COLLEGE PHYSICS
2nd Edition
ISBN: 9781464196393
Author: Freedman
Publisher: MAC HIGHER
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Chapter 23, Problem 35QAP
To determine
The ratio for light required for light to travel through 1000 m of air to the time required for light to travel through 1000 m of vacuum
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Light is an incident on a vertical interface between two mediums as shown in the picture. The medium on the left has an index of refraction n(left) & the medium on the right has an index of refraction n(right). The light comes from the bottom left.
If n(left)=1.3, n(right)=2.3, & angle of incidence = 41degrees. What is the angle of refraction?
-68.2
-49.0
-0
-41.0
-21.8
If n(left)=1.3, n(right)=2.3, & angle of incidence= 41degrees, what is the angle of reflection?
*same choices as first question*
•48 In Fig. 33-48a, a light ray in water is incident at angle 61 on a
boundary with an underlying material, into which some of the
light refracts. There are two choices of underlying material. For
each, the angle of refraction 6, versus the incident angle 6, is
given in Fig. 33-48b. The vertical axis scale is set by 6, = 90°.
%3D
Without calculation, determine whether the index of refraction of
(a) material 1 and (b) material 2 is greater or less than the index
of water (n = 1.33). What is the index of refraction of (c) material
1 and (d) material 2?
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в2.
Water
0°
45°
90°
(a)
(6)
Physics v
Q21
A convex lens made of glass, with
refractive index (), is placed in a
medium of refractive index . A parallel
beam of light entering the lens
diverges
converges
undergoes no refraction
comes out as a parallel beam by itself.
Physics
Chapter 23 Solutions
COLLEGE PHYSICS
Ch. 23 - Prob. 1QAPCh. 23 - Prob. 2QAPCh. 23 - Prob. 3QAPCh. 23 - Prob. 4QAPCh. 23 - Prob. 5QAPCh. 23 - Prob. 6QAPCh. 23 - Prob. 7QAPCh. 23 - Prob. 8QAPCh. 23 - Prob. 9QAPCh. 23 - Prob. 10QAP
Ch. 23 - Prob. 11QAPCh. 23 - Prob. 12QAPCh. 23 - Prob. 13QAPCh. 23 - Prob. 14QAPCh. 23 - Prob. 15QAPCh. 23 - Prob. 16QAPCh. 23 - Prob. 17QAPCh. 23 - Prob. 18QAPCh. 23 - Prob. 19QAPCh. 23 - Prob. 20QAPCh. 23 - Prob. 21QAPCh. 23 - Prob. 22QAPCh. 23 - Prob. 23QAPCh. 23 - Prob. 24QAPCh. 23 - Prob. 25QAPCh. 23 - Prob. 26QAPCh. 23 - Prob. 27QAPCh. 23 - Prob. 28QAPCh. 23 - Prob. 29QAPCh. 23 - Prob. 30QAPCh. 23 - Prob. 31QAPCh. 23 - Prob. 32QAPCh. 23 - Prob. 33QAPCh. 23 - Prob. 34QAPCh. 23 - Prob. 35QAPCh. 23 - Prob. 36QAPCh. 23 - Prob. 37QAPCh. 23 - Prob. 38QAPCh. 23 - Prob. 39QAPCh. 23 - Prob. 40QAPCh. 23 - Prob. 41QAPCh. 23 - Prob. 42QAPCh. 23 - Prob. 43QAPCh. 23 - Prob. 44QAPCh. 23 - Prob. 45QAPCh. 23 - Prob. 46QAPCh. 23 - Prob. 47QAPCh. 23 - Prob. 48QAPCh. 23 - Prob. 49QAPCh. 23 - Prob. 50QAPCh. 23 - Prob. 51QAPCh. 23 - Prob. 52QAPCh. 23 - Prob. 53QAPCh. 23 - Prob. 54QAPCh. 23 - Prob. 55QAPCh. 23 - Prob. 56QAPCh. 23 - Prob. 57QAPCh. 23 - Prob. 58QAPCh. 23 - Prob. 59QAPCh. 23 - Prob. 60QAPCh. 23 - Prob. 61QAPCh. 23 - Prob. 62QAPCh. 23 - Prob. 63QAPCh. 23 - Prob. 64QAPCh. 23 - Prob. 65QAPCh. 23 - Prob. 66QAPCh. 23 - Prob. 67QAPCh. 23 - Prob. 68QAPCh. 23 - Prob. 69QAPCh. 23 - Prob. 70QAPCh. 23 - Prob. 71QAPCh. 23 - Prob. 72QAPCh. 23 - Prob. 73QAPCh. 23 - Prob. 74QAPCh. 23 - Prob. 75QAPCh. 23 - Prob. 76QAPCh. 23 - Prob. 77QAPCh. 23 - Prob. 78QAPCh. 23 - Prob. 79QAPCh. 23 - Prob. 80QAPCh. 23 - Prob. 81QAPCh. 23 - Prob. 82QAPCh. 23 - Prob. 83QAPCh. 23 - Prob. 84QAPCh. 23 - Prob. 85QAPCh. 23 - Prob. 86QAPCh. 23 - Prob. 87QAPCh. 23 - Prob. 88QAPCh. 23 - Prob. 89QAPCh. 23 - Prob. 90QAPCh. 23 - Prob. 91QAPCh. 23 - Prob. 92QAPCh. 23 - Prob. 93QAPCh. 23 - Prob. 94QAPCh. 23 - Prob. 95QAPCh. 23 - Prob. 96QAPCh. 23 - Prob. 97QAPCh. 23 - Prob. 98QAPCh. 23 - Prob. 99QAPCh. 23 - Prob. 100QAPCh. 23 - Prob. 101QAPCh. 23 - Prob. 102QAPCh. 23 - Prob. 103QAPCh. 23 - Prob. 104QAPCh. 23 - Prob. 105QAPCh. 23 - Prob. 106QAPCh. 23 - Prob. 107QAPCh. 23 - Prob. 108QAPCh. 23 - Prob. 109QAPCh. 23 - Prob. 110QAPCh. 23 - Prob. 111QAPCh. 23 - Prob. 112QAPCh. 23 - Prob. 113QAPCh. 23 - Prob. 114QAP
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- •39 In Fig. 34-38, a beam of parallel light rays from a laser is in- cident on a solid transparent sphere of index of refraction n. (a) If a point image is produced at the back of the sphere, what is the index of refraction of the sphere? (b) What index of refraction, if any, will produce a point image at the center of the sphere?arrow_forwardThis question is about refraction and total internal reflection. (a) Light travels from one optical medium to another. State the conditions necessary for total internal reflection to occur at the boundary between the two media. (b) Light is incident on a small scratch in the surface of an optical fibre of refractive index 1.5. The angle between a ray of incident light and the surface of the scratch is 68 as shown below. 68 optic fibre refractive index 1.5 (i) Calculate the angle of refraction of the ray at the surface of the scratch.arrow_forward• A glass surface (n 1.50) has a layer of water (n = 1.33) on it. Light in the glass is incident on the glass-water interface. Find the critical angle for total internal reflection. 40arrow_forward
- Example 5: A narrow light beam in vacuum contains light of two wavelengths, 480 nm and 700 nm. It strikes a flat piece of glass at an angle of incidence of 60.000°. The index of refraction of the glass is 1.4830 at 480 nm and 1.4760 at 700 nm. Determine the angle between the two wavelengths as the light travels in the glass.arrow_forwardWe know that the index of refraction of materials can help identify those materials. A light beam is shined onto a surface a reflected ray and is found to be completely polarized when the angle of incidence is 53.5°.(a) What is the index of refraction of the reflecting material? (b) What is the angle of refraction if some light passes through the surface of the material?°arrow_forward•4 In Fig. 35-32a, a beam of light in material 1 is incident on a boundary at an angle of 30°. The extent to which the light is ben due to refraction depends, in part, on the index of refraction n, o material 2. Figure 35-32b gives the angle of refraction Oz versus n for a range of possible n2 values, from n, = 1.30 to n, = 1.90. Wha is the speed of light in material 1? в, 40° 300! 30° в, 20° по (a) (b)arrow_forward
- If a ray of light enters the prism hypotenuse-face at 0° incident angle, then the minimum index of refraction of the prism for which the ray totally internally reflects at each of the two sides making the right angle will be given by: air ( 45° n = ? 450 .----- n = 1.326 n = 1.351 n = 1.414 n = 1.273 O n= 1.150arrow_forward•• ENGINEERING APPLICATION An optical fiber allows rays of light to propagate long distances by using total internal reflec- tion. Optical fibers are used extensively in medicine and in digital communications. As shown in Figure 31-58 the fiber consists of a core material that has an index of refraction n, and radius b sur- rounded by a cladding material that has an index of refraction n3 < n2. The numerical aperture of the fiber is defined as sine, where 0, is the angle of incidence of a ray of light that impinges on the center of the end of the fiber and then reflects off the core- cladding interface just at the critical angle. Using the figure as a guide, show that the numerical aperture is given by sine, = Vn3 - n? assuming the ray is initially in air. Hint: Use of the Pythagorean theorem may be required. 44arrow_forward33.37 • BIO Heart Sonogram. Physicians use high-frequency (f = 1–5 MHz) sound waves, called ultrasound, to image internal or- gans. The speed of these ultrasound waves is 1480 m/s in muscle and 344 m/s in air. We define the index of refraction of a material for sound waves to be the ratio of the speed of sound in air to the speed of sound in the material. Snell's law then applies to the refraction of sound waves. (a) At what angle from the normal does an ultrasound beam enter the heart if it leaves the lungs at an angle of 9.73° from the normal to the heart wall? (Assume that the speed of sound in the lungs is 344 m/s.) (b) What is the critical angle for sound waves in air incident on muscle?arrow_forward
- A) What is the Speed of light in glass when the index of refraction for glass is 1.52 ? B) Speed of light in sulphuric acid at room temperature is 2.11 x 10° m/s What is the index of refraction for sulphuric acid ? C) A light Ray travels from water (n,=1.33) to air (n, - 1.00). If the angle of refraction is 56° then What is the angle of incidence ?arrow_forwardEstablish the relevant theoretical model:- Write a first general equation giving the angle of refraction (r) as a function of the angle of incidence (i) on a rectangular piece of acrylic and the refractive index (n) of the acrylic.- Write down a second general equation giving the lateral deviation (d)of an incident beam as a function of the angle of incidence (i), the angle of refraction (r) and the thickness (e) of the rectangular piece of acrylic. Note that there are two ways of calculating &, which give two mathematically equivalent equations.Using the relationships you've just obtained, calculate the lateral deviation for the following fictitious situation: angle of incidence i = 45°, acrylic refractive index = 1.49 +- 0.01 and blade thickness e = 6.5 cm.arrow_forward92 In about A.D. 150, Claudius Ptolemy gave the following meas- ured values for the angle of incidence 0, and the angle of refraction 8, for a light beam passing from air to water: 02 10° 8° 50° 35° 20° 15°30' 60° 40°30' 30° 22°30' 70° 45°30' 40° 29° 80° 50° Assuming these data are consistent with the law of refraction, use them to find the index of refraction of water. These data are inter- esting as perhaps the oldest recorded physical measurements.arrow_forward
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