Microelectronic Circuits (The Oxford Series in Electrical and Computer Engineering) 7th edition
7th Edition
ISBN: 9780199339136
Author: Adel S. Sedra, Kenneth C. Smith
Publisher: Oxford University Press
expand_more
expand_more
format_list_bulleted
Question
thumb_up100%
Chapter 4, Problem D4.60P
To determine
The value of load regulation for two kind of diodes.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
4. For the circuit shown in the figure below uses a transformer of 230V/12V-0-12V and all diodes are Ge find
the following, RL-3.3k2. The name of the circuit is ........
Current through the load is............The DC output voltage is............ Draw the input & output wave forms
✈
ellel
eetee
CT
D₂
DE
www
R₂
Power supply circuit is delivering 0.5 A and an average voltage 20 V to the load as shown in the circuit
below. The ripple voltage of the half wave rectifier is 0.5 V and the diode is represented using constant
voltage model. The smoothing capacitor value is equal to
220V ams
5OHZ
İL-DC =05A
RL VL-DC =20V
3: Using silicon diode design a clamper that will produce output V,-20Sin wt+10 (v) when the input
voltage is Vo=20Sin wt-10 (V).Draw the circuit diagram and the input and output signals.
4:The 6-V zener diode has a maximum rated power dissipated of 690 mw.Its reveres current must be
at least 3mA to keep it in breakdown. Find a suitable value for Rs if V; can vary from 9v to 12v
and Ri. can vary from 5000 to 1.2KO.
Chapter 4 Solutions
Microelectronic Circuits (The Oxford Series in Electrical and Computer Engineering) 7th edition
Ch. 4.1 - Prob. 4.1ECh. 4.1 - Prob. 4.2ECh. 4.1 - Prob. 4.3ECh. 4.1 - Prob. 4.4ECh. 4.1 - Prob. 4.5ECh. 4.2 - Prob. 4.6ECh. 4.2 - Prob. 4.7ECh. 4.2 - Prob. 4.8ECh. 4.2 - Prob. 4.9ECh. 4.3 - Prob. 4.10E
Ch. 4.3 - Prob. D4.11ECh. 4.3 - Prob. 4.12ECh. 4.3 - Prob. 4.13ECh. 4.3 - Prob. 4.14ECh. 4.3 - Prob. D4.15ECh. 4.4 - Prob. 4.16ECh. 4.4 - Prob. 4.17ECh. 4.4 - Prob. 4.18ECh. 4.5 - Prob. 4.19ECh. 4.5 - Prob. 4.20ECh. 4.5 - Prob. 4.21ECh. 4.5 - Prob. 4.22ECh. 4.5 - Prob. 4.23ECh. 4.5 - Prob. 4.24ECh. 4.5 - Prob. 4.25ECh. 4.6 - Prob. 4.26ECh. 4.6 - Prob. 4.27ECh. 4 - Prob. 4.1PCh. 4 - Prob. 4.2PCh. 4 - Prob. 4.3PCh. 4 - Prob. 4.4PCh. 4 - Prob. 4.5PCh. 4 - Prob. 4.6PCh. 4 - Prob. D4.7PCh. 4 - Prob. D4.8PCh. 4 - Prob. 4.9PCh. 4 - Prob. 4.10PCh. 4 - Prob. D4.11PCh. 4 - Prob. 4.12PCh. 4 - Prob. 4.13PCh. 4 - Prob. 4.14PCh. 4 - Prob. D4.15PCh. 4 - Prob. 4.16PCh. 4 - Prob. 4.17PCh. 4 - Prob. 4.18PCh. 4 - Prob. 4.19PCh. 4 - Prob. 4.20PCh. 4 - Prob. 4.21PCh. 4 - Prob. 4.22PCh. 4 - Prob. 4.23PCh. 4 - Prob. 4.24PCh. 4 - Prob. 4.25PCh. 4 - Prob. 4.26PCh. 4 - Prob. 4.27PCh. 4 - Prob. 4.28PCh. 4 - Prob. 4.29PCh. 4 - Prob. 4.30PCh. 4 - Prob. 4.31PCh. 4 - Prob. 4.32PCh. 4 - Prob. 4.33PCh. 4 - Prob. 4.34PCh. 4 - Prob. 4.35PCh. 4 - Prob. 4.36PCh. 4 - Prob. D4.37PCh. 4 - Prob. 4.38PCh. 4 - Prob. 4.39PCh. 4 - Prob. 4.40PCh. 4 - Prob. 4.41PCh. 4 - Prob. 4.42PCh. 4 - Prob. 4.43PCh. 4 - Prob. 4.44PCh. 4 - Prob. D4.45PCh. 4 - Prob. 4.46PCh. 4 - Prob. 4.47PCh. 4 - Prob. 4.48PCh. 4 - Prob. 4.49PCh. 4 - Prob. 4.50PCh. 4 - Prob. 4.51PCh. 4 - Prob. 4.52PCh. 4 - Prob. 4.53PCh. 4 - Prob. 4.54PCh. 4 - Prob. 4.55PCh. 4 - Prob. D4.56PCh. 4 - Prob. D4.57PCh. 4 - Prob. 4.58PCh. 4 - Prob. 4.59PCh. 4 - Prob. D4.60PCh. 4 - Prob. 4.61PCh. 4 - Prob. 4.62PCh. 4 - Prob. D4.63PCh. 4 - Prob. D4.64PCh. 4 - Prob. D4.65PCh. 4 - Prob. D4.66PCh. 4 - Prob. 4.67PCh. 4 - Prob. 4.68PCh. 4 - Prob. 4.69PCh. 4 - Prob. 4.70PCh. 4 - Prob. 4.71PCh. 4 - Prob. 4.72PCh. 4 - Prob. D4.73PCh. 4 - Prob. D4.74PCh. 4 - Prob. D4.75PCh. 4 - Prob. 4.76PCh. 4 - Prob. 4.77PCh. 4 - Prob. 4.78PCh. 4 - Prob. 4.79PCh. 4 - Prob. D4.80PCh. 4 - Prob. D4.81PCh. 4 - Prob. D4.82PCh. 4 - Prob. D4.83PCh. 4 - Prob. D4.84PCh. 4 - Prob. 4.85PCh. 4 - Prob. 4.86PCh. 4 - Prob. 4.87PCh. 4 - Prob. 4.88PCh. 4 - Prob. 4.89PCh. 4 - Prob. 4.90PCh. 4 - Prob. 4.91PCh. 4 - Prob. 4.92PCh. 4 - Prob. 4.93PCh. 4 - Prob. 4.94PCh. 4 - Prob. 4.95PCh. 4 - Prob. 4.96PCh. 4 - Prob. 4.97P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, electrical-engineering and related others by exploring similar questions and additional content below.Similar questions
- For the following limiter consider that both zener diodes are identical with Vz = 4.5V @ lz =20mA and rz = 502. Also assume that the zener diodes will have a constant voltage drop of 0.75 V when forward-biased. R Z, Z a) Find the value of R such that the positive and negative limits are +5V when the input reaches ±10V. b) Sketch and label the voltage transfer characteristic for input voltages between ±10 V.arrow_forwardUsing an ideal diode, design a clamper circuit that result in the desired output waveform as shown in Figure Q7. Show overall analysis to justify the proposed design. 7. Vo Vi Designed Clamper Circuit - 3 V -20 - 43 V - Fiqure Q7 20arrow_forwardThere are two LEDS that can be used as a polarity detector. Apply a positive source voltage and a green light results. Negative supplies result in a red light. Packages of such combinations are commercially available.Find the resistor R to ensure a current of 20 mA through the "on" diode for the configuration. Both diodes have a reverse breakdown voltage of 3 V and an average turn-on voltage of 2 V. +8 V Red Greenarrow_forward
- Given the following circuit with VDD= 9.2 V, R=2.3 k2, then the current Iis: Use the CVD model for the diode, with VD = 0.65 V. I VDD a. 0.004000 A O b. 3.717391 A OC. 0 A d. 4.000000 A e. 0.003717 A R + VD -arrow_forwardThere are two LEDs that can be used as a polarity detector. Apply a positive source voltage and a green light results. Negative supplies result in a red light. Packages of such combinations are commercially available.Find the resistor R to ensure a current of 20 mA through the “on” diode for the configuration. Both diodes have a reverse breakdown voltage of 3 V and an average turn-on voltage of 2 Varrow_forwardA zener diode exhibits a certain change in VZ for a certain change in IZ on a portion of the linear characteristic curve between IZK and IZM as illustrated in Figure 5. Calculate the zener impedance.arrow_forward
- For the circuit shown in the Figure, if the diodes are silicon diodes with VD(on)=0.7 V, and VIn=50 sin wt V, V1 =7 V and V2 =13 V, then the value of VOUT (p-p) is: R1 D, D2 VIN VOUT vi E v2= Ca. 19.4 V Ob. 17.4 V Cc. 15.4 V Cd. 21.4 Varrow_forwardLet’s look at the Wheatstone bridge where antiparallel diodes are place between nodes A and B. Assume the diodes have the following characteristic:arrow_forwardconsider the figure below that shows an approximated reverse recovery turn-off characteristics for a power diode. Show that the following relation can express the total reverse recovery charge, Qrr = 1/2(trr*ts1) di1/dt =1/2(trr*ts21) di2/dt * ip Isl 1s2! -Irarrow_forward
- The step up chopper has R=20 ohm and out put voltage is 120V. The source voltage is 40V DC . The load inductance is 0.2mH. If the chopper frequency is 4KHZ find1- the duty cycle2- the average value of source current3- TON4- Imax5- Imin6-The average value of diode currentarrow_forward2. Figure A.1 shows I-V characteristics of two diodes, namely A and B. Diode A has higher dynamic resistance than diode B. UTM &UT ID 4 5UTM 3TM UTM UTM &UTM 5 UTM & UTM UTM 3 UTM 03 TM 6 UT 0.68 (a) UTM VD Figure A.1 State one possible reason why the diodes have different knee voltage values. UTM OM & UTM 3 UTM & TM (b) Based on Figure A.1, identify the knee voltage of UTM" TM 5 UTde BE UTMarrow_forwardAs shown is a positive parallel clipper circuit which has an input voltage of E=t5V. The negative output voltage is to be -4.5V when lo is 5mA. Assume ideal diode model approximation. Determine the value of R1 in ohms. Note: Write only the numeric value of the answer, round to 4 decimal places. No need to include the unit. R, +E ww Output Input D, -E -(E-1,R,)arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Introductory Circuit Analysis (13th Edition)Electrical EngineeringISBN:9780133923605Author:Robert L. BoylestadPublisher:PEARSONDelmar's Standard Textbook Of ElectricityElectrical EngineeringISBN:9781337900348Author:Stephen L. HermanPublisher:Cengage LearningProgrammable Logic ControllersElectrical EngineeringISBN:9780073373843Author:Frank D. PetruzellaPublisher:McGraw-Hill Education
- Fundamentals of Electric CircuitsElectrical EngineeringISBN:9780078028229Author:Charles K Alexander, Matthew SadikuPublisher:McGraw-Hill EducationElectric Circuits. (11th Edition)Electrical EngineeringISBN:9780134746968Author:James W. Nilsson, Susan RiedelPublisher:PEARSONEngineering ElectromagneticsElectrical EngineeringISBN:9780078028151Author:Hayt, William H. (william Hart), Jr, BUCK, John A.Publisher:Mcgraw-hill Education,
Introductory Circuit Analysis (13th Edition)
Electrical Engineering
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:PEARSON
Delmar's Standard Textbook Of Electricity
Electrical Engineering
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Cengage Learning
Programmable Logic Controllers
Electrical Engineering
ISBN:9780073373843
Author:Frank D. Petruzella
Publisher:McGraw-Hill Education
Fundamentals of Electric Circuits
Electrical Engineering
ISBN:9780078028229
Author:Charles K Alexander, Matthew Sadiku
Publisher:McGraw-Hill Education
Electric Circuits. (11th Edition)
Electrical Engineering
ISBN:9780134746968
Author:James W. Nilsson, Susan Riedel
Publisher:PEARSON
Engineering Electromagnetics
Electrical Engineering
ISBN:9780078028151
Author:Hayt, William H. (william Hart), Jr, BUCK, John A.
Publisher:Mcgraw-hill Education,
Three-Phase Half-Wave Rectifier Operation; Author: katkimshow;https://www.youtube.com/watch?v=Uhbr6tbMB9A;License: Standard Youtube License