Concepts of Genetics (12th Edition)
12th Edition
ISBN: 9780134604718
Author: William S. Klug, Michael R. Cummings, Charlotte A. Spencer, Michael A. Palladino, Darrell Killian
Publisher: PEARSON
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Chapter 10, Problem 29PDQ
In some organisms, cytosine is methylated at carbon 5 of the pyrimidine ring after it is incorporated into DNA. If a 5-methyl cytosine molecule is then hydrolyzed, as described in Problem 28, what base will be generated?
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Chapter 10 Solutions
Concepts of Genetics (12th Edition)
Ch. 10 - Would an experiment similar to that performed by...Ch. 10 - In sea urchin DNA, which is double stranded, 17.5...Ch. 10 - German measles results from an infection of the...Ch. 10 - What vital clues were provided by Franklins work...Ch. 10 - Was it ethical for Wilkins to show Franklins...Ch. 10 - Prob. 3CSCh. 10 - HOW DO WE KNOW? In this chapter, we first focused...Ch. 10 - CONCEPT QUESTION Review the Chapter Concepts list...Ch. 10 - Discuss the reasons proteins were generally...Ch. 10 - Contrast the contributions made to an...
Ch. 10 - When Avery and his colleagues had obtained what...Ch. 10 - Why were 32P and 35S chosen for use in the...Ch. 10 - Does the design of the HersheyChase experiment...Ch. 10 - What observations are consistent with the...Ch. 10 - What are the exceptions to the general rule that...Ch. 10 - Draw the chemical structure of the three...Ch. 10 - How are the carbon and nitrogen atoms of the...Ch. 10 - Adenine may also be named 6-amino purine. How...Ch. 10 - Draw the chemical structure of a dinucleotide...Ch. 10 - Describe the various characteristics of the...Ch. 10 - What evidence did Watson and Crick have at their...Ch. 10 - What might Watson and Crick have concluded had...Ch. 10 - How do covalent bonds differ from hydrogen bonds?...Ch. 10 - List three main differences between DNA and RNA.Ch. 10 - What are the three major types of RNA molecules?...Ch. 10 - How is the absorption of ultraviolet light by DNA...Ch. 10 - What is the physical state of DNA after it is...Ch. 10 - What is the hyperchromic effect? How is it...Ch. 10 - Why is Tm related to base composition?Ch. 10 - What is the chemical basis of molecular...Ch. 10 - What did the WatsonCrick model suggest about the...Ch. 10 - A genetics student was asked to draw the chemical...Ch. 10 - Considering the information in this chapter on B-...Ch. 10 - One of the most common spontaneous lesions that...Ch. 10 - In some organisms, cytosine is methylated at...Ch. 10 - Because of its rapid turnaround time, fluorescent...Ch. 10 - Prob. 31ESPCh. 10 - Newsdate: March 1, 2030. A unique creature has...Ch. 10 - During gel electrophoresis, DNA molecules can...Ch. 10 - DNA and RNA are chemically very similar but are...Ch. 10 - Electrophoresis is an extremely useful procedure...
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- In human DNA, 70% of cytosine residues that are followed by guanine (so-called CpG dinucleotides, where p indicates the phosphate in the phosphodiester bond between these two nucleotides) are methylated to form 5-methylcytosine. As shown in the following figure, if 5-methylcytosine should undergo spontaneous deamination, it becomes thymine. NH, Deamination NH 5-methylcytosine Thymine Methylated CpG dinucleotides are hotspots for point mutations in human DNA. Can you propose a hypothesis that explains why?arrow_forwardWhat is the significance of the pentose monophosphate shunt to synthesis of nucleotides? What is a difference between synthesis of purine and pyrimidine nucleotides?arrow_forwardAnalogs of nucleotides are often used in studies of DNA. An analog is a modification of one of the normal bases that can be incorporated into DNA via replication and can later be detected for analysis. The thymidine analog 5-ethynyl-2′-deoxyuridine (EdU) is widely used in the laboratory for these types of experiments. However, EdU is toxic to cells, and inclusion of EdU in growth medium eventually causes cell death, unlike other thymidine analogs. Recently, a research team examined if cells recognized EdU as damage to the DNA and if the cells used the nucleotide excision repair (NER) systems to fix the DNA (see figure A). Human cells cultured in the lab were treated for 24 hours with either EdU or another thymidine analog, BrdU (blue circles in the figure). The cells were then exposed to UV light where damage would occur (red triangles in the figure). After 1 h of repair in the presence of the analog, the cells were lysed and excision products were separated from cells. An…arrow_forward
- Given the structures of the nitrogenous bases shown in the picture, draw the structure of a part of DNA with the sequence: 5'-GTTCA-3'.arrow_forwardEnediynes are natural products with potent antitumor properties because they are able to cleave DNA (page 288). Their cytotoxic properties are due tothe enediyne undergoing a cyclization to form a highly reactive diradical intermediate. The intermediate abstracts hydrogen atoms from the backbone of DNA, which triggers its damage. Draw the structure of the diradical intermediate.arrow_forwardIn E. coli, all newly synthesized DNA appears to be fragmented (an observation that could be interpreted to mean that the leading strand as well as the lagging strand is synthesized discontinuously). However, in E. coli mutants that are defective in uracil–DNA glycosylase, only about half the newly synthesized DNA is fragmented. Explain.arrow_forward
- Ribonuclease A cannot catalyze the hydrolysis of DNA. which of the following statements explains it. a. Ribonuclease requires two active site histidines to be active but the nucleobase of DNA will form hydrogen bonds with these histidines and block their acid-base catalysis. b. DNAs have thymidine that is more stable than the uracil in RNAs c. DNAs are double-stranded and the nucleobases are protected while RNAs are single stranded d. DNAs does not have hydroxyl group at 2' position of the sugar ring to support the catalysisarrow_forwardIn the Watson-Crick model for the DNA double helix (B form) the A-T and G-C base pairs share all but one of the following properties. Which is the exception? None of the proton-binding groups in the purine and pyrimidine bases is in its charged or ionized form. The plane of the base pair is roughly perpendicular to the axis of the helix in each case. The number of hydrogen bonds formed between the two bases of the base pair is the same. O The distance between the two glycosidic (base-sugar) bonds is the same in both base pairs, within a few tenths of an angstrom.arrow_forwardAn exonuclease is an enzyme that sequentially cleaves nucleotides from the end of a polynucleotide strand. Snake venom phosphodiesterase, which hydrolyzes nucleotides from the 3′ end of any oligonucleotidewith a free 3′-hydroxyl group, cleaves between the 3′ hydroxyl of the ribose or deoxyribose and the phosphoryl group of the next nucleotide. It acts on single-stranded DNA or RNA and has no base specificity. This enzyme was used in sequence determination experiments before the development of modern nucleic acid sequencing techniques. What are theproducts of partial digestion by snake venom phosphodiesterase of an oligonucleotide with the sequence (5′)GCGCCAUUGC(3′)—OH?arrow_forward
- Explain why RNase A cannot catalyze the hydrolysis of DNA.arrow_forwardIn human DNA, 70% of cytosine residues that are followed by guanine (so-called CpG dinucleotides, where p indicates the phosphate in the phosphodiester bond between these two nucleotides) are methylated to form 5-methylcytosine. As shown in the following figure, if 5-methylcytosine should undergo spontaneous deamination, it becomes thymine. 2. NH, Deamination 5-methylcytosine Thymine Methylated CpG dinucleotides are hotspots for point mutations in human DNA. Can you propose a hypothesis that explains why?arrow_forwardWhat is the methyl group-containing nucleobase composition of a double- stranded eukaryotic DNA with 52,000 bases that contains 22% bicyclic nucleobases characterized to have both an amino group and a keto group? (Instructions: Do NOT put spaces or commas or additional words/letters/units; Type in your answer in NUMERICAL FORM with the following format: 1234567)arrow_forward
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