(a)
Interpretation:
The change in entropy is whether increased or decreased for the assembling a jigsaw puzzle has to be determined.
Concept Introduction:
Entropy
If the disorder increases in a system, then
If the disorder decreases in a system, then
(b)
Interpretation:
The change in entropy is whether increased or decreased for the given reaction has to be determined.
Concept Introduction:
Entropy
If the disorder increases in a system, then
If the disorder decreases in a system, then
(c)
Interpretation:
The change in entropy is whether increased or decreased for the precipitation by the mixing of two solutions has to be determined.
Concept Introduction:
Entropy
If the disorder increases in a system, then
If the disorder decreases in a system, then
(d)
Interpretation:
The change in entropy is whether increased or decreased for the given reaction is to be determined.
Concept Introduction:
Entropy
If the disorder increases in a system, then
If the disorder decreases in a system, then
(e)
Interpretation:
The change in entropy is whether increased or decreased for the given reaction has to be determined.
Concept Introduction:
Entropy
If the disorder increases in a system, then
If the disorder decreases in a system, then
(f)
Interpretation:
The change in entropy is whether increased or decreased for the given reaction has to be determined.
Concept Introduction:
Entropy
If the disorder increases in a system, then
If the disorder decreases in a system, then
Want to see the full answer?
Check out a sample textbook solutionChapter 7 Solutions
Fundamentals of General, Organic, and Biological Chemistry (8th Edition)
- The following exothermic reaction is at 0.00 °C and 1.00 atm SeO4 (g) ⇌ Se(g) + O2(g) , kc = 2.4 ×10-6 The reaction contains [SeO4] = 0.100 M, [Se] = 0.0034 M, [O2] = 0.0022 M Does the reaction exist at equilibrium? If not, in what direction it will proceed? Question 22 options:arrow_forwardConsider the nonenzymatic elementary reaction A → B. When the concentration of A is 20 mM, the reaction velocity is measured as 5 μM B produced per minute. (a) Calculate the rate constant for this reaction. (b) What is the molecularity of the reaction?arrow_forwardFor a particular reaction, AH° = −16.1 kJ/mol and AS° = −21.8 J/(mol·K). Assuming these values change very little with temperature, at what temperature does the reaction change from nonspontaneous to spontaneous in the forward direction? OT= Is the reaction in the forward direction spontaneous at temperatures greater than or less than the calculated temperature? less than greater than Karrow_forward
- A certain first order reaction has the rate law Rate = k[A] with k=0.0068 sec-1. If the initial concentration of A is 0.75 M, what will be the concentration of A after 1 minute? What is the half-life for this reaction? How much time will it take for 75% of A to react? How much A will be left after the passage of three half-lives? What is the initial rate of the reaction?arrow_forwardConsider the generic reaction2A+3B→2C,ΔHrxn=−100kJIf a reaction mixture initially contains 5 mol of A and 6 mol of B, how much heat (in kJ) will have evolved once the reaction has occurred to the greatest extent possible? 150kj 200kj 300kj 100kJarrow_forwardConsider the reaction A + 2B ----> C. If the molar mass of C is twice the molar mass of A, what mass of C is produced by the complete reaction of 10.0 g A?(a) 10.0 g(b) 30.0 g(c) 60.0 garrow_forward
- What are the benefits of measuring the initial rate of a reaction Vå for use in kinetic studies? (This is a multi-select question). [ES] can be measured accurately. changes in [S] are negligible, so the value of [S] is known. changes in Km are negligible, so Km can be treated as a constant. V₁ = Vmax. --> A negligible amount of product has formed, so that the back reaction P -- need not be considered. ESarrow_forwardUnder what conditions is the entropy H(X) equal to zero?arrow_forwardThe decomposition of crystalline N2O5 N2O5(s) → 2NO2(g) + 1/2O2(g) is an example of a reaction that is thermodynamically favored, even though it absorbs heat. At 25 °C we have the following values for the standard state enthalpy and free energy changes of the reaction: ∆H° = +109.6 kJ/mol ∆G° = -30.5 kJ/mol (a) Calculate ∆S ° at 25 °C. (b) Why is the entropy change so favorable for this reaction?arrow_forward
- The phosphoryl group transfer potentials for glucose-1-phosphate and glucose-6-phosphate are 20.9 kJ/mol and 13.8 kJ/mol, respectively. (a) What is the equilibrium constant for the reaction shown below at 25 °C? (b) If a mixture was prepared containing 1 m glucose-6-phosphate and 1 x 10-3 M glucose-1-phosphate, what would be the thermodynamically favored direction for the reaction?arrow_forwardWhich of the following statements is true? (a) The largerthe Q, the larger the ΔG°. (b) If Q = 0, the system is at equilibrium.(c) If a reaction is spontaneous under standardconditions, it is spontaneous under all conditions. (d) Thefree-energy change for a reaction is independent of temperature.(e) If Q > 1, ΔG > ΔG°.arrow_forwardFind kcat for a reaction in which Vmax is 4 × 10-4 mol•min-1 and the reaction mixture contains one microgram of enzyme (the molecular weight of the enzyme is 200,000 D). Show your work/reasoning.arrow_forward
- Biology 2eBiologyISBN:9781947172517Author:Matthew Douglas, Jung Choi, Mary Ann ClarkPublisher:OpenStax