Determine the absolute maximum bending stress in the tubular shaft if di = 160 mm and do = 200 mm
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Determine the absolute maximum bending stress in the tubular shaft if di = 160 mm and do = 200 mm
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- Draw SF and BM diagrams for the shaft below. 2 kN/m 600 mm 450mm 300 mmRepeat Problem 11.2-3 assuming that R= 10 kN · m/rad and L = 2 m.Question 1: A race car is turning (cornering) on a flat road, as shown in Figure Q1-1. The speed of the car is 300 kph and the turning radius is 260 m. Having the car parameters as below, answer questions a) and b). ● . ● ● m = 890 (kg) (57% of the weight is on the rear axle); Air density = 1.225 (kg/m3); Equivalent aerodynamic lift coefficient for front axle= -0.915 (-); Aerodynamic frontal area= 1.11 (m²); Slip angle of the front tyres= +2.4 (°); Slip angle of rear tyres= +1.2 (°); The steering angle of wheels= -1.9 (°); The efficiency of the drivetrain from the engine to the contact patch of tyres is 100%. 8=-1.9°- ---R=260 m α = +2.4° αR = +1.2° Figure Q1-1 Motion of the vehicle and the angles a) Calculate the engine power delivered to tyres to overcome the total induced drag due to lateral force.
- Q2/ A 3/4in-16 UNF SAE grade 5 bolt is subjected to a load of 8 kip in a tension joint. The initial bolt tension is F 30 kip. The bolt and joint stiffness's are kb=8 & km=15Mlbf/in, respectively. a) Determine the preload and service load stresses in the bolt. Compare the to the SAE minimum proof strength of the bolt. b) Specify the torque necessary to develop the preload.An automatic door lock system is to be designed for automatically locking/unlocking car doors. The design will utilize an electric solenoid with sufficient force and stroke to provide the necessary motion. If the force required to drive the lock linkage is 9.5 N, determine if the solenoid with the following specifications meets this requirement: Number of turns Current Air gap Plunger dia, 2500 1.0 Amps 10 mm 18 mm The initial force available from a solenoid F P=2(ND)² HA 82f1 = 235 N f2 = 564 N UDL kN/m = 1