monkeys, black coat color (B) is dominant over brown color (b). A population of monkeys was found to be composed of 67 brown coated individuals and 119 black coated individuals. What is the frequency of the b allele in this population? What is the frequency of the B allele in this population? Based upon the Hardy‑Weinberg formula, what proportion of the population is expected to have the genotype BB? Based upon the Hardy‑Weinberg formula, what proportion of the population is expected to bave black coat color? Based upon the Hardy‑Weinberg f

monkeys, black coat color (B) is dominant over brown color (b). A population of monkeys was found to be composed of 67 brown coated individuals and 119 black coated individuals. What is the frequency of the b allele in this population? What is the frequency of the B allele in this population? Based upon the Hardy‑Weinberg formula, what proportion of the population is expected to have the genotype BB? Based upon the Hardy‑Weinberg formula, what proportion of the population is expected to bave black coat color? Based upon the Hardy‑Weinberg f

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Description: In monkeys, black coat color (B) is dominant over brown color (b). A population of monkeys was found to be composed of 67 brown coated individuals and 119 black coated individuals.What is the frequency of the b allele in this population? What is the

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter19: Population Genetics And Human Evolution

Section: Chapter Questions

Problem 9QP: Using the HardyWeinberg Law in Human Genetics Suppose you are monitoring the allelic and genotypic...

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Using the HardyWeinberg Law in Human Genetics Suppose you are monitoring the allelic and genotypic frequencies of the MN blood group locus (see Question 2 for a description of the MN blood group) in a small human population. You find that for 1-year-old children, the genotypic frequencies are MM = 0.25, MN = 0.5, and NN = 0.25, whereas the genotypic frequencies for adults are MM = 0.3, MN = 0.4, and NN = 0.3. a. Compute the M and N allele frequencies for 1-year-olds and adults. b. Are the allele frequencies in equilibrium in this population? c. Are the genotypic frequencies in equilibrium?
Assume that the frequency of gene B in a hypothetical population Is 0.63, that there are only two alleles (B and b) of the gee in the population, that allele B is dominant over allele b, that neither allele has a selective advantage over the other, and that the population is at equilibrium with regard to this particular gene. And how many individuals in this population are expected to be of genotype BB according to the Hardy-Weinberg formula? (Assume that the total population size is 150) 71 52 118 60 131
In monkeys, black coat color (B) is dominant over brown color (b). A population of monkeys was found to be composed of 67 brown coated individuals and 119 black coated individuals. Based upon the Hardy‑Weinberg formula, what proportion of the population is expected to have the genotype BB? Based upon the Hardy‑Weinberg formula, what proportion of the population is expected to bave black coat color?
Pretend that you are comparing the actual genotype distribution for a population with the distribution of genotypes predicted by the Hardy-Weinberg theorem. So your hypothesis is that the population is in Hardy-Weinberg equilibrium (i.e. that actual population data fit the Hardy-Weinberg expectations). If you carry out a chisquare goodness of fit test and calculate a total chisquare value of 0.03 with 1 degree of freedom (see table), what does this mean? (select all true statements)a) The data do NOT fit the hypothesized distribution.b) The data do fit the hypothesized distribution well enough, so we accept the hypothesis at this time (i.e. we cannot reject the hypothesis). c) The probability that the data came from a population in Hardy-Weinberg equilibrium is too small, so we reject the hypothesis.d) The probability that the data came from a population in Hardy-Weinberg equilibrium is too big, so we reject the hypothesis.e) The data support Hardy-Weinberg expectations – there is no…
Pretend that you are comparing the actual genotype distribution for a population with the distribution of genotypes predicted by the Hardy-Weinberg theorem. So you hypothesize that the population is in Hardy-Weinberg equilibrium (i.e. that actual population data fit the Hardy-Weinberg expectations). If you carry out chi-square goodness of fit test and calculate a total chi-square value of 0.03 with 1 degree of freedom (see table), what does this mean?
In a population of 200 people, an allele F has a frequency of 84%. What is the frequency of allele f? Using the Hardy-Weinberg equation, estimate the numbers of homozygous dominant, heterozygous, and homozygous recessive genotypes. (Remember that the formula is: p2 + 2pq + q2 = 1, where p represents the dominant allele and q represents the recessive allele.) *Be sure to account for all 200 people in the population.
If a population is in Hardy-Weinberg equilibrium for the multiple alleles A+, A and a, whose frequencies are p= 0.60 for A+, q= 0.20 for A, and r = 0.20 for a, what percentage of the population is expected to be heterozygous?
In a certain population of frogs, 120 are green, 60 are brownish-green, and 20 are brown. The allele for brown is denoted GB, and the allele for green is designated GG. These two alleles are incompletely dominant to each other. What is the frequency of genotype GGGG in this population?
Consider an autosomal locus with alleles A and a. If the the allele frequencies are as follows Freq(A) = 0.4, Freq(a) = 0.6. , then what is the predicted frequency of heterozygous Aa individuals, assuming the population is in Hardy-Weinberg equilibrium? Freq(Aa) = ? Enter a number between 0 and 1, inclusive, for example 0.33
Suppose the frequency of the recessive allele a for the recessive condition albinism is 0.2 Assume the Hardy-Weinberg distribution. What is the frequency of albinism in the general population? What fraction of the population are carriers?
An autosomal locus has alleles A and a. The allele frequencies in a population at Hardy Weinberg equilibrium are p = Freq(A) = 0.5 q = Freq(a) = 0.5 What is the frequency of homozygous wild-type (AA) in this population? Enter a single number between 0 and 1, for example, 0.33
Consider the B locus which has two alleles in a population: B and b. Researchers examined the genotypes several individuals for this locus and obtained the following numbers B/B: 302individuals B/b: 56individuals b/b: 17individuals If the B locus is at Hardy-Weinberg equilibrium, what would the expected number of individuals with the Bb genotype? Round your answer to the closest full number.