TRUE or FALSE: this population is in Hardy-Weinberg equilibrium? What is the predicted frequency of spotted beetle?

There is a chromosome with two loci on it, Locus 1 that has alleles X and x, and Locus 2 that has alleles Y and y. The chromosome types exist in the following proportions:XY: 0.1 Xy: 0.3 xY: 0.4 xy: 0.2 Is this population in linkage equilibrium or linkage disequilibrium?        a. The population is in linkage equilibrium   b. The population is in linkage disequilibrium   c. This population switches between linkage equilibrium and linkage disequilibrium.   d. Not enough information to tell.

Approximately 1% of the magpies (Pica pica) in a hypothetical populations are albino. Assume that the albino phenotype is due to a recessive allele and that this population is in HardyWeinberg proportions at this locus.   (a)  What is the estimated frequency of the albino allele in this population?  (b) What is the probability that the first progeny born to a mating between an albino and a normal magpie from this population will be albino? (Hint: what is the probability that the normal magpie is heterozygous, given the allele frequencies in this population?)

Given the following observed genotype frequencies (AA 0.45, Aa 0.16 and aa 0.39) for a gene that determines coat color with incomplete dominance in a population of lemmings.  Allele "A" results in a dark colored coat.  Allele "a" results in a light colored coat.  What percent of the population would possess a dark coat as their phenotype?

Pretend that you are comparing the actual genotype distribution for a population with the distribution of genotypes predicted by the Hardy-Weinberg theorem.  So your hypothesis is that the population is in Hardy-Weinberg equilibrium (i.e. that actual population data fit the Hardy-Weinberg expectations).  If you carry out a chisquare goodness of fit test and calculate a total chisquare value of 0.03 with 1 degree of freedom (see table), what does this mean? (select all true statements)a) The data do NOT fit the hypothesized distribution.b) The data do fit the hypothesized distribution well enough, so we accept the hypothesis at this time (i.e. we cannot reject the hypothesis). c) The probability that the data came from a population in Hardy-Weinberg equilibrium is too small, so we reject the hypothesis.d) The probability that the data came from a population in Hardy-Weinberg equilibrium is too big, so we reject the hypothesis.e) The data support Hardy-Weinberg expectations – there is no…

Albinism is due to a recessive allele of an autosomal gene. Let a represent the albino allele and A represent the normal non-albino allele. If one out of every 10,000 people were albino and assuming that the population is in Hardy-Weinberg equilibrium, A. what would be the phenotype frequencies of albino and non-albino ? B. what would be the allele frequencies of a and of A? C. what fraction of people can be expected to be of the genotype Aa? D. what fraction of people can be expected to be of the genotype AA?

Consider an autosomal locus with alleles A and a. If the the allele frequencies are as follows Freq(A) = 0.4, Freq(a) = 0.6. , then what is the predicted frequency of heterozygous Aa individuals, assuming the population is in Hardy-Weinberg equilibrium? Freq(Aa) = ? Enter a number between 0 and 1, inclusive, for example 0.33