Concept explainers
Interpretation:
Empirical formula of monosodium glutamate needs to be found for which % of C, H, O, N and Na are is 35.5, 4.77, 39.9, 8.29 and 13.6 respectively.
Concept introduction:
Empirical formula of a molecule is the smallest unit which is repeated in the molecule.
Answer to Problem 172A
The empirical formula is C5H8O4NNa.
Explanation of Solution
% of C, H, O, N and Na are 35.5, 4.77, 39.9, 8.29 and 13.6 respectively. Assuming 100 g of the compound, mass of C, H, O, N and Na is 35.5 g, 4.77 g, 39.9 g, 8.29 g and 13.6 g respectively.
The molar mass of C, H, O, N and Na is 12 g/mol, 1 g/mol, 16 g/mol, 14 g/mol and 23 g/mol respectively.
The number of moles of each element can be calculated as follows:
Moles of C
Moles of H
Moles of O
Moles of N
Moles of Na
Now,
Smallest mole ratio C: H: O: N: Na
Thus, empirical formula is C5H8O4NNa.
Empirical formula of monosodium glutamate is C5H8O4NNa.
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