Chapter SH, Problem 19.3APP

To determine

To calculate: Mass of ${\text{H}}_2\text{O}$ formed.

Answer to Problem 19.3APP

Mass of ${\text{H}}_2\text{O}$ formed is 54 g .

Explanation of Solution

Given:

The following reaction:

  $2\text{Al}{\left(\text{OH}\right)}_3\to {\text{Al}}_2{\text{O}}_3+3{\text{H}}_2\text{O}$

Mass of $\text{Al}{\left(\text{OH}\right)}_3$ = $\text{156}\text{.0 g}$

Mass of ${\text{Al}}_2{\text{O}}_3$ = $\text{102}\text{.0 g}$

Formula used:

According to law of conservation of mass,

Total mass of reactants = Total mass of products

Calculation:

  $\begin{array}{l}\text{Mass of}\text{Al}{\left(\text{OH}\right)}_3{\text{= Mass of Al}}_2{\text{O}}_3{\text{+ Mass of H}}_{\text{2}}\text{O}\\ {\text{Mass of H}}_{\text{2}}\text{O = Mass of}\text{Al}{\left(\text{OH}\right)}_3-{\text{ Mass of Al}}_2{\text{O}}_3\\ {\text{Mass of H}}_{\text{2}}\text{O}=156\text{ g}-102\text{ g}\\ {\text{Mass of H}}_{\text{2}}\text{O}=\text{ 54 g}\end{array}$

Conclusion:

Mass of ${\text{H}}_2\text{O}$ formed is 54 g.