Which of the reactions are spontaneous (favorable)? C6H130,P + ATP → › C6H14º₁₂P2 + ADP AG = -14.2 kJ/mol L-malate + NAD+ → oxaloacetate + NADH + H+ AG = 29.7 kJ/mol glutamate + NAD+ + H₂O → NH‡ + α-ketoglutarate + NADH + H+ AG = 3.7 kcal/mol → CH2O4 + H2O AG = 3.1 kJ/mol * CąHẠO, — CH,O4 + H,O DHAP C₂H + H₂ glyceraldehyde-3-phosphate AG = 3.8 kJ/mol Rh(I) C2H6 AG-150.97 kJ/mol

Under standard conditions, will the following reactions proceed spontaneously as written? (1) Fumarate + NADH + H+ (2) succinate + NAD+ Cyto a (Fe²+) + cyto b (Fe³+) = cyto a (Fe³+) + cyto 6 (Fe²+) b

Consider the fructose-1,6-bisphosphatase reaction. Calculate the free energy change if the ratio of the concentrations of the products to the concentrations of the reactants is 23.7, and the temperature is 37.0 °C? AG" for the reaction is -16.7 kJ/mol. The constant R = 8.3145 J/(mol-K) AG= Number kJ/mol

Below is an image of the Krebs cycle: acetyl-CoA oxaloacetate COASH H20 NADH NAD* H20 malate citrate fumarate isocitrate FADH2 NAD* CO2 FAD АТР NADH + ADP succinate GTP NAD+ a-ketoglutarate H20 GDP NADH + CO2 COASH succinyl CoA COASH Consider the conversion of succinate to fumarate, which is coupled with the production the electron carrier FADH2. If this reaction was NOT coupled with the production of FADH2 (and only catalyzed the conversion of succinate to fumarate), how would this impact ATP production through cell respiration? OATP production would stop because no high energy electron carriers would be produced ATP production would still occur, but there would be a much lower ATP yield because a large number of electron carriers are no longer being made ATP production would stop because without FADH2 we will no longer have electrons moving through the electron transport chain ATP production would still occur, but there would be a slightly lower ATP yield because a small number of…