Interpretation Introduction (a) Interpretation: 4.22 × 10 15 atoms of U should be converted into mass of U in grams. Concept introduction: The number of moles of a compound is defined as the ratio of the given mass of the compound to the molar or molecular mass of the compound. The mathematical expression is given by: Number of moles = given mass of the compound molar mass of the compound The one mole of any substance is equal to the Avogadro number, , i.e., , 6.022 × 10 23 atoms. Answer Mass of U in grams = 166.80 × 10 − 8 g Explanation Since, one mole of any substance is equal to the Avogadro number, i.e., 6.022 × 10 23 atoms. Number of moles = number of atoms × 1 mole 6.022 × 10 23 atoms Put the values, Number of moles = 4.22 × 10 15 atoms × 1 mole 6.022 × 10 23 atoms = 0.70076 × 10 − 8 mole Number of moles = mass of the compound molar mass of the compound Molar mass of U = 238.029 g/mole Put the values, 0 .70076 × 10 − 8 mole = mass 238 .029 g/mole Mass = 0 .70076 × 10 − 8 mole × 238 .029 g/mole Mass of U in grams = 166.80 × 10 − 8 g Interpretation Introduction (b) Interpretation: 8.65 × 10 25 atoms of H should be converted into mass of U in grams. Concept introduction: The number of moles of a compound is defined as the ratio of the given mass of the compound to the molar or molecular mass of the compound. The mathematical expression is given by: Number of moles = given mass of the compound molar mass of the compound The one mole of any substance is equal to the Avogadro number, i.e., 6.022 × 10 23 atoms. Answer Mass of H in grams = 144.76 g Explanation Since, one mole of any substance is equal to the Avogadro number, i.e., 6.022 × 10 23 atoms. Number of moles = number of atoms × 1 mole 6.022 × 10 23 atoms Put the values, Number of moles = 8.65 × 10 25 atoms × 1 mole 6.022 × 10 23 atoms = 1.43639 × 10 2 mole Number of moles = mass of the compound molar mass of the compound Molar mass of H = 1.0078 g/mole Put the values, 1.43639 × 10 2 mole= mass 1 .0078 g/mole Mass = 1.43639 × 10 2 mole × 1 .0078 g/mole Mass of H in grams = 144.76 g Interpretation Introduction (c) Interpretation: 1.25 × 10 22 atoms of O should be converted into mass of U in grams. Concept introduction: Number of moles of a compound is defined as the ratio of given mass of the compound to the molar or molecular mass of the compound. The mathematical expression is given by: Number of moles = given mass of the compound molar mass of the compound The one mole of any substance is equal to the Avogadro number, i.e., 6.022 × 10 23 atoms. Answer Mass of O in grams = 0.332 g Explanation Since, one mole of any substance is equal to the Avogadro number, i.e., 6.022 × 10 23 atoms. Number of moles = number of atoms× 1 mole 6.022 × 10 23 atoms Put the values, Number of moles = 1.25 × 10 22 atoms × 1 mole 6.022 × 10 23 atoms = 0.2076 × 10 − 1 mole Number of moles = mass of the compound molar mass of the compound Molar mass of O = 15.999 g/mole Put the values, 0.2076 × 10 − 1 mole = mass 15 .999 g/mole Mass = 1.43639 × 10 2 mole × 1 .0078 g/mole Mass of O in grams = 0.332 g Interpretation Introduction (d) Interpretation: 4.44 × 10 23 atoms of Pb should be converted into mass of U in grams. Concept introduction: Number of moles of a compound is defined as the ratio of given mass of the compound to the molar or molecular mass of the compound. The mathematical expression is given by: Number of moles = given mass of the compound molar mass of the compound The one mole of any substance is equal to the Avogadro number, i.e., 6.022 × 10 23 atoms. Answer Mass of Pb in grams = 152.8 g Explanation Since, one mole of any substance is equal to the Avogadro number, i.e., 6.022 × 10 23 atoms. Number of moles = number of atoms × 1 mole 6.022 × 10 23 atoms Put the values, Number of moles = 4.44 × 10 23 atoms × 1 mole 6.022 × 10 23 atoms = 0.7373 mole Number of moles = mass of the compound molar mass of the compound Molar mass of Pb in = 207.2 g/mole Put the values, 0.7373 mole = mass 207 .2 g/mole Mass = 0.7373 mole × 207 .2 g/mole Mass of Pb in grams = 152.8 g

1st Edition

ISBN: 9780078746376

Author: Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom

Publisher: Glencoe/McGraw-Hill School Pub Co

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Textbook Question

Chapter 10, Problem 112A

Convert each to mass in grams.

a. $4.22 × 10 15$ atoms c

b. $8 .65 × 10 25$ atoms H

c. $1 .25 × 10 22$ atoms O

d. $4 .44 × 10 23$ atoms Pb

Expert Solution

Interpretation Introduction

(a)

Interpretation:

$4.22×1015 atoms$ of U should be converted into mass of U in grams.

Concept introduction:

The number of moles of a compound is defined as the ratio of the given mass of the compound to the molar or molecular mass of the compound.

The mathematical expression is given by:

Number of moles = $given mass of the compoundmolar mass of the compound$

The one mole of any substance is equal to the Avogadro number, , i.e., , $6.022×1023$ atoms.

Answer to Problem 112A

Mass of U in grams = $166.80×10−8 g$

Explanation of Solution

Since, one mole of any substance is equal to the Avogadro number, i.e., $6.022×1023$ atoms.

Number of moles = $number of atoms ×1 mole6.022×10 23atoms$

Put the values,

Number of moles = $4.22×1015 atoms ×1 mole6.022×10 23atoms$

$=0.70076×10−8 mole$

Number of moles = $mass of the compoundmolar mass of the compound$

Molar mass of U = 238.029 g/mole

Put the values,

$0.70076×10−8 mole = mass238.029 g/mole$

$Mass = 0.70076×10−8 mole ×238.029 g/mole$

Mass of U in grams = $166.80×10−8 g$

Expert Solution

Interpretation Introduction

(b)

Interpretation:

$8.65×1025 atoms$ of H should be converted into mass of U in grams.

Concept introduction:

The number of moles of a compound is defined as the ratio of the given mass of the compound to the molar or molecular mass of the compound.

The mathematical expression is given by:

Number of moles = $given mass of the compoundmolar mass of the compound$

The one mole of any substance is equal to the Avogadro number, i.e., $6.022×1023$ atoms.

Answer to Problem 112A

Mass of H in grams = $144.76 g$

Explanation of Solution

Since, one mole of any substance is equal to the Avogadro number, i.e., $6.022×1023$ atoms.

Number of moles = $number of atoms ×1 mole6.022×10 23atoms$

Put the values,

Number of moles = $8.65×1025 atoms ×1 mole6.022×10 23atoms$

$=1.43639×102 mole$

Number of moles = $mass of the compoundmolar mass of the compound$

Molar mass of H = 1.0078 g/mole

Put the values,

$1.43639×102 mole= mass1.0078 g/mole$

$Mass = 1.43639×102 mole×1.0078 g/mole$

Mass of H in grams = $144.76 g$

Expert Solution

Interpretation Introduction

(c)

Interpretation:

$1.25×1022 atoms$ of O should be converted into mass of U in grams.

Concept introduction:

Number of moles of a compound is defined as the ratio of given mass of the compound to the molar or molecular mass of the compound.

The mathematical expression is given by:

Number of moles = $given mass of the compoundmolar mass of the compound$

The one mole of any substance is equal to the Avogadro number, i.e., $6.022×1023$ atoms.

Answer to Problem 112A

Mass of O in grams = $0.332 g$

Explanation of Solution

Since, one mole of any substance is equal to the Avogadro number, i.e., $6.022×1023$ atoms.

Number of moles = $number of atoms×1 mole6.022×10 23atoms$

Put the values,

Number of moles = $1.25×1022 atoms ×1 mole6.022×10 23atoms$

$=0.2076×10−1 mole$

Number of moles = $mass of the compoundmolar mass of the compound$

Molar mass of O = 15.999 g/mole

Put the values,

$0.2076×10−1 mole = mass15.999 g/mole$

$Mass = 1.43639×102 mole×1.0078 g/mole$

Mass of O in grams = $0.332 g$

Expert Solution

Interpretation Introduction

(d)

Interpretation:

$4.44×1023 atoms$ of $Pb$ should be converted into mass of U in grams.

Concept introduction:

Number of moles of a compound is defined as the ratio of given mass of the compound to the molar or molecular mass of the compound.

The mathematical expression is given by:

Number of moles = $given mass of the compoundmolar mass of the compound$

The one mole of any substance is equal to the Avogadro number, i.e., $6.022×1023$ atoms.

Answer to Problem 112A

Mass of $Pb$ in grams = $152.8 g$

Explanation of Solution

Since, one mole of any substance is equal to the Avogadro number, i.e., $6.022×1023$ atoms.

Number of moles = $number of atoms ×1 mole6.022×10 23atoms$

Put the values,

Number of moles = $4.44×1023 atoms ×1 mole6.022×10 23atoms$

$=0.7373 mole$

Number of moles = $mass of the compoundmolar mass of the compound$

Molar mass of $Pb$ in = 207.2 g/mole

Put the values,

$0.7373 mole = mass207.2 g/mole$

$Mass = 0.7373 mole×207.2 g/mole$

Mass of $Pb$ in grams = $152.8 g$

Chapter 10, Problem 111A

Chapter 10, Problem 113A

Chapter 10 Solutions

Chemistry: Matter and Change

Ch. 10.1 - Prob. 1PP Ch. 10.1 - Prob. 2PP Ch. 10.1 - Prob. 3PP Ch. 10.1 - Prob. 4PP Ch. 10.1 - Prob. 5PP Ch. 10.1 - Prob. 6PP Ch. 10.1 - Prob. 7SSC Ch. 10.1 - Prob. 8SSC Ch. 10.1 - Prob. 9SSC Ch. 10.1 - Prob. 10SSC

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