Genetic Analysis: An Integrated Approach (3rd Edition)
3rd Edition
ISBN: 9780134605173
Author: Mark F. Sanders, John L. Bowman
Publisher: PEARSON
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Chapter E, Problem 8P
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Consider the first category of test-cross offspring shown in figure 8.2 (+b, LS). Consider also that the parents of the heterozygous female flies in the test cross had the following genotypes: bb, SS, and +, LL.
A. What would be the physical phenotype of these flies?
B. If PC was conducted with the DNA of one of these flies using the primers for the molecular marker, what would be the appearance of the bands on an electrophoresis gel with the PC products?
C. If the gene for black body and the locus for the molecular marker (L long or S short) were unlinked, what proportion of the test-cross progeny would be black flies that are heterozygous for the molecular marker? What proportion would be flies with normal body color, which are homozygous for one form of the molecular marker?
D. If the gene for black body and the locus for the molecular marker were linked, how would the proportion of flies be different?
The DNA of every individual in the pedigree shown in image B (below) has been sequenced at the causative locus, all the non-shaded individuals are wild type apart from III.1 and III.6. III.1 and III.6 have both been proven to have the causative allele for the condition but they do not exhibit any of the phenotypic signs or symptoms. Based on this pedigree, what is the level of penetrance for the condition? Please give your answer as a percentage to one decimal place, give the number only, no percentage symbol.
Given the information above I calculate the level of penetrance seen in image B to be "Blank" 1 percent.
The figure below represents a two-generation pedigree representing the inheritance of hereditary deafness (HD), which, has been shown to be autosomal recessive. Below the pedigree (and aligned with each person in each generation) are Southern blot gels for two RFLP loci. The BamH1 RFLP locus has alleles of either 7 kb or 5 kb and the EcoRI RFLP locus gives either a 4 kb or 3 kb EcoRI fragment.
a. Determine if HD is linked to either of these markers.
b. If linkage is detected between HD and one of the RFLPs, are there any recombinant offspring that you can detect?
c. If linkage is detected between HD and one of the RFLPs, what is the approximate map distance between the two? Do you think that this distance will efficiently and effectively allow the RFLP to track the HD gene?
Chapter E Solutions
Genetic Analysis: An Integrated Approach (3rd Edition)
Ch. E - E.1 What is CODIS? Describe the four most...Ch. E - Compare and constast the terms paternity index...Ch. E - What is exclusion principle? How is it used in...Ch. E - What is the statistical principle underlying...Ch. E - Explain the meaning of identity by descent in the...Ch. E - Prob. 6PCh. E - E.7 The results shown are from a DNA test for four...Ch. E - E.8 Figure illustrates the results of an...Ch. E - E.9 Additional STR allele frequency information...Ch. E - Prob. 10P
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- The DNA of every individual in the pedigree shown in image B (below) has been sequenced at the causative locus, all the non- shaded individuals are wild type apart from III.1 and III.6. III.1 and III.6 have both been proven to have the causative allele for the condition but they do not exhibit any of the phenotypic signs or symptoms. Based on this pedigree, what is the level of penetrance for the condition? Please give your answer as a percentage to one decimal place, give the number only, no percentage symbol. ANSWER: Given the information above I calculate the level of penetrance seen in image B to be Blank 1 percent. A KEY Homozygous Homozygous Heterozygous Heterozygous Wild Type Male Female Male Female Male Note: Completely red symbol denotes an individual exhibiting the phenotype of interest CI || III IV V 1/4 1/2 1/2 1/2 1/2 Wild Type Female 1/4 1/2 Affected Known carrier Affected female Normal female Affected male Normal male D ●●●arrow_forwardConsider a maize plant: Genotype C/cm ; Ac/Ac+ where cm is an unstable colorless allele caused by Ds insertion. What phenotypic ratios would be produced and in what proportions when this plant is crossed with a mutant c/c Ac+/Ac+? Assume that the Ac and c loci are unlinked, that the chromosome-breakage frequency is negligible, and the C allele encodes pigment production.arrow_forwardUsing figure 1 and the following background information answer the following questions. Identification of the genetic cause of hornlessness in cattle has been the subject of intensive genetic and genomic research, culminating in the nomination of two different candidate neomutations on cattle chromosome 1 that are predicted to have arisen 500-1,000 years ago: a complex allele of Friesian origin (PF), an 80,128 base pair (bp) duplication (1909352–1989480 bp), and a second, simple allele of Celtic origin (PC) corresponding to a duplication of 212 bp (chromosome 1 positions 1705834–1706045) in place of a 10-bp deletion (1706051–1706060)We report the use of genome editing using transcription activator-like effector nucleases (TALENs) to introgress the putative PC POLLED allele into the genome of bovine embryo fibroblasts to try and produce a genotype identical to what is achievable using natural mating, but without the attendant genetic drag and admixture. In our previous studies, we…arrow_forward
- A RFLP is discovered that is linked to the gene for Duchenne’s muscular dystrophy (DMD). DMD is an X-linked, recessive trait. The RFLP is 2 map units from the gene for DMD. Consider the following pedigree and Southern blot using a probe that hybridizes to the RFLP. Which band/s is/are associated with DMD? What is the genotype for individuals 3 and 4? (Remember, this is an X linked disease, so use X’s and Y’s to denote). Individual 9 married a man who does NOT have muscular dystrophy, and she is pregnant. DMD is an X-linked trait. What is the probability for their child to have DMD? An amniocentesis is performed and it is determined that 9’s child in utero has only a 10 kb band that hybridizes to the same probe used above. What can you say about the child now?arrow_forwardThe data set attached presents the results of a testcross using female flies heterozygous for three traits and male flies, which are homozygous recessive. For simplicity, mutant alleles are shown with letters a, b, and c and wildtype alleles are indicated by a “+” symbol. For this part of the report do the following in order: a) Determine the gene order (which gene is in the middle?)d) Construct a genetic map for the three genes, including the map distances between them. Clearly indicate the logic you followed and show all your calculations. Include the full distance calculations for the two most distanced genes (do not just add the other 2 distances). Ensure the work is neat and clear and does not contain spelling or grammatical errors so that it is understandable. Make sure to double check the solution provided.arrow_forwardAn experimental assay for the blood-clotting protein called factorIX is available. A blood sample was obtained from each individual in the following pedigree. The amount of factor IX protein, shown within each symbol on the pedigree, is expressed as a percentage of the average amount observed in individuals who do not carry a mutant copy of the gene.arrow_forward
- You would like to isolate loci in the genome that influence plant height in tomato plants. Describe how you would achieve this through QTL mapping. Choose a true breeding tall strain and a true breeding short strain and compare the genomic sequences. Choose a true breeding tall strain and true breeding short strain and type them for molecular markers. Mate them together to produce F1 offspring and evaluate whether the F1 are tall or short. Choose two true breeding tall strains and compare the genomic sequences. Choose a true breeding tall strain and true breeding short strain and type them for molecular markers. Mate them together to produce F1 offspring. Genotype the F1 to identify makers that are associated with differences in plant height. Choose a true breeding tall strain and true breeding short strain and type them for molecular markers. Mate them together to produce F1 offspring, then backeross the F1 offspring to produce F2 offspring carrying recombinant chromosomes from tall…arrow_forwardA blood stain from a crime scene and blood samples from four suspects were analyzed by PCR using fluorescent primers associated with three STR loci: D3S1358, vWA, and FGA. The resulting electrophoretograms are shown below. The numbers beneath each peak identify the allele (upper box) and the height of the peak in relative fluorescence units (lower box). Solve, (a) Since everyone has two copies of each chromosome and therefore, two alleles of each gene, what accounts for the appearance ofonly one allele at some loci? (b) Which suspect is a possible source of the blood? (c) Could the suspect be identifi ed using just one of the three STR loci? (d) What can you conclude about the amount of DNA obtained from Suspect 1 compared to Suspect 4?arrow_forwardstion 6 of 18 Suppose that a geneticist discovers a new mutation in Drosophila melanogaster that causes the flies to shake and quiver. She calls this mutation quiver, qu, and determines that it is due to an autosomal recessive gene. She wants to determine whether the gene encoding quiver is linked to the recessive gene for vestigial wings, vg. She crosses a fly homozygous for quiver and vestigial traits with a fly homozygous for the wild-type traits, and then uses the resulting F, females in a testcross. She obtains the flies from this testcross. Phenotype Number of flies vg* qu+ 230 vg qu 224 vg qut vg* qu 97 99 Test the hypothesis that the genes quiver and vestigial assort independently by calculating the chi-squared, X², for this hypothesis. Provide the X2 to one decimal place. X2 = Does the X value support the hypothesis that the quiver and vestigial genes assort independently? Why or why not? the partial table of critical values for X2 calculations to test this hypothesis.arrow_forward
- You may insert a hand-drawn diagram of your map, but the rest of the assignment must be fully typed. The data set attached presents the results of a testcross using female flies heterozygous for three traits and male flies, which are homozygous recessive. For simplicity, mutant alleles are shown with letters a, b, and c and wildtype alleles are indicated by a “+” symbol. For this part of the report do the following in order: a) Determine the gene order (which gene is in the middle?)d) Construct a genetic map for the three genes, including the map distances between them. Clearly indicate the logic you followed and show all your calculations. Include the full distance calculations for the two most distanced genes (do not just add the other 2 distances). Ensure the work is neat and clear and does not contain spelling or grammatical errors so that it is understandable.arrow_forwardA student crossed a female worm homozygous for the dpy-17 e164 allele with a wild-type male worm heterozygous for dpy-17 e164. He then scored all of the developing eggs/larva for the Dpy phenotype. He found 88 with the Dpy phenotype and 98 wild type. Do a Chi square test on phenotypic data to determine if your data supports the hypothesis that the mutation segregates as a single-gene mutation. Show your work in a table and include Null hypothesis Χ2 value dof p value Conclusionarrow_forwardThe picture shows a gel of PCR products for the loci SRY, AMELX/Y and ZFX/Y, for three controls and five test human individuals (1-5). Below the gel is the phenotypic sex of each individual, their fertility status, and the number of Barr bodies seen in the nucleus of a somatic cell in each case. The diagram to the right shows the positions of the tested loci on the human sex chromosomes, and also the positions of the PRKX and PRKYgenes. Which sample carries a derived X chromosome with a translocation due to ectopic crossover between the loci PRKX and PRKY: 46,X,derX,t(X,Y); ? 1 2 3 4 5arrow_forward
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