COLLEGE PHYSICS
2nd Edition
ISBN: 9781464196393
Author: Freedman
Publisher: MAC HIGHER
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Question
Chapter 23, Problem 91QAP
To determine
(a)
The distance D in the given figure.
To determine
(b)
The distance D if the water is replaced by oil.
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•39 In Fig. 34-38, a beam of parallel light rays from a laser is in-
cident on a solid transparent sphere of index of refraction n. (a) If
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What index of refraction, if any, will
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•4 In Fig. 35-32a, a beam of light in material 1 is incident on a
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due to refraction depends, in part, on the index of refraction n, o
material 2. Figure 35-32b gives the angle of refraction Oz versus n
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is the speed of light in material 1?
в,
40°
300!
30°
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(b)
•• ENGINEERING APPLICATION An optical fiber allows rays
of light to propagate long distances by using total internal reflec-
tion. Optical fibers are used extensively in medicine and in digital
communications. As shown in Figure 31-58 the fiber consists of a
core material that has an index of refraction n, and radius b sur-
rounded by a cladding material that has an index of refraction
n3 < n2. The numerical aperture of the fiber is defined as sine,
where 0, is the angle of incidence of a ray of light that impinges
on the center of the end of the fiber and then reflects off the core-
cladding interface just at the critical angle. Using the figure as
a guide, show that the numerical aperture is given by
sine, = Vn3 - n? assuming the ray is initially in air. Hint: Use of the
Pythagorean theorem may be required.
44
Chapter 23 Solutions
COLLEGE PHYSICS
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- • The radius of the 10th dark ring in Newton's rings apparatus changes from 60 to 50 mm when a liquid is introduced between the lens and the plate. Calculate the refraction index of the liquid.arrow_forward•• Alight ray passes through a prism with an apex angle of a, as shown in Figure 31-62. The ray and the bisector of the apex angle intersect at right angles. Show that the angle of deviation & is related to the apex angle and the index of refraction of the prism material by sin {(a + 8)] = n sin(ta). 78arrow_forward•Explain what happens to the light ray at ech boundary: a plastic rectblock a mirrorarrow_forward
- Calculate the angle of refraction at the air/core interface. • nair = 1, ncore = 1.47, ncladding = 1.45, incident = 30oarrow_forward•48 In Fig. 33-48a, a light ray in water is incident at angle 61 on a boundary with an underlying material, into which some of the light refracts. There are two choices of underlying material. For each, the angle of refraction 6, versus the incident angle 6, is given in Fig. 33-48b. The vertical axis scale is set by 6, = 90°. %3D Without calculation, determine whether the index of refraction of (a) material 1 and (b) material 2 is greater or less than the index of water (n = 1.33). What is the index of refraction of (c) material 1 and (d) material 2? Ө, в2. Water 0° 45° 90° (a) (6)arrow_forward• Light is refracted as it travels from a point A in medium 1 to apoint B in medium 2. If the index of refraction is 1.33 in medium1 and 1.51 in medium 2, how much time does it take for light to gofrom A to B, assuming it travels 331 cm in medium 1 and 151 cm inmedium 2?arrow_forward
- •8 In Fig. 35-33, two light pulses are sent through layers of plastic Pulse п п with thicknesses of either L or 2L as shown and indexes of refraction Pulse n = 1.55, nz = 1.70, nz = 1.60, n4 = i 1.45, ng = 1.59, ng = 1.65, and n, = 1.50. (a) Which pulse travels through the plastic in less time? (b) What multiple of Lic gives the difference in the traversal times of the pulses? %3D Figure 35-33 Problem 8.arrow_forward•45 When the rectangular metal tank in Fig. 33-46 is filled to the top with an unknown liquid, observer o- O, with eyes level with the top of the tank, can just see corner E. A ray that refracts toward O at the top surface of the liquid is shown. If D = 85.0 cm and L = 1.10 m, what -Normal to liquid surface is the index of refraction of the liquid? -L-arrow_forward•48 An object is moved along the central axis of a thin lens while the lateral magnification m is measured. Figure 34-43 gives m ver- sus object distance p out to p, = 8.0 cm. What is the magnification of the object when the object is 14.0 cm from the lens? p (cm)arrow_forward
- • A beam of light strikes the plane surface of silicate flint glass at an angle of incidence of 45°. The index of refraction of the glass varies with wavelength (see Figure 31-59). How much smaller is the angle of refraction for violet light of wavelength 400 nm than the angle of refraction for red light of wavelength 700 nm? 49 11 1.7 Silicate flint glass 1.6 Borate flint glass Quartz Silicate crown glass 1.5 Violet Red 1.4 400 500 600 700 2, nmarrow_forwardInstructions: • For each item, show your complete solution and box your final answer with proper units. Questions: 1. What is the frequency of light that has a wavelength in water of 600 nm if the refractive index for this light is 1.33? 2. Light enters a glass plate whose index of refraction is 1.6 at an angle of incidence of 30°. What is the angle of refraction? 3. Light travelling in water (n = 1.33) strikes a glass plate at an angle of incidence of 53°; part of the beam is reflected and part is refracted. If the reflected and refracted portions makes an angle of 90° with each other, what is the index of refraction of the glass? 4. What is the critical angle for light passing from diamond to air if the index of refraction of diamond is 2.42? 5. A woman stands 2.0 m in front of a convex mirror and notices that her image height is 1/4 of her actual height. Determine the radius of curvature of the mirror.arrow_forward• The angle between the Sun and a rescue aircraft is 54°. Whatshould be the angle of incidence for sunlight on a plane mirror sothat the rescue pilot sees the reflected light?arrow_forward
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Laws of Refraction of Light | Don't Memorise; Author: Don't Memorise;https://www.youtube.com/watch?v=4l2thi5_84o;License: Standard YouTube License, CC-BY