TSA plates of microorganisms grown at 30°C or 37°C In words, describe the differences you see for each organism (E. coli M.,luteus ,S. marcescens and S. saprophyticus) grown at 30°C or 37°C (ie, amount of growth, color, etc
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TSA plates of microorganisms grown at 30°C or 37°C In words, describe the differences you see for each organism (E. coli M.,luteus ,S. marcescens and S. saprophyticus) grown at 30°C or 37°C (ie, amount of growth, color, etc
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- Sulfur Indole Motility (SIM) Medium H2S produced, color and +/-: ______________________________ Indole present/Tryptophan hydrolysis, color and +/-: ___________________________ Motile or non-motile: _____________________________You are cultivating Escherichia coli in a chemostat culture. The maximum specific growth rate (µmax) of E. coli that you can reach is known as 1.0 h-1 at your culture conditions. Describe what you would observe for each condition if you have the following settings: F (flow rate of the fresh medium into the bioreactor vessel) (L/h) V (Volume of the liquid culture in the bioreactor vessel) (L) a) 1 1 b) 5 4 c) 1 2A culture of S. cerevisea has an overnight OD of 4.5 (1.0 OD is approx 1.0x107 cells/ml) You will be plating 100µl onto agar and want the final count of colonies on the plate to be around 300 colonies. How much of the 4.5 OD culture must you use to get a 500µl subdilution (with sterile water), so that you have diluted enough to get approx 300 colonies per 100ul
- The production of a product P from a particular gram-negative bacteria follows the Monod growth law max Cs Co Ks + C, rg = with max (a) The reaction is to be carried out in a batch reactor with the initial cell concentration of Cco = 0.1 g/dm³ and substrate concentration of Cso = 20 g/dm³. = 1 h-¹, Ks = 0.25 g/dm³, and Y₁ = 0.5 g/g. c/s = p/c Cc Cco + Yc/s(Cs0 - Cs) = Plot rg, -rs-re, Cs, and Co as a function of time. The reaction is now to be car (b) dilution rate at which wash-out out in a CSTR with Cso = 20 g/dm³ and Cco = 0. What is the occurs? (c) For the conditions in part (b), what is the dilution rate that will give the maximum product rate 0.15 g/g? What are the concentrations Cc, C₁, Cp, and ―r, at this value of D? (g/h) if YEscherichia coli Mycobacterium phlei Bacillus Micrococcus subtilis luteus A B Figure 1: Agar Slant Cultures of Bacteria (Gary E. Kaiser, Ph.D.- Professor of Microbiology) . Observe and describe the colour of the slant cultures (A-D) in fig 1. ( . Define the following terms: pure culture, sterile medium, inoculum, aseptic technique, and colony. What is the name of the cultures that you used . Where they gram negative or positive Define the following terms: psychrophile, mesophile, thermophile, and hyperthermophile.In the context of flow cytometry data: It is clear that Lactobacillus cells can be detected based on their FSC (forward scatter) and SSC (side scatter) signal since it is above the noise. Thus, they could be quantified using these parameters without staining. Give two reasons as to why anyone would bother SYBRGreen (SG) staining samples that contain heterotrophs?
- TRUE OF FALSE: Is E coli colonies would be pink mucoid in Eosin Methylene BlueAgar (EMBA)? Is Coliform colonies would be pink mucoid in Eosin Methylene BlueAgar (EMBA)?Antibiotic Code Zone of Inhibition (mm) S, I, or R? Penicillin P 15 Streptomycin S 8 Ampicillin A 25 Chloramphenicol C 14 Bacitracin B 5 QUESTIONS: Which antimicrobial agent was most effective against your organism? Can you determine from your results whether this antimicrobial agent will also be most effective against another bacterium? Why or why not? Is this technique measuring bacteriostatic effect, bactericidal effects, or both? Explain. 4) Consider the following list of hypothetical antibiotics, tested against Escherichia coli in a Kirby-Bauer test: Antibiotic Zone of Inhibition (mm) Astonostatin 12 Bodaciosporin 25 Crazifloxacin 5 Dorkimycin 16 When the above antibiotics were tested as treatments for E. coli infections in humans, it was found that Dorkimycin has virtually no effect on the infection, while Astonostatin is the most effective of the four antibiotics listed. Propose an explanation for this result. Based purely on these…Hao. - Hao + O. BLOOD AGAR Hemalysis ACID-FAST STAINING Cell Wall (Mycolle Acid) Data Table P. S. aureus | E. coli B. subtilis mirabilis aerogenes Gram Bacillus Bacillus Gram+ Gram Gram Gram* MORPHOLOGY Сосcus Bacillus Bacillus LACTOSE Variable B- B- BLOOD AGAR Variable Swarming Variable Hemolysis Hemolysis CATALASE + OXIDASE + INDOLE + Using the workflow images and data table, match the results of each test used to identify the bacteria S. aureus is causing the disease. S. aureus is lactose Gamma-hemol O positive On blood agar S. [ Choose ] aureus showed In the oxidase test S. [ Choose ] aureus In the indole test S. [ Choose ] aureus The gram status of S. [ Choose] aureus In the acid-fast test S. [ Choose ] aureus
- Examine the given table below. What conclusions can be drawn from the data regarding the effects of varying pH in bacterial activity? Explain and Justify your points. Table 1. Effect of different pH on Antibacterial Growth Diameter of Inhibition zone (mm) of different pH 7 6 8 9 21 15 12 34 21 15 41 33 21 22 20 0 Test organisms Escheichia coli S. typhi Bacillus subtilis 5.8 33 30 44 42 54 50 30 Staphylococcus 33 aureus1. To test the ability of each diluent to sustain the viability of Escherichia coli during dilution, the cells were incubated at room temperature (20 to 23°C) or 37°C for 0 or 2 h and plated on NA agarin duplicate. The counts obtained are shown in the following table: E. coli counts on dilution time O hour 2 hours Diluents 10-5 10-6 10-7 10-5 10-6 10-7 R1 26 ; 27 3:2 0:0 0:0 0:0 0:0 Distilled Water R2 31 ; 27 1:0 0:0 0:0 0:0 0:0 (DW) R3 27 : 28 4:5 0:0 0:0 0:0 0:0 R1 290 : 295 34 :31 2:1 252 : 239 27 : 26 1;1 DW-0.85% NacI R2 315 ; 309 37 : 34 2;2 250 : 245 26 ; 26 1:0 R3 301 ; 285 36 : 44 1:2 235 ; 267 34 : 21 0:0 R1 385 ; 392 42 : 35 4:5 368 :379 33 ; 32 2:2 DW-3.0% Nacı R2 370 : 388 37 : 40 2:4 305 : 303 35 ; 30 2:5 R3 355 : 365 35 : 28 4:6 370 :350 33: 37 3:1 R1 380 ; 383 30 : 27 2:2 255 : 245 25 : 24 2;2 PBS R2 341 ; 352 27 : 34 1:3 230 : 245 26 : 27 2:2 R3 329 ; 335 33 : 31 3:6 242 : 250 28 : 29 2:1 R1 340 ; 320 32 : 35 1:0 245 : 249 27 : 25 1 1 PBS-0.85% Naci R2 340 ; 345 35 :…In growing E.coli, why is that (reasons) they do not grow after doubling time under 20 degrees celsius and under 37 degrees celsius, the number of colonies after doubling time has decreased? provide reliable sources (links).