(a)
Interpretation: To determine the number of isotopes in an isotope.
Concept introduction:
Isotopes are any two or more different chemical forms of the same element that have the same number of protons but varying numbers of neutrons in their nucleus.
(a)
Answer to Problem 98A
So, no. of neutrons is 48.
Explanation of Solution
Given isotope:
The
The mass number is 84.
Expression for mass number is,
So, calculate no. of neutrons as shown,
So, no. of neutrons is 48.
(b)
Interpretation: To determine the number of isotopes in an isotope.
Concept introduction:
Isotopes are any two or more different chemical forms of the same element that have the same number of protons but varying numbers of neutrons in their nucleus.
(b)
Answer to Problem 98A
So, no. of neutrons is 44.
Explanation of Solution
Given isotope:
The atomic number is 35. The atomic number is no. of protons.
The mass number is 79.
Expression for mass number is,
So, calculate no. of neutrons as shown,
So, no. of neutrons is 44.
(c)
Interpretation: To determine the number of isotopes in an isotope.
Concept introduction:
Isotopes are any two or more different chemical forms of the same element that have the same number of protons but varying numbers of neutrons in their nucleus.
(c)
Answer to Problem 98A
So, no. of neutrons is 114.
Explanation of Solution
Given isotope:
The atomic number is 76. The atomic number is no. of protons.
The mass number is 190.
Expression for mass number is,
So, calculate no. of neutrons as shown,
So, no. of neutrons is 114.
(d)
Interpretation: To determine the number of isotopes in an isotope.
Concept introduction:
Isotopes are any two or more different chemical forms of the same element that have the same number of protons but varying numbers of neutrons in their nucleus.
(d)
Answer to Problem 98A
So, no. of neutrons is 110.
Explanation of Solution
Given isotope:
The atomic number is 75. The atomic number is no. of protons.
The mass number is 185.
Expression for mass number is,
So, calculate no. of neutrons as shown,
So, no. of neutrons is 110.
Chapter 6 Solutions
Chemistry 2012 Student Edition (hard Cover) Grade 11
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY