Chapter SH, Problem 21.7APP

To determine

To calculate: Maximum amount of potassium bromide that will dissolve in the given amount of water.

Answer to Problem 21.7APP

The amount of potassium bromide that will dissolve in $\text{237 mL}$ of water is $\underset{\_}{\text{154}\text{.76 g}}$ .

Explanation of Solution

Given:

Solubility of potassium bromide in water = $65.3\text{ g/100 mL}$

Amount of water = $\text{237 mL}$

Calculation:

  $\text{100 mL}$ of water dissolves $65.3\text{ g}$ of potassium bromide.

  $\text{1 mL}$ of water dissolves $\frac{65.3\text{ g}}{100\text{ mL}}$ of potassium bromide.

  $\text{237 mL}$ of water dissolves $\frac{65.3\text{ g}}{100\text{ mL}}\times 237\text{ mL = 154}\text{.76 g}$ of potassium bromide.

Conclusion:

The amount of potassium bromide that will dissolve in $\text{237 mL}$ of water is $\underset{\_}{\text{154}\text{.76 g}}$ .