Microelectronic Circuits (The Oxford Series in Electrical and Computer Engineering) 7th edition
7th Edition
ISBN: 9780199339136
Author: Adel S. Sedra, Kenneth C. Smith
Publisher: Oxford University Press
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 4, Problem 4.25P
To determine
The value of currents through the diodes
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
Diodes Are Connected In
Series To Share A Total...
21
Question
• Two diodes are connected in series to share
a total reverse voltage of VD=D 5 KV. Reverse leakage
currents of the diodes are ID1=30 mA and Ip2=35 mA.
- Find Vp1 and Vp2 for R,=R2=100 k2
- Find R, and R2 for VD1=VD2
R1
VD1
Hint:
Is=L,+IRj= I,2+IR2
VD
R2
VD2
2. Draw the graph of the voltage across the 10K resistor (calculate the values for the different voltages across the 10K resistor) of the circuit in the figure, knowing that the voltage source V is sinusoidal. And the diodes are silicon
A diode circuit is given in the below figure, in which two diodes are connected in series
and their saturation currents are Is1 =10-¹6 A and Is2 =10-¹4 A. If the applied source voltage
is 1 V, calculate the currents IDI and ID2 and the voltage across each diode VDI and VD2.
IDI
Ī
Vpl
+
D₂
VD2
Chapter 4 Solutions
Microelectronic Circuits (The Oxford Series in Electrical and Computer Engineering) 7th edition
Ch. 4.1 - Prob. 4.1ECh. 4.1 - Prob. 4.2ECh. 4.1 - Prob. 4.3ECh. 4.1 - Prob. 4.4ECh. 4.1 - Prob. 4.5ECh. 4.2 - Prob. 4.6ECh. 4.2 - Prob. 4.7ECh. 4.2 - Prob. 4.8ECh. 4.2 - Prob. 4.9ECh. 4.3 - Prob. 4.10E
Ch. 4.3 - Prob. D4.11ECh. 4.3 - Prob. 4.12ECh. 4.3 - Prob. 4.13ECh. 4.3 - Prob. 4.14ECh. 4.3 - Prob. D4.15ECh. 4.4 - Prob. 4.16ECh. 4.4 - Prob. 4.17ECh. 4.4 - Prob. 4.18ECh. 4.5 - Prob. 4.19ECh. 4.5 - Prob. 4.20ECh. 4.5 - Prob. 4.21ECh. 4.5 - Prob. 4.22ECh. 4.5 - Prob. 4.23ECh. 4.5 - Prob. 4.24ECh. 4.5 - Prob. 4.25ECh. 4.6 - Prob. 4.26ECh. 4.6 - Prob. 4.27ECh. 4 - Prob. 4.1PCh. 4 - Prob. 4.2PCh. 4 - Prob. 4.3PCh. 4 - Prob. 4.4PCh. 4 - Prob. 4.5PCh. 4 - Prob. 4.6PCh. 4 - Prob. D4.7PCh. 4 - Prob. D4.8PCh. 4 - Prob. 4.9PCh. 4 - Prob. 4.10PCh. 4 - Prob. D4.11PCh. 4 - Prob. 4.12PCh. 4 - Prob. 4.13PCh. 4 - Prob. 4.14PCh. 4 - Prob. D4.15PCh. 4 - Prob. 4.16PCh. 4 - Prob. 4.17PCh. 4 - Prob. 4.18PCh. 4 - Prob. 4.19PCh. 4 - Prob. 4.20PCh. 4 - Prob. 4.21PCh. 4 - Prob. 4.22PCh. 4 - Prob. 4.23PCh. 4 - Prob. 4.24PCh. 4 - Prob. 4.25PCh. 4 - Prob. 4.26PCh. 4 - Prob. 4.27PCh. 4 - Prob. 4.28PCh. 4 - Prob. 4.29PCh. 4 - Prob. 4.30PCh. 4 - Prob. 4.31PCh. 4 - Prob. 4.32PCh. 4 - Prob. 4.33PCh. 4 - Prob. 4.34PCh. 4 - Prob. 4.35PCh. 4 - Prob. 4.36PCh. 4 - Prob. D4.37PCh. 4 - Prob. 4.38PCh. 4 - Prob. 4.39PCh. 4 - Prob. 4.40PCh. 4 - Prob. 4.41PCh. 4 - Prob. 4.42PCh. 4 - Prob. 4.43PCh. 4 - Prob. 4.44PCh. 4 - Prob. D4.45PCh. 4 - Prob. 4.46PCh. 4 - Prob. 4.47PCh. 4 - Prob. 4.48PCh. 4 - Prob. 4.49PCh. 4 - Prob. 4.50PCh. 4 - Prob. 4.51PCh. 4 - Prob. 4.52PCh. 4 - Prob. 4.53PCh. 4 - Prob. 4.54PCh. 4 - Prob. 4.55PCh. 4 - Prob. D4.56PCh. 4 - Prob. D4.57PCh. 4 - Prob. 4.58PCh. 4 - Prob. 4.59PCh. 4 - Prob. D4.60PCh. 4 - Prob. 4.61PCh. 4 - Prob. 4.62PCh. 4 - Prob. D4.63PCh. 4 - Prob. D4.64PCh. 4 - Prob. D4.65PCh. 4 - Prob. D4.66PCh. 4 - Prob. 4.67PCh. 4 - Prob. 4.68PCh. 4 - Prob. 4.69PCh. 4 - Prob. 4.70PCh. 4 - Prob. 4.71PCh. 4 - Prob. 4.72PCh. 4 - Prob. D4.73PCh. 4 - Prob. D4.74PCh. 4 - Prob. D4.75PCh. 4 - Prob. 4.76PCh. 4 - Prob. 4.77PCh. 4 - Prob. 4.78PCh. 4 - Prob. 4.79PCh. 4 - Prob. D4.80PCh. 4 - Prob. D4.81PCh. 4 - Prob. D4.82PCh. 4 - Prob. D4.83PCh. 4 - Prob. D4.84PCh. 4 - Prob. 4.85PCh. 4 - Prob. 4.86PCh. 4 - Prob. 4.87PCh. 4 - Prob. 4.88PCh. 4 - Prob. 4.89PCh. 4 - Prob. 4.90PCh. 4 - Prob. 4.91PCh. 4 - Prob. 4.92PCh. 4 - Prob. 4.93PCh. 4 - Prob. 4.94PCh. 4 - Prob. 4.95PCh. 4 - Prob. 4.96PCh. 4 - Prob. 4.97P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, electrical-engineering and related others by exploring similar questions and additional content below.Similar questions
- An ac voltage source with a peak value of 20 V LUK is a silicon doped diode and a 500 ohm resistor is connected in series in the circuit. The forward direction resistance of the resistor in D phase is 10 ohms. A) the highest current value through the diode B) Calculate the output voltage when the welding voltage is at its maximum level. C) If the diode is considered ideal, repeat steps a and b.arrow_forward4. For the circuit shown in the figure below uses a transformer of 230V/12V-0-12V and all diodes are Ge find the following, RL-3.3k2. The name of the circuit is ........ Current through the load is............The DC output voltage is............ Draw the input & output wave forms ✈ ellel eetee CT D₂ DE www R₂arrow_forwardA clipper circuit based on diodes are simple way to modify waveform in mechatronics. Assume that the two diodes shown in the circuit below are ideal diodes. If the input voltage in the circuit is a 1 kHz sinusoid with peak amplitude of 8V, sketch the Va.. (t) 10 kO 8V 10 kO Vin Vin(t) D2 Vout(t) RL Ims D1 6V -8V 4V Page | 1arrow_forward
- A circuit contains a diode in series with a 500 Ohm resistor. The diode is oriented to all current towards the positive side of the power source. Plot the theoretical I-V curve.arrow_forwardA single phase – half wave controlled rectifier with freewheeling diode is supplying a load consistingseries connected a resistor and an inductance from a 70.7V (RMS), 50Hz sinusoidal AC source.The firing delay of the thyristor is 90° and the load values are R=10Ω, L=0.1 H. Define the loadcurrent expression and draw the load current by calculating for first two periods. And calculate theaverage values of the load voltage and current.arrow_forwardA- If V, is a sinusoidal voltage with Vm = 40 V, and V= 15 V. Plot the waveform of the output voltage in each of the following clippers circuits assuming ideal diodes. B- Repeat part (A) if the diodes are silicon diodes. R R R (a) (b) (c) (d)arrow_forward
- Two ideal diodes are placed in series, pointing in opposite directions. What is the equivalent circuit for the combination? What is the equivalent circuit if the diodes are in parallel and pointing in opposite directions?arrow_forwardA clipper circuit based on diodes are simple way to modify waveform in mechatronics. Assume that the two diodes shown in the circuit below are ideal diodes. If the input voltage in the circuit is a 1 kHz sinusoid with peak amplitude of 8V, sketch the Vaue (t). 10 k. 8V 10 kN. D2 RL Vourlt) Vin= Vin(t) Ims D1 6V -8V 4V Page | 1arrow_forwardIn the circuit shown below, the ideality factorn of the diode is unity and the voltage drop across it is 0.7 V. The dynamic resistance of the diode at room temperature is approximately 1.7 V 31 k2arrow_forward
- In the circuit given in the figure, find the current passing through the diode in mA since R1 = 4.95Kohm, R2 = 2.50Kohm, R3 = 1.69Kohm, R4 = 5.44Kohm, VCC = 13.00V and the diode is silicon?arrow_forwardFor the circuit shown in figure 1, the diodes is in complete model and the resistance of both diodes are 5 Ohm. Find the current in the resistance RL. When the both switch S1 and switch S2 are ON. v1= 6V, V3 =3 Vv2=12 V.arrow_forwardA 3-phase full-wave bridge rectifier is built using six power diodes numbered 1 to 6. The phase sequence of the 3-phase source is ABC and the line to line voltage is 440 V. The line to neutral voltage of phase A has an angle of -30 degrees. The anodes of the diodes 1, 2, 3 are connected to phase A, B, and C, respectively, and the cathodes of diodes 1, 2, and 3 are connected to a common terminal that serves as the positive terminal of the rectifier's output. The cathodes of diodes 4, 5, and 6 are connected to phase A, B, and C, respectively, and the anodes of diodes 4, 5, and 6 are connected to a common terminal that serves as the negative terminal of the rectifier's output. If diode 1 is damaged and acts as an open circuit, what would the RMS voltage be at the load?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Introductory Circuit Analysis (13th Edition)Electrical EngineeringISBN:9780133923605Author:Robert L. BoylestadPublisher:PEARSONDelmar's Standard Textbook Of ElectricityElectrical EngineeringISBN:9781337900348Author:Stephen L. HermanPublisher:Cengage LearningProgrammable Logic ControllersElectrical EngineeringISBN:9780073373843Author:Frank D. PetruzellaPublisher:McGraw-Hill Education
- Fundamentals of Electric CircuitsElectrical EngineeringISBN:9780078028229Author:Charles K Alexander, Matthew SadikuPublisher:McGraw-Hill EducationElectric Circuits. (11th Edition)Electrical EngineeringISBN:9780134746968Author:James W. Nilsson, Susan RiedelPublisher:PEARSONEngineering ElectromagneticsElectrical EngineeringISBN:9780078028151Author:Hayt, William H. (william Hart), Jr, BUCK, John A.Publisher:Mcgraw-hill Education,
Introductory Circuit Analysis (13th Edition)
Electrical Engineering
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:PEARSON
Delmar's Standard Textbook Of Electricity
Electrical Engineering
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Cengage Learning
Programmable Logic Controllers
Electrical Engineering
ISBN:9780073373843
Author:Frank D. Petruzella
Publisher:McGraw-Hill Education
Fundamentals of Electric Circuits
Electrical Engineering
ISBN:9780078028229
Author:Charles K Alexander, Matthew Sadiku
Publisher:McGraw-Hill Education
Electric Circuits. (11th Edition)
Electrical Engineering
ISBN:9780134746968
Author:James W. Nilsson, Susan Riedel
Publisher:PEARSON
Engineering Electromagnetics
Electrical Engineering
ISBN:9780078028151
Author:Hayt, William H. (william Hart), Jr, BUCK, John A.
Publisher:Mcgraw-hill Education,
What is an electric furnace and how does it work?; Author: Fire & Ice Heating and Air Conditioning Inc;https://www.youtube.com/watch?v=wjAWecPGi0M;License: Standard Youtube License