World of Chemistry
World of Chemistry
7th Edition
ISBN: 9780618562763
Author: Steven S. Zumdahl
Publisher: Houghton Mifflin College Div
Question
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Chapter 10, Problem 46A
a.
Interpretation Introduction

Interpretation: The value of energy needs to be converted from 462.4 kJ to kilocalories.

Concept Introduction: The conversion factor is a ratio that is widely used to describe the relation between two different units. In order to convert one unit into another, the original unit is multiplied with a proper conversion factor to yield a new unit.

a.
Expert Solution
Check Mark

Answer to Problem 46A

  110.52 kcal .

Explanation of Solution

The conversion factors used are:

  1 kJ = 1000 J1 cal= 4.184 J1 kcal = 1000 cal

So, the conversion of 462.4 kJ to kcal is as follows:

  462.4 kJ×1000 JkJ×cal4.184 J×1 kcal1000 cal=462.4 ×1000 kcal4.184×1000=110.52 kcal

Hence, the value of energy 462.4 kJ in kilocalories is 110.52 kcal .

b.
Interpretation Introduction

Interpretation: The value of energy needs to be converted from 18.28 kJ to kilocalories.

Concept Introduction: The conversion factor is a ratio that is widely used to describe the relation between two different units. In order to convert one unit into another, the original unit is multiplied with a proper conversion factor to yield a new unit.

b.
Expert Solution
Check Mark

Answer to Problem 46A

  4.37 kcal .

Explanation of Solution

The conversion factors used are:

  1 kJ = 1000 J1 cal= 4.184 J1 kcal = 1000 cal

So, the conversion of 18.28 kJ to kcal is as follows:

  18.28 kJ×1000 JkJ×cal4.184 J×1 kcal1000 cal=18.28×1000 kcal4.184×1000=4.37 kcal

Hence, the value of energy 18.28 kJ in kilocalories is 4.37 kcal .

c.
Interpretation Introduction

Interpretation: The value of energy needs to be converted from 1.014 kJ to kilocalories.

Concept Introduction: The conversion factor is a ratio that is widely used to describe the relation between two different units. In order to convert one unit into another, the original unit is multiplied with a proper conversion factor to yield a new unit.

c.
Expert Solution
Check Mark

Answer to Problem 46A

  0.242 kcal .

Explanation of Solution

The conversion factors used are:

  1 kJ = 1000 J1 cal= 4.184 J1 kcal = 1000 cal

So, the conversion of 1.014 kJ to kcal is as follows:

  1.014 kJ×1000 JkJ×cal4.184 J×1 kcal1000 cal=1.014×1000 kcal4.184×1000=0.242 kcal

Hence, the value of energy 1.014 kJ in kilocalories is 0.242 kcal .

d.
Interpretation Introduction

Interpretation: The value of energy needs to be converted from 190.5 kJ to kilocalories.

Concept Introduction: The conversion factor is a ratio that is widely used to describe the relation between two different units. In order to convert one unit into another, the original unit is multiplied with a proper conversion factor to yield a new unit.

d.
Expert Solution
Check Mark

Answer to Problem 46A

  45.53 kcal .

Explanation of Solution

The conversion factors used are:

  1 kJ = 1000 J1 cal= 4.184 J1 kcal = 1000 cal

So, the conversion of 190.5 kJ to kcal is as follows:

  190.5 kJ×1000 JkJ×cal4.184 J×1 kcal1000 cal=190.5×1000 kcal4.184×1000=45.53 kcal

Hence, the value of energy 190.5 kJ in kilocalories is 45.53 kcal .

Chapter 10 Solutions

World of Chemistry

Ch. 10.2 - Prob. 4RQCh. 10.2 - Prob. 5RQCh. 10.2 - Prob. 6RQCh. 10.3 - Prob. 1RQCh. 10.3 - Prob. 2RQCh. 10.3 - Prob. 3RQCh. 10.3 - Prob. 4RQCh. 10.3 - Prob. 5RQCh. 10.4 - Prob. 1RQCh. 10.4 - Prob. 2RQCh. 10.4 - Prob. 3RQCh. 10.4 - Prob. 4RQCh. 10.4 - Prob. 5RQCh. 10.4 - Prob. 6RQCh. 10.4 - Prob. 7RQCh. 10 - Prob. 1ACh. 10 - Prob. 2ACh. 10 - Prob. 3ACh. 10 - Prob. 4ACh. 10 - Prob. 5ACh. 10 - Prob. 6ACh. 10 - Prob. 7ACh. 10 - Prob. 8ACh. 10 - Prob. 9ACh. 10 - Prob. 10ACh. 10 - Prob. 11ACh. 10 - Prob. 12ACh. 10 - Prob. 13ACh. 10 - Prob. 14ACh. 10 - Prob. 15ACh. 10 - Prob. 16ACh. 10 - Prob. 17ACh. 10 - Prob. 18ACh. 10 - Prob. 19ACh. 10 - Prob. 20ACh. 10 - Prob. 21ACh. 10 - Prob. 22ACh. 10 - Prob. 23ACh. 10 - Prob. 24ACh. 10 - Prob. 25ACh. 10 - Prob. 26ACh. 10 - Prob. 27ACh. 10 - Prob. 28ACh. 10 - Prob. 29ACh. 10 - Prob. 30ACh. 10 - Prob. 31ACh. 10 - Prob. 32ACh. 10 - Prob. 33ACh. 10 - Prob. 34ACh. 10 - Prob. 35ACh. 10 - Prob. 36ACh. 10 - Prob. 37ACh. 10 - Prob. 38ACh. 10 - Prob. 39ACh. 10 - Prob. 40ACh. 10 - Prob. 41ACh. 10 - Prob. 42ACh. 10 - Prob. 43ACh. 10 - Prob. 44ACh. 10 - Prob. 45ACh. 10 - Prob. 46ACh. 10 - Prob. 47ACh. 10 - Prob. 48ACh. 10 - Prob. 49ACh. 10 - Prob. 50ACh. 10 - Prob. 51ACh. 10 - Prob. 52ACh. 10 - Prob. 53ACh. 10 - Prob. 54ACh. 10 - Prob. 55ACh. 10 - Prob. 56ACh. 10 - Prob. 57ACh. 10 - Prob. 58ACh. 10 - Prob. 59ACh. 10 - Prob. 60ACh. 10 - Prob. 61ACh. 10 - Prob. 62ACh. 10 - Prob. 63ACh. 10 - Prob. 64ACh. 10 - Prob. 65ACh. 10 - Prob. 1STPCh. 10 - Prob. 2STPCh. 10 - Prob. 3STPCh. 10 - Prob. 4STPCh. 10 - Prob. 5STPCh. 10 - Prob. 6STPCh. 10 - Prob. 7STPCh. 10 - Prob. 8STPCh. 10 - Prob. 9STPCh. 10 - Prob. 10STPCh. 10 - Prob. 11STP
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