Shigley's Mechanical Engineering Design (McGraw-Hill Series in Mechanical Engineering)
10th Edition
ISBN: 9780073398204
Author: Richard G Budynas, Keith J Nisbett
Publisher: McGraw-Hill Education
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Chapter 6, Problem 3P
A steel rotating-beam test specimen has an ultimate strength of 120 kpsi. Estimate the life of the specimen if it is tested at a completely reversed stress amplitude of 70 kpsi.
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A steel rotating-beam test specimen has an ultimate strength of 1600 MPa. Estimate the life of the specimenif it is tested at a completely reversed stress amplitude of 900 MPa.
If the ultimate strength of a steel rotating-beam test specimen was around 1600 MPa.
Estimate the life of the specimen if it is tested at a completely reversed stress
amplitude of 900 MPa.
A tensile test was conducted on a mild steel& the following data was obtained as follows. Diameter of the steel bar = 3 cm,Gauge length of the bar = 20 cm. Load at elastic limit = 250 kN . Extension at a load of 150kN = 0.21 mm . Maximum load = 380 kN . Total extension = 60 mm . Diameter of the rod at failure = 2. 25 cm
Determine: (a) Young’s modulus (b) stress at elastic limit (c)the percentage of elongation (d) Percentage decrease in area.
Chapter 6 Solutions
Shigley's Mechanical Engineering Design (McGraw-Hill Series in Mechanical Engineering)
Ch. 6 - A 10-mm steel drill rod was heat-treated and...Ch. 6 - Prob. 2PCh. 6 - A steel rotating-beam test specimen has an...Ch. 6 - A steel rotating-beam test specimen has an...Ch. 6 - A steel rotating-beam test specimen has an...Ch. 6 - Repeat Prob. 6-5 with the specimen having an...Ch. 6 - A steel rotating-beam test specimen has an...Ch. 6 - Derive Eq. (6-17). Rearrange the equation to solve...Ch. 6 - For the interval 103 N 106 cycles, develop an...Ch. 6 - Estimate the endurance strength of a...
Ch. 6 - Two steels are being considered for manufacture of...Ch. 6 - A 1-in-diamctcr solid round bar has a groove...Ch. 6 - A solid square rod is cantilevered at one end. The...Ch. 6 - A rectangular bar is cut from an AISI 1020...Ch. 6 - A solid round bar with diameter of 2 in has a...Ch. 6 - The rotating shaft shown in the figure is machined...Ch. 6 - The shaft shown in the figure is machined from...Ch. 6 - Solve Prob. 6-17 except with forces F1 = 1200 lbf...Ch. 6 - Bearing reactions R1 and R2 are exerted on the...Ch. 6 - A bar of steel has the minimum properties Se = 40...Ch. 6 - Repeat Prob. 6-20 but with a steady torsional...Ch. 6 - Repeat Prob. 6-20 but with a steady torsional...Ch. 6 - Repeat Prob. 6-20 but with an alternating...Ch. 6 - A bar of steel has the minimum properties Se = 40...Ch. 6 - The cold-drawn AISI KUO steel bar shown in the...Ch. 6 - Repeat Prob. 6-25 for a load that fluctuates from...Ch. 6 - An M14 2 hex-head bolt with a nut is used to...Ch. 6 - The figure shows a formed round-wire cantilever...Ch. 6 - The figure is a drawing of a 4- by 20-mm latching...Ch. 6 - The figure shows the free-body diagram of a...Ch. 6 - Solve Prob. 6-30 except let w1 = 2.5 in. w2 = l.5...Ch. 6 - For the part in Prob. 630, recommend a fillet...Ch. 6 - Prob. 33PCh. 6 - Prob. 34PCh. 6 - A part is loaded with a combination of bending,...Ch. 6 - Repeat the requirements of Prob. 6-35 with the...Ch. 6 - 6-37 to 6-46For the problem specified in the build...Ch. 6 - 6-37 to 6-46For the problem specified in the build...Ch. 6 - 637 to 646 For the problem specified in the table,...Ch. 6 - For the problem specified in the table, build upon...Ch. 6 - 6-37 to 6-46 For the problem specified in the...Ch. 6 - 6-37 to 6-46 For the problem specified in the...Ch. 6 - 6-37 to 6-46 For the problem specified in the...Ch. 6 - Problem Number Original Problem, Page Number 637...Ch. 6 - 6-37 to 6-46 For the problem specified in the...Ch. 6 - 6-37 to 6-46 For the problem specified in the...Ch. 6 - 6-47 to 6-50 For the problem specified in the...Ch. 6 - 6-47 to 6-50 For the problem specified in the...Ch. 6 - Prob. 49PCh. 6 - Prob. 50PCh. 6 - 6-51 to 6-53 For the problem specified in the...Ch. 6 - 6-51 to 6-53 For the problem specified in the...Ch. 6 - 6-51 to 6-53 For the problem specified in the...Ch. 6 - Solve Prob. 6-17 except include a steady torque of...Ch. 6 - Solve Prob. 618 except include a steady torque of...Ch. 6 - In the figure shown, shaft A, made of AISI 1020...Ch. 6 - A schematic of a clutch-testing machine is shown....Ch. 6 - For the clutch of Prob. 657, the external load P...Ch. 6 - A flat leaf spring has fluctuating stress of max =...Ch. 6 - A rotating-beam specimen with an endurance limit...Ch. 6 - A machine part will be cycled at 350 MPa for 5...Ch. 6 - The material properties of a machine part are Sut...Ch. 6 - Repeat Prob. 662 using the Goodman criterion....
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- Find the equivalent stresses at Points 1 and 2 of the element with given geometry and loading conditions according to the Maximum shear stress hypothesis and the Maximum strain energy hypothesis. Shaft diameter: 20 mm, Shaft Length 120 mm, F1 = 750N, F2 = 3000N, Mb = 2400 N.mm. Steel if St37 and Safety coefficient is 2 If taken, will this stick work safely under these operating conditions? (Yield of given steel Strength 225 Mpa, Tensile strength 370 Mpa)arrow_forward2 Estimate the fatigue strength of a rotating-beam made of AISI 1035 CR steel corresponding to a life of 10° cycles of stress reversal. Also, estimate the life of the specimen corresponding to stress amplitude of 60 ksi.arrow_forwardA rod specimen of ductile cast iron was tested in a torsion-testing machine. The rod diameter was 14 mm, and the rod length was 440 mm. When the applied torque reached 225.3 N-m, a shear strain of 2105 microradians was measured in the specimen. What was the angle of twist in the specimen? Calculate the shear stress in the specimen. Answer: T = MPaarrow_forward
- Estimate the fatigue strength of a rotating-beam made of AISI 1020 HR steel corresponding to a life of 12.5 kilocycles of stress reversal. Also, estimate the life of the specimen corresponding to stress amplitude of 36 ksi.arrow_forwardA rod specimen of ductile cast iron was tested in a torsion-testing machine. The rod diameter was 16 mm, and the rod length was 360 mm. When the applied torque reached 254.8 N-m, a shear strain of 1780 microradians was measured in the specimen. What was the angle of twist in the specimen? Part 1 Calculate the shear stress in the specimen. Answer: T= i MPaarrow_forwardA rod specimen of ductile cast iron was tested in a torsion-testing machine. The rod diameter was 14 mm, and the rod length was 440 mm. When the applied torque reached 225.3 N-m, a shear strain of 2105 microradians was measured in the specimen. What was the angle of twist in the specimen? Calculate the shear stress in the specimen. Answer: T= 418.16 Use Hooke's Law to calculate the shear modulus of the specimen. answer: MPa G = i MPaarrow_forward
- 1. A steel of rotating-beam test specimen has an ultimate strength of 1600Mpa. Estimate the life of the specimen if it is tested at a completely reversed stress amplitude of 900MPA. Hint: You can either extrapolate the curve of f vs. Sut, or use the equation derived on P10 to estimate the value of f.arrow_forwardScenario. Three specimen of D12 rebar was subjected to a Tensile Test. Using a steel density of 8000Kg/cu.m. With the following result specimen 1 specimen 2 M=0.895 kg M=0.89 kg L=98 cm L=99 cm Load at yield strength= 5000 kg Load at ultimate =8600 kg Gauge length after test=21.5 cm Load at yield strength= 5000 kg Load at ultimate =8600 kg Gauge length after test=21.6 cm specimen 3 M=0.897 kg L=100 cm Load at yield strength= 5010 kg Load at ultimate strength=8590 kg Gauge length after test=21.6 cm specimen Yield strength Yield strength Ultimate strength Ultimate strength STRAIN based on actual based on 12mm based on actual based on 12mm diameter (MPa) diameter (MPa) diameter (MPa) diameter (MPa) 1. 2. averagearrow_forward*O llAsiacell Strength of m. -> 02: A steel specimen 12mm diameter has gauge length 50mm. the steel specimen had tested via tensile test under maximum load 66KN with elongation 7.5mm, and the yield load of this specimen is 15KN with elongation 2.4mm. Calculate: 1- The engineering ultimate stress (ultimate tensile strength), and engineering strain at this point. 2- The engineering stress and strain at yield point. 3- The modulus of elasticity, and the modulus of resilience. 4- The final or fracture strain of a steel specimen, if you know that the final length of specimen after testing is 58.5mm. 5- The true stress and strain for ultimate point. Q3: The yoke-and-rod connection is subjected to a tensile force of 15 kN. Determine the average normal stress in each rod and the average shear stress in the pin A between the members. Finally, find the shear strain in pin A. Take G teef 75GPA 40 mm 15 kN, 30 mm 30 mn 15 kN 04: In figure as shown below, assume that a 35mm diameter rivet joint the…arrow_forward
- 1. A steel rotating-beam specimen has an ultimate strength of 1600 MPa. It is tested at a completely reversed stress amplitude of 900 MPa. The life of the specimen is ( _) cycles.arrow_forwardA Brass specimen is subjected to a Tensile test in a laboratory. The following data obtained are: Length of Specimen = 367 mm; Diameter of Specimen = 19 mm; Yield Stress = 124 N/mm?: Ultimate Stress = 217 N/mm?: Fracture Stress = 183 N/mm?: % of Elongation = 50 % % of Reduction in area = 27 %. Determine the elongation at 103 kN, Load at yielding. Maximum load, Load at fracture, Final Length & Final diameter. Take Young's Modulus as 104 GPa.arrow_forwardDetermine the yield strength of a material required such that the component would not fail when subject to the following stresses sigma1 = 2 MPa and sigma 2= -15 MPa sigma 3 = 10 MPa). Use a yield criterion that assumes that yield failure will occur when the maximum shear stress in the complex system becomes equal to the limiting shear strength in a simple tensile test.arrow_forward
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