1. What are the most probable genotypes of individuals II-9 and II-10 2. If individuals II-1 and II-2 have another child, what is the probability that it will have the disease?
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1. What are the most probable genotypes of individuals II-9 and II-10
2. If individuals II-1 and II-2 have another child, what is the probability that it will have
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- I II III II-1 11-2 Aa 1-1 11-3 Aa 1-2 II-4 III-1 Example: Given the pedigree above, what is the probability that the granddaughter (III-1) will be heterozygous? In order to determine the probability that III-1 is heterozygous, we need to determine the probability of the possible genotypes for her mother (II-2). Because the grandparents are both heterozygous, we would expect the following genotypic ratios in their offspring: ¼ AA, ½ Aa, and 14 aa. However, we have to use all possible information, and the circle representing III-1 is not shaded in, so she cannot be aa. Therefore, we eliminate the probability that II-2 is aa, and the final probability for II-2 is 1/3 AA and 2/3 Aa. We assume II-1 is AA because he is marrying into the family and we assume everyone marrying into a family is homozygous wild-type, unless proven otherwise. If II-2 is AA, and we assume II-1 is AA, then there is no chance that their daughter (III-1) is Aa If II-2 is Aa, and we assume II-1 is AA, then there is a…II 2 III 1 Refer to the pedigree above. What is the genotype of person II-1 if this pedigree is for hemophilia? (A dot in the centre of a symbol indicates a known carrier of a recessive trait). hh O xtxh Hh O xhy OxHy16) If individuals III-2 and III-3 have an additional child, what are the chances that it'll be an unaffected boy?
- 1 A B C 5 D 6 7 8 9 10 11 Which of the following best describes the genotype of parents in the pedigree? Female with Long Hair Female with Short Hair Male with Long Hair Male with Short Hair The mother is heterozygous for the long-hair allele, and the father is homozygous for the long-hair allele. The mother is heterozygous for the long-hair allele, and the father is heterozygous for the long-hair allele. The mother is homozygous for the long-hair allele, and the father is homozygous for the long-hair allele. The mother is homozygous for the long-hair allele, and the father is heterozygous for the long-hair allele. Submit2 11 11 IV 1. The pedigree above shows the passing on of colorblindness. What sex is MOST likely to be carriers of colorblindness? 2. Why does individual IV-7 (a female) have colorblindness? 3. Why do all the daughters in generation II carry the colorblind gene? 4. List 2 IV generation colorblind males.1 II 1 4 6. II 1 2 4 5 6. 8. IV The above image shows a pedigree for a monogenic inherited disease. Although this trait is only observed in males in this family, the pattern of inheritance of this disease is autosomal recessive. Use the pedigree to explain why the inheritance of this disease cannot be autosomal dominant. If this trait is X-linked recessive, what would be the genotypes of the people in Row I? 2. 2. 3. 2. 3.
- As it turned out, one of the tallest Potsdam Guards had an unquenchable attraction to short women. During his tenure as guard, he had numerous clandestine affairs. In each case, children resulted. Subsequently, some of the childrenwho had no way of knowing that they were relatedmarried and had children of their own. Assume that two pairs of genes determine height. The genotype of the 7-foot-tall Potsdam Guard was A9A9B9B9, and the genotype of all of his 5-foot clandestine lovers was AABB. An A9 or B9 allele in the offspring each adds 6 inches to the base height of 5 feet conferred by the AABB genotype. a. What were the genotypes and phenotypes of all the F1 children? b. Diagram the cross between the F1 offspring, and give all possible genotypes and phenotypes of the F2 progenyA pedigree analysis was performed on the family of a man with schizophrenia. Based on the known concordance statistics, would his MZ twin be at high risk for the disease? Would the twins risk decrease if he were raised in an environment different from that of his schizophrenic brother?what are the phenotypes of individuals #3 and 4?
- age An extra finger in humans is rare but is due to a dominant gene. When one parent is normal and the other parent has an extra finger but is heterozygous for the trait, what is the probability that the first child will have an extra finger? - /mod/quiz/attempt.php?attempt=1173673&cmid=3837312&page=11# Select one: O a. 25% O b. 50% O c. 75% O d. 0% O e. 100% @ 2 W # 3 E с $ 4 R G Search or type URL % 5 T MacBook Pro 6 Y & 7 ☆ U * 8 ( 9 F ) 0 0 Next page P (3) BO 11What do you know about individual III-1's mother? II II IV O Shehad the trait. She was a carrier. She was homozygous recessive. She was homozygous dominant.ii) State the genotypes of individuals # 1-5 in the following table using the letter "A". Use the uppercase letter to represent the dominant allele and lowercase letter to represent the recessive allele. Genotype Individual #1 # 3 #4 #5 If individuals # 2 and 3 have another son what are the chances that this son will be affected? b) i) What is the most likely mode of inheritance for this pedigree? ii) State the genotypes of individuals # 6-8 in the following table using the letter "B". Use the uppercase letter to represent the dominant allele and lowercase letter to represent the recessive allele. Individual # 6 7 # 7 # 8 Genotype