Biochemistry: Concepts and Connections (2nd Edition)
2nd Edition
ISBN: 9780134641621
Author: Dean R. Appling, Spencer J. Anthony-Cahill, Christopher K. Mathews
Publisher: PEARSON
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Textbook Question
Chapter 9, Problem 12P
One or more of the compounds shown below will satisfy each of the following statements. Not all compounds may be used; some may be used twice. Put the number (s) in the blank.
1. Found in chitin.________
2. An L-saccharide._______
3. The first residue attached to asparagines in N-linked glycans.______
4. A uronic acid. __________
5. A ketose. _______
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Select the term in column B which best matches the description in column A. There are more terms then
needed.
Column A
Column B
1. The pentose sugar found in DNA.
a) Cis fatty acid
b) Trans fatty acid
c) Coenzyme
d) Cofacipr
2. Commonly referred to as "insoluble fiber".
3. Considered to be an amphipathic molecule.
4. A molecule with the formula C18H3602 is probably a
e) Phospholipid
5. Bond created during the formation of the primary structure of a protein.
) Glycogen
6. A non-protein organic molecule needed for proper enzyme functioning.
g) Cellulose
7. Pyrimidine base found only in RNA.
h) Galactose
i) Fructose
8. Increasing the number of these molecules in the cell membrane would
increase the permeability of the cell membrane.
i) Thymine
k) Uracil
9. Bond which connects nucleotide monomers together.
1) Fatty acid
m) Disaccharide
n) Peptide bond
o) A-Helix
p) B-Pleated Sheet
q) Ribose
r) Deoxyribose
10.
Blueberries have proanthocyanidins, which contain catechin monomer, dimer, and trimer, and polymers of flavan-3-ol. Proanthocyanidins have bacterial anti-sticking properties that create a thin wall of protection on tissues. This anti-sticking property helps prevent pathogens that act against the stomach wall and tooth enamel. There are also antioxidant properties that are more effective than vitamin E and C. Blueberries also contain manganese which is a crucial mineral for human functioning. Manganese is a component of the bone. An intake of manganese helps structure and strengthen the human bones.
provide at least one alternative food item that provides one or more of the same macromolecules and/or minerals. Is your alternative healthier than the original selection? Are there any associated physiological disorders if one or more of the minerals provided were lacking from an individual’s diet?
Give an example of each of the following:a. epimerb. glycosidic linkagec. reducing sugard. monosaccharidee. anomerf. diastereomer
Chapter 9 Solutions
Biochemistry: Concepts and Connections (2nd Edition)
Ch. 9 - Prob. 1PCh. 9 - -D-Galactopyranose rotates the plane of polarized...Ch. 9 - Provide an explanation for the fact that a-...Ch. 9 - Why is a type O individual considered a universal...Ch. 9 - The disaccharide , -trehalose differs from the ,...Ch. 9 - A reducing sugar will undergo the Fehling...Ch. 9 - Prob. 7PCh. 9 - Prob. 8PCh. 9 - Indicate whether the structures shown are R and S...Ch. 9 - Prob. 10P
Ch. 9 - Draw (using Haworth projections) the fragments of...Ch. 9 - One or more of the compounds shown below will...Ch. 9 - Why do you suppose that the influenza virus...Ch. 9 - Prob. 14PCh. 9 - Are mannose and galactose epimers? Allose and...Ch. 9 - Prob. 16PCh. 9 - Explain in about one sentence why it is important...Ch. 9 - Prob. 18PCh. 9 - Prob. 19PCh. 9 - Prob. 20PCh. 9 - Prob. 21PCh. 9 - Prob. 22PCh. 9 - Prob. 23P
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- Define the following: 1. Cofactor 2. Coenzyme 3. "-ase" endingarrow_forwardA decapeptide which could resist burns was isolated from an endemic plant from Mt. Mayon. Deduce the amino acid sequence of the decapeptide given the following informations. Mercaptoethanol gave two pentapeptides F1 and F2. Chymotrypsin treatment of F1 releases S and a tetrapeptide (C,K,F,M) while F2 gave a dipeptide (M,S) and a tripeptide (C,F,K) F1 when treated with CNBr released a free homoserine lactone and a tetrapeptide. Trypsin treatment of F1 gave a tripeptide and a dipeptide. F2 treated with carboxypeptidase released free M while with trypsin gave free K and a tetrapeptide.arrow_forwardMake a table consisting of the following classes of Amino Acids (A). Give the 3 letter abbreviation, one letter symbol. Classify if the AA is essential or non essential, polar or non-polar. Write A for essential and B for non essential, write P for for polar and N for non polar. Draw the AA in the ff. format: Encircle the -R (side chain)do not include met in aliphaticamino acids. it has a separate box inS containing amino acidsarrow_forward
- Which of the following statements is correct regarding the structures below? CHO CHO CHO -Н НО H НО н- ОН -Н - ОН CH2OH CAB All are structures of D-sugars. All are structures of ketohexoses. Only CAR is a monosaccharide. O Only CAP is a L-sugar. -ОН -ОН H-OH H-OH H- ОН CH₂OH CAR но-н H-OH н НО т н-он CH₂OH CAP CH₂OH Fo НО-Н H НО-Н H он CH₂OH CATarrow_forwardWhat are the glycosidic linkages of the trisaccharide shown? α1→6, α1→6 α1→6, β1→6 α1→6, β1→5 α1→6, α1→5arrow_forwardA toxin is glycopeptide, X that is composed of an octapeptide and a saccharide Y. Glycopeptide X is composed of a glycan Y and an octapeptide. The octapeptide was cleaved by trypsin, giving 2 tetrapeptides of exactly the same composition except for its N-terminals. When the octapeptide was cleaved by chymotrypsin, it gave a pentapeptide and a tripeptide. DNFB treatment gave DNP-ser. The composition of the octapeptide is lys, ser, trp.and leu. The leu:ser ratio is 4:1. 1. What is the sequence of this octapeptide? Saccharide Y is a tetrasaccharide. To determine its linkages, a person methylated glycopeptide X effectively methylating saccharide Y. Cleavage gave the peptide and the following products: 2,3,4-tri-O-methyl-a-D-glucopyranoside acid, 2,3-di-O-methyl-ß-D- glucopyranoside, 1,3,4-tri-O- methyl-ß-D-glucuronic acid treatments to the isolated tetrasaccharide gave the following results: and 1,4,6-tri-O-methyl-ß-D-N- acetylgalactosamine. Further 1. A. Treatment of saccharide Y with an…arrow_forward
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