Chapter U3, Problem 1RE

Interpretation Introduction

Interpretation: The substance which has a greater mass from liquid water and ice needs to be determined.

Concept Introduction:

The density of a substance is related to mass and volume as follows:

  $d=\frac{m}{V}$

Here, m is mass and V is volume.

Answer to Problem 1RE

Mass of liquid water is greater than ice.

Explanation of Solution

The volume of both liquid water and ice is 500 mL. The density of ice is 0.92 g/mL and that of water is 1 g/mL.

Since,

  $d=\frac{m}{V}$

Thus, at constant volume, density is directly proportional to mass.

  $d\propto m$

Since, density of water is more than that of ice thus, mass of liquid water should be greater than ice.

The mass of water and ice can be calculated as follows:

  $m=d\times V$

Thus,

  $m_{\text{liquid water}}=\left(1\text{ g/mL}\right)\left(50\text{0 mL}\right)=500\text{ g}$

Similarly,

  $m_{\text{ice}}=\left(\text{0}\text{.92 g/mL}\right)\left(50\text{0 mL}\right)=460\text{ g}$

Conclusion

Thus, the mass of liquid water is greater than ice.