Microelectronic Circuits (The Oxford Series in Electrical and Computer Engineering) 7th edition
7th Edition
ISBN: 9780199339136
Author: Adel S. Sedra, Kenneth C. Smith
Publisher: Oxford University Press
expand_more
expand_more
format_list_bulleted
Question
Chapter 4, Problem 4.69P
To determine
The average value of output voltage
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
Draw the corresponding output waveform of the double diode partial limiter below using
simplified diode model. Indicate all the necessary voltage levels and use Silicon diodes.
20 VP-P
1KQ
M
D1
9V
D2
4.5V
VOUT
In the clamping circuit below, assume the diode has Von-0.7V and V₁ is a sinusoidal wave with
a peak-to-peak amplitude of 10V.
How much is the maximum value of the output voltage signal (Vmax)? And how much will it be if we
set V₂=2V?
Input
V1
C1
0.1e-6
9.3 V and 7.3 V
9.3 V and 11.3 V
11.3 V and 7.3 V
O 7.3 V and 12.0 V
O 12.0 V and 7.3 V
Output
D1
1N4148
.tran 30-3
V2
0
Vmax
V(output)
0.0ms
putput
MAN
Input
0.6ms
1.2ms
V(input)
1.8ms
2.4ms
3.0ms
Questions 1
V, is a 60Hz source with a peak voltage VP-120V is feeding a rectifier, assume ideal diode. The load resistance
has a value of R= 10 kn.
If ripple voltage Vr = 2V, the Diode average current Ipavg is
VI
Select one:
None
b. 580mA
850mA
O c.
Od 245mA
O e. 425mA
D
C
C:
R
www
Q+
Vo
Chapter 4 Solutions
Microelectronic Circuits (The Oxford Series in Electrical and Computer Engineering) 7th edition
Ch. 4.1 - Prob. 4.1ECh. 4.1 - Prob. 4.2ECh. 4.1 - Prob. 4.3ECh. 4.1 - Prob. 4.4ECh. 4.1 - Prob. 4.5ECh. 4.2 - Prob. 4.6ECh. 4.2 - Prob. 4.7ECh. 4.2 - Prob. 4.8ECh. 4.2 - Prob. 4.9ECh. 4.3 - Prob. 4.10E
Ch. 4.3 - Prob. D4.11ECh. 4.3 - Prob. 4.12ECh. 4.3 - Prob. 4.13ECh. 4.3 - Prob. 4.14ECh. 4.3 - Prob. D4.15ECh. 4.4 - Prob. 4.16ECh. 4.4 - Prob. 4.17ECh. 4.4 - Prob. 4.18ECh. 4.5 - Prob. 4.19ECh. 4.5 - Prob. 4.20ECh. 4.5 - Prob. 4.21ECh. 4.5 - Prob. 4.22ECh. 4.5 - Prob. 4.23ECh. 4.5 - Prob. 4.24ECh. 4.5 - Prob. 4.25ECh. 4.6 - Prob. 4.26ECh. 4.6 - Prob. 4.27ECh. 4 - Prob. 4.1PCh. 4 - Prob. 4.2PCh. 4 - Prob. 4.3PCh. 4 - Prob. 4.4PCh. 4 - Prob. 4.5PCh. 4 - Prob. 4.6PCh. 4 - Prob. D4.7PCh. 4 - Prob. D4.8PCh. 4 - Prob. 4.9PCh. 4 - Prob. 4.10PCh. 4 - Prob. D4.11PCh. 4 - Prob. 4.12PCh. 4 - Prob. 4.13PCh. 4 - Prob. 4.14PCh. 4 - Prob. D4.15PCh. 4 - Prob. 4.16PCh. 4 - Prob. 4.17PCh. 4 - Prob. 4.18PCh. 4 - Prob. 4.19PCh. 4 - Prob. 4.20PCh. 4 - Prob. 4.21PCh. 4 - Prob. 4.22PCh. 4 - Prob. 4.23PCh. 4 - Prob. 4.24PCh. 4 - Prob. 4.25PCh. 4 - Prob. 4.26PCh. 4 - Prob. 4.27PCh. 4 - Prob. 4.28PCh. 4 - Prob. 4.29PCh. 4 - Prob. 4.30PCh. 4 - Prob. 4.31PCh. 4 - Prob. 4.32PCh. 4 - Prob. 4.33PCh. 4 - Prob. 4.34PCh. 4 - Prob. 4.35PCh. 4 - Prob. 4.36PCh. 4 - Prob. D4.37PCh. 4 - Prob. 4.38PCh. 4 - Prob. 4.39PCh. 4 - Prob. 4.40PCh. 4 - Prob. 4.41PCh. 4 - Prob. 4.42PCh. 4 - Prob. 4.43PCh. 4 - Prob. 4.44PCh. 4 - Prob. D4.45PCh. 4 - Prob. 4.46PCh. 4 - Prob. 4.47PCh. 4 - Prob. 4.48PCh. 4 - Prob. 4.49PCh. 4 - Prob. 4.50PCh. 4 - Prob. 4.51PCh. 4 - Prob. 4.52PCh. 4 - Prob. 4.53PCh. 4 - Prob. 4.54PCh. 4 - Prob. 4.55PCh. 4 - Prob. D4.56PCh. 4 - Prob. D4.57PCh. 4 - Prob. 4.58PCh. 4 - Prob. 4.59PCh. 4 - Prob. D4.60PCh. 4 - Prob. 4.61PCh. 4 - Prob. 4.62PCh. 4 - Prob. D4.63PCh. 4 - Prob. D4.64PCh. 4 - Prob. D4.65PCh. 4 - Prob. D4.66PCh. 4 - Prob. 4.67PCh. 4 - Prob. 4.68PCh. 4 - Prob. 4.69PCh. 4 - Prob. 4.70PCh. 4 - Prob. 4.71PCh. 4 - Prob. 4.72PCh. 4 - Prob. D4.73PCh. 4 - Prob. D4.74PCh. 4 - Prob. D4.75PCh. 4 - Prob. 4.76PCh. 4 - Prob. 4.77PCh. 4 - Prob. 4.78PCh. 4 - Prob. 4.79PCh. 4 - Prob. D4.80PCh. 4 - Prob. D4.81PCh. 4 - Prob. D4.82PCh. 4 - Prob. D4.83PCh. 4 - Prob. D4.84PCh. 4 - Prob. 4.85PCh. 4 - Prob. 4.86PCh. 4 - Prob. 4.87PCh. 4 - Prob. 4.88PCh. 4 - Prob. 4.89PCh. 4 - Prob. 4.90PCh. 4 - Prob. 4.91PCh. 4 - Prob. 4.92PCh. 4 - Prob. 4.93PCh. 4 - Prob. 4.94PCh. 4 - Prob. 4.95PCh. 4 - Prob. 4.96PCh. 4 - Prob. 4.97P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, electrical-engineering and related others by exploring similar questions and additional content below.Similar questions
- What is the difference between a diode and rectifier?arrow_forwardConsidering a clamper circuit, where capacitance C, load R, the cut-in voltage of diode are unknown, which is the correct statement 1- the dc level of the signal changes 2- the peak-to-peak value of signal changes 3- the shape of signal changes 4- the dc level shifts up 5- the dc level shifts downarrow_forwardPower supply circuit is delivering 0.5 A and an average voltage 20 V to the load as shown in the circuit below. The ripple voltage of the half wave rectifier is 0.5 V and the diode is represented using constant voltage model. The smoothing capacitor value is equal to 220V ams 5OHZ İL-DC =05A RL VL-DC =20Varrow_forward
- The single phase half-wave uncontrolled rectifier has a freewheeling diode and a ripple free average load current of 2OA (high inductance). The source is 220V 50HZ. Determine the input PF and HF (THD) of the source current at the rectifier inputarrow_forwardSelect any diode from LTSpice Library. (The type of diode should either be RECTIFIER or SILICON) Create a Half-Wave Rectifier circuit. Use a resistor of 1000 Ohms. Input Voltage should be 95VAC - 65Hz Plot both the Input voltage and output voltage. Determine the Voltage drop across the diode by subtracting the output voltage to the input voltage peaks. Create a Bridge-Type Full Wave Rectifier Circuit. Repeat the steps done on the Half-Wave Rectifier circuit.arrow_forwardConsider all Si diodes and Vi has a peak amplitude of 10V Find Vi and Vo relationship assuming diode ON and OFF Draw the timing diagram between Vi and Vo Draw the transfer characteristicsarrow_forward
- Q4) Determine and sketch the output voltage across the load resistor (RL) for the circuit shown below. (assume Si diodes) V_DC 0.75 0.25 V_SIN Y SIN as RL -1 v SOR V_SQR 0.75 -0.75 V_TRI V TRI asarrow_forwardAssuming an ideal diode, sketch Vị, Và and ia for the half-wave rectifier below. The input is sinusoidal waveform with a frequency of 60 Hz. Also, determine and sketch V, and ir Ideal V-2 V 2.2 ka R 6.8 kaarrow_forwardPower supply circuit is delivering 0.5 A and an average voltage 20 V to the load as shown in the circuit below. The ripple voltage of the half wave rectifier is 0.5 V and the diode is represented using constant voltage model. The smoothing capacitor value is equal to IL-DC =0:5A RL VL-DC =20V 220V omsb O 001 F O 0.02 F O 0.0167F O None of the above Activatearrow_forward
- For the circuit shown below, sketch to scale the output V waveform and draw the transfer characteristic (V versus Vi), Assume the diodes are ideal.arrow_forwardThe cut-in voltage for each diode in the circuits shown in Figure Pl.30 is V, = 0.6 V. For each circuit, determine the diode current I, and the voltage Vo (mea- sured with respect to ground potential). Q7 R= 10 k2 Vo oVo Ip R= 10 k2 5 V 5V 5 V 5 V (a) (b) R= 10 k2 Vo 5V E 5 V (c)arrow_forwardPower supply circuit is delivering 0.5 A and an average voltage 20 V to the load as shown in the circuit below. The ripple voltage of the half wave rectifier is 0.5 V and the diode is represented using constant voltage model. The smoothing capacitor value is equal to 220V omsh RL VI-DC20V 0.01 F 0.02 F 0.0167 F None of the abovearrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Electricity for Refrigeration, Heating, and Air C...Mechanical EngineeringISBN:9781337399128Author:Russell E. SmithPublisher:Cengage Learning
Electricity for Refrigeration, Heating, and Air C...
Mechanical Engineering
ISBN:9781337399128
Author:Russell E. Smith
Publisher:Cengage Learning
Three-Phase Half-Wave Rectifier Operation; Author: katkimshow;https://www.youtube.com/watch?v=Uhbr6tbMB9A;License: Standard Youtube License