A spherical cell with the diameter of 10uMhas a protein concentration of 20 mg/ml. Determine the number of protein molecules within the cell if the molecular weight of an average protein is 50,000 daltons (g/mol). Recall that Avogadro's number is NA 6.0221367×1023 molecules/mol. =
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- Protein concentration can readily be determined using the Beer-Lambert law: A = e l c where A = absorbance e = molar absorption coefficient (M-1cm-1) l = light path length (cm) c = concentration (M) If the molar absorption coefficient at 280 nm for yeast ADH is 48860 M-1cm-1 and a 10 mL solution of the protein has an absorbance at 280 nm of 0.4 (as measured by a spectrometer with pathlength 1 cm), then what is the concentration of the protein solution (in μM)? i.e. concentration = ______ μM If the molecular weight of the protein is 36849, what is its concentration in mg/mL? i.e. concentration = _______ mg/mL For each part of the question, show your calculations to arrive at your answers.Please answer the question below and show all your work. You are given a pure protein sample to characterize and provided the following information: Its molar extinction coefficient, ε280, is 0.25 liters micromole^-1 cm^-1 Using a 0.5 cm pathlength cell, you measure the absorbance at 280 nm of a 20- fold dilution of your pure protein in solution (by this, we mean that 50 ul of the protein sample was diluted to a final volume of 1 ml) and find A280 = 0.40. What is the original concentration of the protein before dilution?Give only typing answer with explanation and conclusion You want to make 94 µL of the diluted Cell-Free extract for estimation of total protein. To do this, how much water will you add to the correct volume of the undiluted cell-free extract? Note: Cell-free extracts will need to be diluted 1:25 in water.
- Using the equation for the best-fit straight line through your data, the average absorbance of your unknown samples U1 and U2, and any dilution factors (DON’T LEAVE OUT THE DILUTION FACTOR), calculate the concentration of protein in the original unknown protein sample. y = 1.6849x + 0.0414R² = 0.9904Does this calculation look correct? My goal isto have a target mass of 10 µg of my protein with a total volume of 30 µl. Protein was measured and found to have a concentration of at 308.35 µg/ml Recall, mass = concentration * volume 10 µg = 308.35 µg/ml * V V = 0.01 mg/ 0.30835 mg/mL = 0.032430679 mL = 32.43067942 µL Note: cannot measure this amount; two dilutions required. Dilute by 1/40: measure 2.5 µl of protein at 0.30835 µg/µl and add it to 97.5 diluent to prepare a solution of protein at 7.71 mg/ml. This diluted sample will be used further. Mass = concentration * volume 10 µg = 7.71 mg/ml * V V = 0.01 mg/ 7.71 mg/ml = 1.3 µL Therefore, will measure 1.3 µl of protein at 7.71 mg/ml and add it to 28.7 µl of diluent.You are given a pure protein sample to characterize and provided the following information: Its molar extinction coefficient, ε280, is 0.25 liters micromole-1 cm-1 in both the folded and unfolded form Its ΔGo for unfolding is 1.5 kcal/mol at 37o (where RT = 0.59 kcal/mole) A) Using a 0.5 cm pathlength cell, you measure the absorbance at 280 nm of a 20-fold dilution of your pure protein in solution (by this, we mean that 50 ul of the protein sample was diluted to a final volume of 1 ml) and find A280 = 0.40. What is the original concentration of the protein before dilution? B) What is the concentration of the unfolded form of the protein in your sample?
- Consider the following protein mixture: Protein A B C D Molecular Weight (kDa) 50 150 200 350 Affinity to Metal ion === Zn²+ === 1. Using hydrophobic interaction chromatography, the protein that will be eluted last is [Select] 2. Using affinity chromatography, the protein that will be eluted last in a Zn²+-containing column is 3. The protein with the fastest migration towards the anode in SDS-PAGE is [Select] IpH value 7 3 9 5 [Select] [Select] 4. Using a buffer solution with a pH of 4, the protein that will bind to an anion exchanger is 5. The protein that will be eluted last in a gel filtration column is [Select] 6. Using isoelectric focusing, the protein that will have a protein band nearest to the cathode (negative electrode) is [Select] % Hydrophobicity 20 45 75 55Compute for the albumin to globulin (A/G) ratio using these data given Albumin= 51.9g/L Total protein = 75.5 g/L Note: answer should be in ratio formCompute for Total protein concentration Given: Absorbance of standard = 0.280 Absorbance of sample = 0.423 Concentration of standard = 5 g/dL NOTE: Convert your final answer to g/L
- A protein required 6.8 min to travel 82 cm to the detector in a 96 cm -long capillary tube with 25.4 kV between the ends. Find the apparent electrophoretic mobility. How many femtomoles of 2.4 μM protein are injected electrokinetically into a 50 μm diameter capillary at 5.0 kV for 3.0 sec. if the sample has half of the conductivity of the background electrolyte.pls answerA series of standard proteins and an unknown enzyme were studied by gel filtration on a Sephadex G200 (the 200 refers to the maximum pore size in kDa) column. The elution volume Vel for each protein is given in Table 1 below. (a) Plot the data in the form of log Mr versus elution volume. From the line of best fit through the points for the standards, determine the Mr of the unknown enzyme. Explain why ferritin and ovomucoid behave anomalously. Table 1 - The Vel versus Mr data Protein Mr Vel (mL) Blue dextran* Lysozyme Chymotrypsin Ovalbumin Serum albumin Aldolase Urease Ferritin# Ovomucoid# Unknown 1,000,000 14,000 25,000 45,000 68,500 150,000 500,000 700,000 28,000 ⎯ 85 200 190 170 150 125 90 92 160 139 *Blue dextran is not a protein but a high-Mr carbohydrate that has a covalently bound blue dye, and it elutes with the void volume of the column. # Do not…