Below is a pedigree of a family, some of whom have the autosomal dominant condition Huntington's disease. Affected individuals are indicated by a dark square or circle. The male in generation I (indicated by the arrow) is heterozygous for the Huntington's disease mutation. The following two questions relate to this pedigree. Generation II II If H represents the disease allele, and h the wild type allele, what is the genotype of the individual indicated by the *? Select one alternative: O hh O Hh O hH О НН

Type 1 albinism in humans is a rare hereditary condition associated with a reduced amount of active tyrosinase, an enzyme required for the conversion of the amino acid tyrosine to the dark pigment melanin. In the pedigree above, males are indicated by squares, females by circles and individuals with type 1 albinism are indicated by shading. Use A and a for the dominant (sufficient active tyrosinase) and recessive alleles (absent or insufficient tyrosinase activity), respectively. Remember that, when genotype is not known for a dominant phenotype, an m-dash is used (A– = AA or Aa). If individuals B and E marry, what is the probability that their first child will be affected by type 1 albinism? А. 1/2 В. 1/12 С. 1/4 D. 2/3 O E. 1/24

Type 1 albinism in humans is a rare hereditary condition associated with a reduced amount of active tyrosinase, an enzyme required for the conversion of the amino acid tyrosine to the dark pigment melanin. In the pedigree above, males are indicated by squares, females by circles and individuals with type 1 albinism are indicated by shading. Use A and a for the dominant (sufficient active tyrosinase) and recessive alleles (absent or insufficient tyrosinase activity), respectively. Remember that, when genotype is not known for a dominant phenotype, an m-dash is used (A- = AA or Aa). Match the genotypes of the indicated family members as specifically as possible based on the pedigree data. Except where necessary to explain the pedigree, assume that the individuals marrying into the family are homozygous wild-type. v Individual A - v Individual B 1. A- v Individual C 2. Aa Individual C v Individual E

Cystic fibrosis (CF) is an autosomal recessive trait. A three-generation pedigree is shown below for a family that carries the mutant allele for cystic fibrosis. Note that carriers are not colored in to allow you to figure out their genotypes.      Normal allele =  F      CF mutant allele =  f        What is the genotype of individual #13? A) ff B) FF C) Ff  D) it is impossible to tell

Retinoblastoma can be seen as a familial cancer, inherited in an autosomal recessive manner (RB-/RB-), individuals heterozygous for the RB+ and RB- alleles can develop tumor as a result of… A mitotic crossover that leads to homozygosity for RB+ in some cells and RB- in other cells A meiotic mutation in the RB+ allele that leads to homozygosity for RB+ A somatic mutation in the RB- allele that leads to homozygosity for RB+ The fact that RB- is dominant to RB+

Pedigree information regarding the incidence of Tay-Sachs within a family is depicted above. The row below that indicates the genotypes of individuals II-1, II-2, and III-1 is Select one: a. II-1 II-2 III-1 Aa Aa aa   b. II-1 II-2 III-1 XAY XAXA XaXa

In humans, ABO blood types refer to glycoproteins in the membranes of red blood cells. There are three alleles for this autosomal gene: IA, IB, and i. The IA allele codes for the A sugar, The IB allele codes for the B sugar, and the i allele doesn't code for any sugar. IA and IB are codominant, and i is recessive to both IA and IB. If an individual with type AB blood has a child with an individual with type O blood, what blood types could their children possibly have?

the pedigree below shows the inheritance of a newly identified eye color gene. Assume 100% penetrance and expressivity. Use the pedigree to find: 1. Identify the mode of inheritance (either autosomal dominant, or autosomal recessive) 2. Argue why your mode of inheritance must be correct. Your argument should cite specific individuals from the pedigree. (For example, the top left individual is person I-1).

Shown below is a pedigree for a completely penetrant trait called Adams syndrome in which babies are born blind. This trait occurs when an allele of the adams gene is associated with ≥200 tandem trinucleotide repeats (the normal number is 10). First cousins, III-1 and III-2 married and their first child (IV-1) was blind. For their next child, they decided to do in vitro fertilization with III-1's sperm and III-2's eggs to generate six embryos (labeled E1-6). When each embryo contained eight cells, a single cell was removed and genomic DNA was isolated. PCR reactions using primers that flank the trinucleotide repeat region were then performed and the resulting fragments were fractionated on an agarose gel. PCR reactions using genomic DNA from III-1, III-2 and IV-1 were included as controls. The DNA was visualized using a fluorescent dye and the gel is shown below. Based on this information, select the best answer from the list to the questions below. || E1 = embryo 1 IV E1 E2 E3 E4 E5…

The pedigree below shows a family affected by a disease. Assume that the individuals marked with an asterisk (*) do not carry any allele associated with the affected phenotype, no other mutation spontaneously occurred, and complete penetrance. Answer the following questions below. Use the notation XR for the allele associated with the dominant phenotype and Xr for the allele associated with the recessive phenotype. Q1) Give the genotypes for as many individuals in the pedigree as possible.