Biochemistry
9th Edition
ISBN: 9781319114671
Author: Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher: W. H. Freeman
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Using the equation for the best-fit straight line through your data, the average absorbance of your unknown samples U1 and U2, and any dilution factors (DON’T LEAVE OUT THE DILUTION FACTOR), calculate the concentration of protein in the original unknown protein sample.
y = 1.6849x + 0.0414
R² = 0.9904
Transcribed Image Text:**Concentration of Standard Protein Stock Solution: 10 mg/mL**
| Tube | Absorbance at 540 nm | Diluted Concentration of Protein Standards (mg/mL) |
|--------|----------------------|-----------------------------------------------|
| Blank | 0 | 0 mg/mL |
| S1 | 0.11 | 0.2 mg/mL |
| S3 | 0.23 | 0.4 mg/mL |
| S3 | 0.43 | 0.8 mg/mL |
| S4 | 0.64 | 1.2 mg/mL |
| S5 | 0.96 | 1.6 mg/mL |
| U1 | 0.36 | |
| U2 | 0.34 | |
**Concentration of Protein in Unknown Sample: ______**
This table displays the absorbance values at 540 nm for different protein tubes, along with their corresponding diluted concentrations in mg/mL. The absorbance of the blank sample is 0, indicating no protein presence. Tubes S1, S3, S4, and S5 show increasing absorbance values, corresponding to higher protein concentrations. The unknown samples U1 and U2 have no given concentration values, which need to be determined from the absorbance data.
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