(a)
Interpretation:
The following table is to be completed by assuming a fixed amount of gas:
0.55atm | 1.1L | 340K | ? | 3.0L | 298K |
Concept Introduction:
The concept of the combination gas will be used
Or,
Or,
Or,
Here,
Answer to Problem 44P
0.55atm | 1.1L | 340K | 0.18atm | 3.0L | 298K |
Explanation of Solution
The combined
Given that −
Initial volume, V1 = 1.1L
Initial temperature, T1 = 340K
Initial pressure, P1 = 0.55atm
Final temperature, T2 = 298K
Final volume, V2 = 3.0L
Put the values in above equation.
The final pressure of gas that is P2 = 0.18atm.
Thus,
a. | 0.55atm | 1.1L | 340K | 0.18atm | 3.0L | 298K |
(b)
Interpretation:
The following table is to be completed by assuming a fixed amount of gas:
735mmHg | 1.2L | 298K | 1.1atm | ? |
Concept Introduction:
The concept of the combination gas will be used
Or,
Or,
Or,
Here,
Answer to Problem 44P
735mmHg | 1.2L | 298K | 1.1atm | 0.89L |
Explanation of Solution
The combined gas law is used to determine the unknown values. The combined gas law includes the change in pressure-temperature and the volume of the gas. This relation is represented as
Given that
Initial volume, V1 = 1.2L
Initial temperature, T1 = 298
Initial pressure, P1 = 735mmHg
Final pressure, P2 = 1.1atm
Final temperature, T2 =
Or,
Put the values in the above equation.
The final volume of gas that is V2 = 0.89L.
Thus,
735mmHg | 1.2L | 298K | 1.1atm | 0.89L |
(c)
Interpretation:
The following table is to be completed by assuming a fixed amount of gas.
7.5atm | 230mL | 15atm | 0.45L | ? |
Concept Introduction:
The concept of the combination gas will be used
Or,
Or,
Or,
Here,
Answer to Problem 44P
7.5atm | 230mL | 15atm | 0.45L | 600K |
Explanation of Solution
The combined gas law is used to determine the unknown values. The combined gas law includes the change in pressure-temperature and the volume of the gas. This relation is represented as −
Given that −
Initial volume, V1 = 230mL
Initial pressure, P1 = 7.5atm
Initial temperature, T1 =
Final pressure, P2 = 15atm
Final volume, V2 = 0.45L
Put the values in the above equation.
The final volume of gas that is T2 = 600K.
Thus,
7.5atm | 230mL | 15atm | 0.45L | 600K |
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Chapter 7 Solutions
General, Organic, and Biological Chemistry - 4th edition
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