Chapter SH, Problem 19.10APP

To determine

To calculate: The rate by which the reaction is faster in the presence of the enzyme.

Answer to Problem 19.10APP

The rate of reaction with the catalyst is 26 times faster than the rate of reaction without the catalyst.

Explanation of Solution

Given:

Without a catalyst:

A reaction produces $0.050\text{ g}$ of a product in $\text{0}\text{.18 s}$ .

With a catalyst:

The reaction produces $0.050\text{ g}$ of the same product in $\text{0}\text{.0070 s}$ .

Formula used:

Rate of change is,

  $R=\frac{\text{mass}}{\text{time}}$

Calculation:

Rate at which reactant changes into product without the catalyst:

  $\frac{0.050\text{ g}}{\text{0}\text{.18 s}}=0.27\text{ g/s}$

Rate at which reactant changes into product with the catalyst:

  $\frac{0.050\text{ g}}{\text{0}\text{.0070 s}}=7.14\text{ g/s}$

The rate of reaction with the catalyst is faster than the rate of reaction without the catalyst by:

  $\frac{7.14\text{ g/s}}{0.27\text{ g/s}}=26\text{ times}$

Conclusion:

The rate of reaction with the catalyst is 26 times faster than the rate of reaction without the catalyst.