or rewrite the symbols in one appropriate place. c)In one sentence, explain what the diagram is showing.arrow_forwardLactic acid 4 g Salicylic acid 5 g Trichloroacetic acid 2 g Flexible collodion qs ad 100 g Sig: wart remover. Use as directed (a) Flexible collodion contains 20% w/w camphor and 30% w/w castor oil. How many grams of each would be contained in 30 g of the mixture? (b) The specific gravity of castor oil is 0.955. H ow many milliliters of the oil is contained in 30 g of the mixture? (c) If the specific gravity of the mixture is 0.781, what are the percent w/v concentrations of lactic acid, salicylic acid, and trichloroacetic acid in the mixture? Answer: (a) 5.34 g camphor and 8.01 g castor oil (b) 8.39 mL castor oil (c) 3.12% w/v lactic acid, 3.91% w/v salicylic acid, and 1.56% w/v trichloroacetic acid Solution of the given answer is needed. Thank you so much and God bless. Happy new yeararrow_forward
- Consider the following acids and their ionization constant, determine which conjugate base is HCOOH Ka = 1.7 x 10-4 (b) HCN Ka = 4.9 x 10-10arrow_forwardThe ionization of p-nitrophenol is shown below (pKa = 7.0): a. Identify the weak acid and conjugate base. b. At pH 7, what are the relative concentrations of ionized and un-ionized p-nitrophenol? c. If enough concentrated hydrochloric acid is added to a solution of p-nitrophenol to lower the pH from 7 to 5, what will happen to the relative concentrations of the ionized and un-ionized forms? d. Ionized p-nitrophenol has a yellow color, while the un-ionized form is colorless. The yellow color can be measured using a spectrophotometer at 400nm. In order to determine the total amount of p-nitrophenol in a solution, would you perform the spectrophotometer reading at an acidic or basic pH? Clearly explain why? e. A solution of p-nitrophenol at pH 7.95 was found to have an A400 of 0.255 . What is the total concentration (in µM) of p-nitrophenol (ionized plus un-ionized) in the solution? The molar extinction coefficient of p-nitrophenol is 18,500 M-1cm-1 and the pKa is 7.arrow_forwardIdentify the acid on the left and its conjugate base on the right in the following equations:(a) HOCl + H2O ↔ H3O+ + OCl-(b) HONH2 + H2O ↔ HONH3+ + OH-(c) NH4+ + H2O ↔ NH3 + H3O+(d) 2HCO3-2 ↔ H2CO3 + CO3-2 (e) PO4-3 + H2PO4- ↔ 2HPO4-2arrow_forward
- Determine the weight/volume of the chemicals needed to prepare the following solutions: a) 100 ml of 0.9% (w/v) saline (NaCl) b) 30 ml of 50% glycerol (v/v) c) Electrophoresis requires TAE, which is a specific mixture of Tris base, acetic acid, and EDTA. TAE is normally made as a 50X concentrated stock. Provide a recipe to make 40 ml of 50X TAE. The recipe for one liter of 50X TAE is as follows: 242g Tris base, 57.1 ml glacial acetic acid, 100 ml 0.5 M EDTAarrow_forwardWhat mass of sodium glycolate (NaC2H3O3) should be added to 400.0 mL of 1.00 M glycolic acid to produce a buffer solution with a pH of 4.00? Ka = 1.47 x 10-4. Please indicate the full solutions.arrow_forwardA 0.578-g saltwater sample was titrated with 1.864 g AgNO3 solution to reach the endpoint of the reaction. Calculate the following by showing all necessary solutions: 1. mol AGNO3 if the AGNO3 solution was prepared by dissolving 5.0 g of AgNO3 in distilled water until 100 ml is reached. (MW AgNO3 = 169.87 g/mol) 2. % Cl in the saltwater sample (MM CI = 35.45 g Cl /mol CI" )arrow_forward
- The density of trifluoroacetic acid vapor was determined at 118.1 °C and 468.5 torr, and found to be 2.784 g/L. Calculate K, for the association of the acid. 0-H...O 2CF,CO,H(g) = CF;C CF,C(g) O----H-Oarrow_forwardQuinine ( C20 H24 N2 O2) is the most important alkaloid derived from cinchona bark. It is used as an antimalarial drug. For quinine, pK, = 5.1 and pK, = 9.7 ( pKp = – log Kp). Only 1 g quinine will dissolve in 1920.0 mL of solution. Calculate the pH of a saturated aqueous solution of quinine. Consider only the reaction | Q+ H2O= QH+ + OH- described by pK, where Q = quinine. pH =arrow_forwardAssuming equal concentrations of conjugate base and acid, which one of the following mixtures is suitable for making a buffer solution with an optimum pH of 7.4–7.6? NaOCl / HOCl (K a = 3.2 × 10 –8) NH 3 / NH 4Cl (K a = 5.6 × 10 –10) NaNO 2 / HNO 2 (K a = 4.5 × 10 –4) NaCl / HCl CH 3COONa / CH 3COOH (K a = 1.8 × 10 –5)arrow_forward