Chapter 10, Problem 49A

Interpretation Introduction

Interpretation:

Mass of silver sample must be calculated which takes 1.25 kJ energy to heat a certain sample of pure silver from 12.0°C to 15.2°C.

Concept Introduction:

Heat (H) required to increase temperature by t°C for a sample with mass m and specific heat is given by

  $\text{H=m×s×t}\text{.}$

Answer to Problem 49A

Mass of the silver sample is 1627.6 g.

Explanation of Solution

Specific heat (s) of silver is 0.24 J/g°C.

Heat $\left(\text{H}\right)\text{=1}\text{.25 kJ=1250 J}\text{.}$

Temperature increase $\text{t=(15}\text{.2-12}\text{.0)°C=3}\text{.2°C}\text{.}$

Putting all values it can be written as

  $\begin{array}{l}\text{1250 J=m×0}\text{.24 J/g°C×3}\text{.2°C}\\ \text{Or,m=}\frac{\text{1250 J}}{\text{0}\text{.24 J/g°C×3}\text{.2°C}}\text{=}\frac{\text{1250 g}}{\text{0}\text{.768}}\text{=1627}\text{.6 g}\text{.}\end{array}$

Conclusion

Mass of the silver sample is 1627.6 g.