COLLEGE PHYSICS
2nd Edition
ISBN: 9781464196393
Author: Freedman
Publisher: MAC HIGHER
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Question
Chapter 23, Problem 3QAP
To determine
Does the depth of a pool determine the critical angle that a light ray will have as it travels from the bottom of the pool and heads toward the air above the water?
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
• A glass surface (n 1.50) has a layer of water
(n = 1.33) on it. Light in the glass is incident on the glass-water
interface. Find the critical angle for total internal reflection.
40
Light is an incident on a vertical interface between two mediums as shown in the picture. The medium on the left has an index of refraction n(left) & the medium on the right has an index of refraction n(right). The light comes from the bottom left.
If n(left)=1.3, n(right)=2.3, & angle of incidence = 41degrees. What is the angle of refraction?
-68.2
-49.0
-0
-41.0
-21.8
If n(left)=1.3, n(right)=2.3, & angle of incidence= 41degrees, what is the angle of reflection?
*same choices as first question*
If a ray of light enters the prism
hypotenuse-face at 0° incident angle,
then the minimum index of refraction
of the prism for which the ray totally
internally reflects at each of the two
sides making the right angle will be
given by:
air
( 45°
n = ?
450
.-----
n = 1.326
n = 1.351
n = 1.414
n = 1.273
O n= 1.150
Chapter 23 Solutions
COLLEGE PHYSICS
Ch. 23 - Prob. 1QAPCh. 23 - Prob. 2QAPCh. 23 - Prob. 3QAPCh. 23 - Prob. 4QAPCh. 23 - Prob. 5QAPCh. 23 - Prob. 6QAPCh. 23 - Prob. 7QAPCh. 23 - Prob. 8QAPCh. 23 - Prob. 9QAPCh. 23 - Prob. 10QAP
Ch. 23 - Prob. 11QAPCh. 23 - Prob. 12QAPCh. 23 - Prob. 13QAPCh. 23 - Prob. 14QAPCh. 23 - Prob. 15QAPCh. 23 - Prob. 16QAPCh. 23 - Prob. 17QAPCh. 23 - Prob. 18QAPCh. 23 - Prob. 19QAPCh. 23 - Prob. 20QAPCh. 23 - Prob. 21QAPCh. 23 - Prob. 22QAPCh. 23 - Prob. 23QAPCh. 23 - Prob. 24QAPCh. 23 - Prob. 25QAPCh. 23 - Prob. 26QAPCh. 23 - Prob. 27QAPCh. 23 - Prob. 28QAPCh. 23 - Prob. 29QAPCh. 23 - Prob. 30QAPCh. 23 - Prob. 31QAPCh. 23 - Prob. 32QAPCh. 23 - Prob. 33QAPCh. 23 - Prob. 34QAPCh. 23 - Prob. 35QAPCh. 23 - Prob. 36QAPCh. 23 - Prob. 37QAPCh. 23 - Prob. 38QAPCh. 23 - Prob. 39QAPCh. 23 - Prob. 40QAPCh. 23 - Prob. 41QAPCh. 23 - Prob. 42QAPCh. 23 - Prob. 43QAPCh. 23 - Prob. 44QAPCh. 23 - Prob. 45QAPCh. 23 - Prob. 46QAPCh. 23 - Prob. 47QAPCh. 23 - Prob. 48QAPCh. 23 - Prob. 49QAPCh. 23 - Prob. 50QAPCh. 23 - Prob. 51QAPCh. 23 - Prob. 52QAPCh. 23 - Prob. 53QAPCh. 23 - Prob. 54QAPCh. 23 - Prob. 55QAPCh. 23 - Prob. 56QAPCh. 23 - Prob. 57QAPCh. 23 - Prob. 58QAPCh. 23 - Prob. 59QAPCh. 23 - Prob. 60QAPCh. 23 - Prob. 61QAPCh. 23 - Prob. 62QAPCh. 23 - Prob. 63QAPCh. 23 - Prob. 64QAPCh. 23 - Prob. 65QAPCh. 23 - Prob. 66QAPCh. 23 - Prob. 67QAPCh. 23 - Prob. 68QAPCh. 23 - Prob. 69QAPCh. 23 - Prob. 70QAPCh. 23 - Prob. 71QAPCh. 23 - Prob. 72QAPCh. 23 - Prob. 73QAPCh. 23 - Prob. 74QAPCh. 23 - Prob. 75QAPCh. 23 - Prob. 76QAPCh. 23 - Prob. 77QAPCh. 23 - Prob. 78QAPCh. 23 - Prob. 79QAPCh. 23 - Prob. 80QAPCh. 23 - Prob. 81QAPCh. 23 - Prob. 82QAPCh. 23 - Prob. 83QAPCh. 23 - Prob. 84QAPCh. 23 - Prob. 85QAPCh. 23 - Prob. 86QAPCh. 23 - Prob. 87QAPCh. 23 - Prob. 88QAPCh. 23 - Prob. 89QAPCh. 23 - Prob. 90QAPCh. 23 - Prob. 91QAPCh. 23 - Prob. 92QAPCh. 23 - Prob. 93QAPCh. 23 - Prob. 94QAPCh. 23 - Prob. 95QAPCh. 23 - Prob. 96QAPCh. 23 - Prob. 97QAPCh. 23 - Prob. 98QAPCh. 23 - Prob. 99QAPCh. 23 - Prob. 100QAPCh. 23 - Prob. 101QAPCh. 23 - Prob. 102QAPCh. 23 - Prob. 103QAPCh. 23 - Prob. 104QAPCh. 23 - Prob. 105QAPCh. 23 - Prob. 106QAPCh. 23 - Prob. 107QAPCh. 23 - Prob. 108QAPCh. 23 - Prob. 109QAPCh. 23 - Prob. 110QAPCh. 23 - Prob. 111QAPCh. 23 - Prob. 112QAPCh. 23 - Prob. 113QAPCh. 23 - Prob. 114QAP
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- 1) A light ray incoming from air hits a glass surface. Incident angle and refraction angle is calculated at the table below. a)Find the index of refraction of the medium for 3 different angles Incoming Refracted index N/A 30 8.7 45 12.2 60 15.3 b) Plot sin(theta1) vs sin(theta2) and obtain best fit line. What does the numeric value of the slope corresponds to in Snell's Law equation.arrow_forward•48 In Fig. 33-48a, a light ray in water is incident at angle 61 on a boundary with an underlying material, into which some of the light refracts. There are two choices of underlying material. For each, the angle of refraction 6, versus the incident angle 6, is given in Fig. 33-48b. The vertical axis scale is set by 6, = 90°. %3D Without calculation, determine whether the index of refraction of (a) material 1 and (b) material 2 is greater or less than the index of water (n = 1.33). What is the index of refraction of (c) material 1 and (d) material 2? Ө, в2. Water 0° 45° 90° (a) (6)arrow_forwardMY NOTES ASK YOUR TEACHER Using filters, a technician has created a beam of light consisting of three wavelengths: 400 nm (violet), 500 nm (green), and 650 nm (red). He aims the beam so that it passes through air and then enters a block of crown glass. The beam enters the glass at an incidence angle of ?1 = 46.1°. The glass block has the following indices of refraction for the respective wavelengths in the light beam. wavelength (nm) 400 500 650 index of refraction n400 nm = 1.53 n500 nm = 1.52 n650 nm = 1.51 (a) Upon entering the glass, are all three wavelengths refracted equally, or is one bent more than the others? 400 nm light is bent the most 500 nm light is bent the most 650 nm light is bent the most all colors are refracted alike (b) What are the respective angles of refraction (in degrees) for the three wavelengths? (Enter each value to at least two decimal places.) (i) ?400 nm ° (ii) ?500 nm ° (iii) ?650 nm °arrow_forward
- Reflection and Refraction (The Nature and Propagation of Light) The critical angle for total internal reflection at a liquid- air interface is 42.5 degrees. A) If a ray of light travelling in the liquid has an angle of incidence at the interface of 35 degrees, what angle does the refracted ray in the air make with the normal? b) If a ray of light travelling in air has an angle of incidence at the interface of what angle does the refracted way in the liquid make with the normal?arrow_forward• During a daytime football game you notice that a player’s reflective helmet forms an image of the Sun 4.8 cm behind the surface ofthe helmet. What is the radius of curvature of the helmet, assuming it to be roughly spherical?arrow_forwardWe know that the index of refraction of materials can help identify those materials. A light beam is shined onto a surface a reflected ray and is found to be completely polarized when the angle of incidence is 53.5°.(a) What is the index of refraction of the reflecting material? (b) What is the angle of refraction if some light passes through the surface of the material?°arrow_forward
- A) What is the Speed of light in glass when the index of refraction for glass is 1.52 ? B) Speed of light in sulphuric acid at room temperature is 2.11 x 10° m/s What is the index of refraction for sulphuric acid ? C) A light Ray travels from water (n,=1.33) to air (n, - 1.00). If the angle of refraction is 56° then What is the angle of incidence ?arrow_forward•39 In Fig. 34-38, a beam of parallel light rays from a laser is in- cident on a solid transparent sphere of index of refraction n. (a) If a point image is produced at the back of the sphere, what is the index of refraction of the sphere? (b) What index of refraction, if any, will produce a point image at the center of the sphere?arrow_forwardEstablish the relevant theoretical model:- Write a first general equation giving the angle of refraction (r) as a function of the angle of incidence (i) on a rectangular piece of acrylic and the refractive index (n) of the acrylic.- Write down a second general equation giving the lateral deviation (d)of an incident beam as a function of the angle of incidence (i), the angle of refraction (r) and the thickness (e) of the rectangular piece of acrylic. Note that there are two ways of calculating &, which give two mathematically equivalent equations.Using the relationships you've just obtained, calculate the lateral deviation for the following fictitious situation: angle of incidence i = 45°, acrylic refractive index = 1.49 +- 0.01 and blade thickness e = 6.5 cm.arrow_forward
- • The angle between the Sun and a rescue aircraft is 54°. Whatshould be the angle of incidence for sunlight on a plane mirror sothat the rescue pilot sees the reflected light?arrow_forwardA ray of light impinges from air onto a block of ice (n = 1.309) at a 50.0° angle of incidence. Assuming that this angle 02. water in the angles of refraction when the ice turns to water (n = 1.333). remains the same, find the difference 0, ice - 02, ice - 02, water = Additional Materials eBook h (Unite 398 1,373 APR 21 tv MacBook Air 80 DII esc F1 F2 F3 F4 F5 F6 F7 F8 * 23 24 & 1 3 4 6. 8. Q W E R. T Yarrow_forwardExample (2): Light traveling through a bowl of water (n-1.33) to the glass (n=1.5), if the angle of incidence is (30), what is the angle of refraction, what happen if the light incident from the giass into water with the same incident angle?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
University Physics Volume 3PhysicsISBN:9781938168185Author:William Moebs, Jeff SannyPublisher:OpenStax
University Physics Volume 3
Physics
ISBN:9781938168185
Author:William Moebs, Jeff Sanny
Publisher:OpenStax
Convex and Concave Lenses; Author: Manocha Academy;https://www.youtube.com/watch?v=CJ6aB5ULqa0;License: Standard YouTube License, CC-BY