Chapter SH, Problem 17.6APP

To determine

To calculate:The mass of goldoreto be mined to produce an ounce of gold.

Answer to Problem 17.6APP

  $5,660\text{ kg}$ of ore needs to be mined to produce one ounce of gold.

Explanation of Solution

Given data:

Mass of gold produced by $\text{1,000 kg}$ of gold ore $\text{=5 g}$

  $\text{1}$ ounce $\text{=28}\text{.3 g }$

Calculation:

As per the problem,

Mass of gold produced by $\text{1,000 kg}$ of gold ore $\text{=5 g}$

Or, mass of gold ore that produces $\text{5 g}$ of gold $\text{=1,000 kg}$

So, mass of gold ore that produces $\text{1 g}$ of gold $\text{=}\frac{\text{1,000 kg}}{5\text{ g}}$

Therefore,

Mass of gold ore that will produce $\text{1}$ ounce of gold

  $\begin{array}{l}\text{=}\frac{\text{1,000 kg}}{5\text{ g}}\times 1\text{ ounce}\\ \text{=}\frac{\text{1,000 kg}}{5\text{ g}}\times 28.3\text{ g [1 ounce}=28.3\text{ g]}\\ \text{=5660 kg}\end{array}$

Conclusion:

  $5,660\text{ kg}$ of ore needs to be mined to produce one ounce of gold.