Chapter SH, Problem 15.7APP

To determine

To calculate: Mass of ${\text{CO}}_{\text{2}}$ produced.

Answer to Problem 15.7APP

Mass of ${\text{CO}}_{\text{2}}$ produced is $\underset{\_}{\text{110 g}}$ .

Explanation of Solution

Given:

The following reaction:

  ${\text{CaCO}}_3\to \text{CaO}+{\text{CO}}_{\text{2}}$

Mass of ${\text{CaCO}}_3$ = $250\text{ g}$

Percentage of $\text{CaO}$ = $56\%$

Calculation:

According to law of conservation of mass,

Total mass of reactants = Total mass of products

Therefore, total mass of products = $250\text{ g}$

Since amount $\text{CaO}$ is $56\%$ of mass of the products, amount of ${\text{CO}}_{\text{2}}$ is $100-56=44\%$

Mass of ${\text{CO}}_{\text{2}}$ is calculated as:

  $\begin{array}{l}44\%\text{ of 250 g}\\ \text{=}\frac{44}{100}\times 250\text{ g}\\ \text{=110 g}\end{array}$

Conclusion:

Mass of ${\text{CO}}_{\text{2}}$ produced is $\underset{\_}{\text{110 g}}$ .