(a)
Interpretation:
The following table is to be completed by assuming a fixed amount of gas.
0.90atm | 4.0L | 265K | ? | 3.0L | 310K |
Concept Introduction:
The concept of the combination gas will be used
Or,
Or,
Or,
Here,
Answer to Problem 43P
0.90atm | 4.0L | 265K | 1.4atm | 3.0L | 310K |
Explanation of Solution
The combined
Given that
Initial volume, V1 = 4.0L
Initial temperature, T1 = 265K
Initial pressure, P1 = 0.90atm
Final temperature, T2 = 310K
Final volume, V2 = 3.0L
Put the values in the above equation.
The final pressure of gas that is P2 = 1.4atm
Thus,
a. | 0.90atm | 4.0L | 265K | 1.4atm | 3.0L | 310K |
(b)
Interpretation:
The following table is to be completed by assuming a fixed amount of gas.
1.2atm | 75L | 700mmHg | ? |
Concept Introduction:
The concept of the combination gas will be used
Or,
Or,
Or,
Here,
Answer to Problem 43P
1.2atm | 75L | 700mmHg | 110L |
Explanation of Solution
The combined gas law is used to determine the unknown values. The combined gas law includes the change in pressure-temperature and the volume of the gas. This relation is represented as
Given that
Initial volume, V1 = 75L
Initial temperature, T1 =
Initial pressure, P1 = 1.2atm
Final pressure, P2 = 700mmHg
Final temperature, T2 =
Or,
Put the values in the above equation.
The final volume of gas that is V2 =
Thus,
1.2atm | 75L | 700mmHg | 110L |
(c)
Interpretation:
The following table is to be completed by assuming a fixed amount of gas.
200mmHg | 125mL | 298K | 100mmHg | 0.62L | ? |
Concept Introduction:
The concept of the combination gas will be used
Or,
Or,
Or,
Here,
Answer to Problem 43P
200mmHg | 125mL | 298K | 100mmHg | 0.62L | 740K |
Explanation of Solution
The combined gas law is used to determine the unknown values. The combined gas law includes the change in pressure-temperature and the volume of the gas. This relation is represented as −
Given that −
Initial volume, V1 = 125mL
Initial pressure, P1 = 200mmHg
Initial temperature, T1 = 298K
Final pressure, P2 = 100mmHg
Final volume, V2 = 0.62L
Put the values in the above equation.
The final volume of gas that is T2 = 740K
The final table is
200mmHg | 125mL | 298K | 100mmHg | 0.62L | 740K |
Want to see more full solutions like this?
Chapter 7 Solutions
General, Organic, and Biological Chemistry - 4th edition
- 5.18 When helium escapes from a balloon, the balloon’s volume decreases. Based on your intuition about stretching rubber, explain how this observation is consistent with the gas law.arrow_forwardThe graph below shows the distribution of molecular speeds for helium and carbon dioxide at the same temperature. (a) Which curve could represent the behavior of carbon dioxide? (b) Which curve represents the gas that would effuse more quickly? (c) Which curve could represent the behavior of helium gas?arrow_forward
- General Chemistry - Standalone book (MindTap Cour...ChemistryISBN:9781305580343Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; DarrellPublisher:Cengage LearningChemistry: Matter and ChangeChemistryISBN:9780078746376Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl WistromPublisher:Glencoe/McGraw-Hill School Pub CoLiving By Chemistry: First Edition TextbookChemistryISBN:9781559539418Author:Angelica StacyPublisher:MAC HIGHER
- Chemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage LearningWorld of Chemistry, 3rd editionChemistryISBN:9781133109655Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCostePublisher:Brooks / Cole / Cengage LearningIntroductory Chemistry: A FoundationChemistryISBN:9781337399425Author:Steven S. Zumdahl, Donald J. DeCostePublisher:Cengage Learning