0 0.1 0.2 Normalized Intensity 0.3 0.4 -7.22 7.20 7.18 -7.06 -7.04 325.5 0.0050 U.00 350.5 0.0176 30 1.76 705.6 0.0410 43 4.83 1931.2 569 0.78 311.6 0.0569 18 1.06 424.5 0.0171 31 1.77 706.9 0.0215 44 7.04 2818.9 0.1228 0.78 313.3 0.3306 19 1.08 433.3 0.0199 32 1.78 712.4 0.0493 45 7.06 2825.2 0.0465 7 0.78 314.1 0.1493 20 1.19 477.5 0.0203 33 1.78 713.6 0.0217 46 7.06 2826.9 0.1630 8 0.79 317.3 0.0347 21 1.20 480.0 0.0252 34 1.80 719.2 0.0384 47 7.18 2874.4 0.0976 9 0.80 319.9 0.3062 10 0.80 321.9 0.1648 11 0.81 324.9 0.0809 12 0.82 327.9 0.9166 13 0.83 331.9 0.0988 22222 1.22 487.3 0.0237 35 1.81 725.9 0.0220 48 7.19 2877.9 0.0227 1.22 488.3 0.0195 36 2.38 953.3 0.1947 49 7.20 2879.9 0.1697 1.24 494.5 0.0187 37 2.40 960.6 0.1832 50 7.20 2881.6 0.0455 1.24 495.5 0.0180 38 2.51 1004.8 0.0513 51 7.21 2886.2 0.0406 1.41 564.8 0.5505 39 3.41 1362.7 0.0237 52 7.22 2887.9 0.1238 0.7 4 OH₂ 0.6 6 3 7 0.5 8. 2 0.73 1.24 0.03 0.78 1.00 0.19 0.41 ㅂ H 7.5 7.0 6.5 6.0 5.5 5.0 4.5 4.83 4.81 -4.79 4.78 No. (ppm) Value Absolute Value Non-Negative Value No. 1 7186.. 0.849.29831886 4.04236124e+10 9.29756831 11 Value (ppm) 5154.. 2.610.00149039 Absolute Value Non-Negative Value 6.47935250e+6 0.00149027 2 9959.. 1.070.28707433 1.24803008e+9 0.28705116 3 1678. 1.220.76462668 3.32414643e+9 0.76456496 12 4083.. 3.45-0.00170753 13 5951 .. 4.800.41017941 -7.42333250e+6 0.00000000 1.78321843e+9 0.41014630 4 3397.. 1.432.60550404 1.13271972e+10 2.60529372 14 8114.. 4.960.19421759 8.44343680e+8 0.19420192 5 6669.. 1.720.84659183 3.68048256e+9 0.84652349 15 0297.. 7.061.00000000 4.34741094e+9 0.99991928 6 7279. 1.740.08307895 3.61178336e+8 0.08307224 7 7446.. 1.790.64705968 2.81303424e+9 8 7945.. 1.820.28858626 9 3324.. 2.380.50680262 1.25460301e+9 2.20327936e+9 10 3823.. 2.421.43892062 6.25557914e+9 0.64700745 0.28856296 0.50676171 1.43880447 16 0629.. 7.110.78234935 17 1461..7.150.02843460 3.40119424e+9 0.78228620 1.23616880e+8 0.02843230 18 1517.. 7.211.23595273 19 2127.. 7.350.73474079 5.37319424e+9 1.23585297 3.19422029e+9 0.73468149 4.0 Chemical Shift (ppm) 3.5 0.00 ㅂ 3.0 -3.41 -2.51 -2.40 -2.38 1.77 1.76 1.70 1.43 -1.41 1.80 1.78 -1.78 1.81 1.20 1.22 1.19 -0.86 0.85 0.78 0.80 0.77 0.78 0.00 1.44 0.51 0.29 0.650.08 0.85 2.61 0.76 0.299.30 பப ㅂ ㅂ ㅂㅂ ㅂㅂㅂ 2.5 2.0 1.5 1.0 0.5 0.76 0.76 0.84 0.82

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Learning AA prod03-cnow-owl.cengagenow.com Login Learning Learning × Online tea... y dr. marlow... ember L... with We 3. AS surroundi... M 2BrF3 (9) Br2 (g) + 3F2 (9) 4. AG° = AH°... M 5. AG: Pre... 1req 6. AG: Enthal... Using standard thermodynamic data at 298 K, calculate the free energy change when 2.14 moles of BrF3 (9) react at standard conditions. Substance AG (kJ/mol) 7. AG fro... 1req Question Question Question 8. Calculat... 1req AG° = 9. Calculat... 1req BrF3 (9) -229.4 Br2(g) 3.1 F2(9) 0.0 kj

Assessment-Chem 18-Gen (X 80 $ 54 R UCI General Chemistry Peer Tu X 65.2% Use the molar bond enthalpy data in the table to estimate the value of AHin for the equation CCI, (g) + 2 F₂ (g) →→→ CF₂(g) + 2Cl₂(g) The bonding in the molecules is shown. ΔΗ; = 888 F4 ++++ % 5 FS F-F A 6 New Tab MacBook Air ܀ T Y F6 & 7 CICI CI-CI A4 F7 * 8 ∞ Resources Average molar bond enthalpics. (Hond) kJ. mol Bond 464 C=N 142 N-H 351 N-N 502 N=N 730 N=N 347 F-F 615 811 414 439 331 276 293 615 Bond O-H 0-0 C-0 0=0 C=0 C-C C=C C=C C-H C-F C-CI C-Br C-N C=N DII FB 69 DD F9 kJ Question Source: McQuarrie, Rock, And Gallogly 4e-General Chemistry Publisher: University Science Books 1 0 ) CI-CI Br-Br H-H H-F H-CI H-Br H-S S-S 0 A F10 I' Check Answer P kJ. mol-1 890 390 159 418 945 155 243 192 435 565 431 368 364 225 3 F11 0 + Show All 411) F12 X }

5964. X The in xIG what x I PAP C X G 2HCI X PAP C x G Thep x Q chapt x b ar-2903012.agilixbuzz.com/student/135113422/activity/9ff34d34-df47-4faa-a022-8d87ab138ea2 G.How x Chem x G List a x HASessi X Mastery Assess It 7 150% +, Reset PAP Chemistry-2903012-42100P-1 / Stoichiometry / Lesson 107 Enrique Solis All changes saved 13. Some rocket engines use a mixture of hydrazine, N2 H4, and hydrogen peroxide, H2O2, as the propellant. The reaction equation is N2H4(0) +2 H2O2() → N2(9) + 4 H2O(). Which is the limiting reagent in this reaction when 0.750 mol N2H4 is mixed with 0.500 mol H2O2? O a. H2O b. H2O2 O c. N2H4 с. NHА O d. N2 SAVE&EXIT 13 of 16 NEXT PREVIOUS O O

I 596420-7 x The impo X IG what ma X H PAP Cher X Qchapter x ぐ -> b ar-2903012.agilixbuzz.com/student/135113422/activity/9ff34d34-df47-4fas022 Mastery Assess It 7 PAP Chemistry-2903012-42100P-1/ Stoichiometry/Lesson 107 12. The combustion of glucose is represented by the following balanced equation: CGH12O6+6 0, 6 H20+6CO2. Which reactant is the limiting reagent if there is 1 gram of both 0, Hy06 and 0,7 O a. CgHy06 O b. H20 O c. 0, Od. CO,

Commun x Bb Blackboard Collaborate Ultra -2 X General Psychology-Fall 20 O X A ALEKS - Griffin Barden - Learn ww-awa.aleks.com/alekscgi/x/Isl.exe/1o_u-IgNslkr7j8P3jH-JcZzdcvSCzsqTCIDqNGV3bKqhMfPmUcQ4ENkmiXn9QCwgeDPDkQ06yszYWESPcekwL0-Qg619rekU7404HgFAGBEZaDr080?1oBw7QYjibavbSPXtx-YCjsh_7mMmrq#item O THERMOCHEMISTRY Griffin V Using Hess's Law to calculate net reaction enthalpy Nitric acid can be formed in two steps from the atmospheric gases nitrogen and oxygen, plus hydrogen prepared by reforming natural gas. In the first step, nitrogen and hydrogen react to form ammonia: N,(g) + 3 H,(g) → 2 NH3(g) AH=-92. kJ In the second step, ammonia and oxygen react to form nitric acid and water: NH3(g) + 20,(g) HNO3(g) H,O(g) AH=-330. kJ – + Calculate the net change in enthalpy for the formation of one mole of nitric acid from nitrogen, hydrogen and oxygen from these reactions. dla Round your answer to the nearest kJ. kJ

I need step by step process solving [4.184x156(Tf-295)] + [4.184x85.2(Tf-368)] = 0. because my work is wrong. Thank you!!

C 596420 X I The im X G what m X HPAP Ch x GHow m X G2HCIC X a ar-2903012.agilixbuzz.com/student/135113422/activity/9ff34d34-df47-4faa-a022-8d87ab138ca2 Chemi X Gst a x Sessio X Mastery Assess It_7 175% Reset PAP Chemistry-2903012-42100P-1/ Stoichiom... Enrique Solis All changes saved 16. How many moles of carbon dioxide are produced in the reaction between hydrochloric acid and calcium carbonate when 2 moles of HCl are used to start with? 2HCI + CaCO3 → CaCl2 + CO2 + H2O O 4 O 2 SUBMIT ALL ANS 16 of 16 SAVE & EXIT PREVIOUS 中

Help 100% 47 T. "ublic Health Ch HSC 258 - Major Projec x MindTap - Cengage Lea X C The Illustration To T =55750828934189288909969212&elSBN=9781305657571&id=D1061392007&nbld=21... * Q Search t Referonces Use the References to access important values if needed for this question. For the following reaction, 50.4 grams of sulfur dioxide are allowed to react with 17.9 grams of water. sulfur dioxide (g) + water (I) sulfurous acid (H2SO3) (g) grams What is the maximum amount of sulfurous acid (H,SO3) that can be formed? What is the FORMULA for the limiting reagent? grams What amount of the excess reagent remains after the reaction is complete? Submit Answer