4.26. In Chapter 11 we are much smarter and are able to show that for a cantilever beam, the force required to deflect the end, as is illustrated in Figure 4.32 is F Fig. 4.32 Cantilever beam subjected to a force at the end. 3EI L3 where E is the modulus of elasticity, which is a property of the material used, I is the area moment of inertia of the cross-section of the beam, and L is the length. If a mass m,is attached to the end of the beam, what is the equation of motion for the vertical motion of the beam? If the length is doubled, what is the change in frequency of the free vibration of the beam? x=0 F x=L

4.26. In Chapter 11 we are much smarter and are able to show that for a cantilever beam, the force required to deflect the end, as is illustrated in Figure 4.32 is F Fig. 4.32 Cantilever beam subjected to a force at the end. 3EI L3 where E is the modulus of elasticity, which is a property of the material used, I is the area moment of inertia of the cross-section of the beam, and L is the length. If a mass m,is attached to the end of the beam, what is the equation of motion for the vertical motion of the beam? If the length is doubled, what is the change in frequency of the free vibration of the beam? x=0 F x=L

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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ard and has been opened read-only to prevent modification. Enable Editing is one of the fundamental ering. A cantilever beam is other. In Fig. 3.35, the fixed Fig, 3.37. The beam is mounted to the wall at point A, the dentified as points A and C, ds to the center of gravity of Search Highlight Problem 3.9 Consider the L-shaped beam illustrated in P Export PDF arm AB extends in the z direction, and the arm BC extends in the x direction. A force F is applied in the z direction at Adobe Export PDF Convert PDF Files to Word or Excel Online the free-end of the beam. en has a weight W = 100 N (a) If the lengths of ams AB and BC are a and b, respectively, vith magnitude F = 150 N is cam in a direction that makes zontal. d direction of the net moment and the magnitude of the applied force is F, observe that the position vector of point C relative to point A can be written as r= bi+ ak and the force vector can be expressed as F = Fk, where i,j, and k are unit vectors indicating positive x, y,…