An autosomal locus has alleles A and a.  The allele frequencies in a population at Hardy Weinberg equilibrium are p = Freq(A) = 0.5 q = Freq(a) = 0.5 What is the frequency of homozygous wild-type (AA) in this population? Enter a single number between 0 and 1, for example, 0.33

You discover two segregating genes (A and B) that affect resistance in a population of snails. You are interested in determining if the two loci are in LD. You analyzed 100 snails for allelic and haplotype states, and observed the frequencies reported in the table below. a. Calculate D for genes A and B. (D = gAB9ab - gAb9aB) b. Is this population in linkage equilibrium or linkage disequilibrium with respect to genes A and B? Frequency Allele A 0.6 Allele a 0.4 Allele B 0.8 Allele b 0.2 Haplotype AB Haplotype Ab Haplotype aB Haplotype ab 0.48 0.12 0.32 0.08

In a large population of squirrels,  0.14 have the recessive genetic condition nlourianfilindr (fictional).  Assume the Hardy-Weinberg distribution.  What is the frequency of the dominant allele in this population? Giver your answer with two digits parts the decimal point.

If a disease determined by autosomal recessive heredity occurs at a frequency of 0.04 in a population, what is the frequency of this disease allele in the population? Assume Hardy-Weinberg equilibrium and use Aand a to symbolize the dominant and recessive alleles, respectively. Show calculation.

Genotypes of leopard frogs from a population in central Kansas were determined for a locus (M) that encodes the enzyme malate dehydrogenase. The following numbers of genotypes were observed:   Calculate the genotypic and allelic frequencies for the population (round to the nearest thousandth). f(M1M1) = f(M1M2) = f(M2M2) = f(M1M3) = f(M2M3) = f(M3M3) = f(M1) = f(M2) = f(M3) =   What would be the expected number of each genotype (round to the nearest whole number assuming genotype represents an individual) assuming the population was in Hardy Weinberg equilibrium? f(M1M1) = f(M1M2) = f(M2M2) = f(M1M3) = f(M2M3) = f(M3M3) =    Referencing a p-value of 0.05 and a CV of 11.070, state if the population is in HWE. Genotype Observed Expected O–E (O–E)2 (O–E)2/E M1M1           M1M2           M2M2           M1M3           M2M3           M3M3             Chi-squared = Statement:…

A population consists of 300 individuals with the following genotypes: AA – 100                               Aa – 125                  aa – 75 a.       What are the values of p and q? b.       Is the population in Hardy-Weinberg equilibrium? Explain.

The above data are from a landmark student looking into the relationship between sickle cell anemia and malaria. These data are from a population where malaria is prevalent. A is the allele for normal red blood cells; S is the sickle cell allele (you should know what this means). Is this population in H-W equilibrium? Make sure to use chi-square. Why or why not (if not, what assumption(s) violated). Genotype AA AS SS Total Observed 9365 (75.6%) 2993 (24.2%) 29 (0.2%) 12,387

Pretend that you are comparing the actual genotype distribution for a population with the distribution of genotypes predicted by the Hardy-Weinberg theorem.  So you hypothesize that the population is in Hardy-Weinberg equilibrium (i.e. that actual population data fit the Hardy-Weinberg expectations).  If you carry out chi-square goodness of fit test and calculate a total chi-square value of 0.03 with 1 degree of freedom (see table), what does this mean?

Could you help fill in tables UV-13 to find the allele and genotype frequencies using the Hardy- Weinberg equations Thank you

In mice, black fur (W) is dominant over white fur (w). In an ideal mouse population exhibiting Hardy–Weinberg equilibrium, 177 mice out of 236 have white fur.    Calculate the number of mice that are heterozygous dominant for the fur colour gene in the population.