Chemistry 2012 Student Edition (hard Cover) Grade 11
Chemistry 2012 Student Edition (hard Cover) Grade 11
12th Edition
ISBN: 9780132525763
Author: Prentice Hall
Publisher: Prentice Hall
Question
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Chapter 6, Problem 100A

(a)

Interpretation Introduction

Interpretation: To calculate the no. of filled p-orbitals in the element.

Concept introduction:

The electron configuration of an element defines how its electrons are arranged throughout its atomic orbitals. Standard notation is used to represent atomic electron configurations, placing all electron-containing atomic subshells in sequential order. The number of electrons held by the subshell is indicated by superscript.

(a)

Expert Solution
Check Mark

Answer to Problem 100A

Filled p-orbital is 2

Explanation of Solution

The element is carbon. Its atomic number is 6 and its configuration is as shown,

  C6:1s22s22p2

So, filled p-orbital is 2.

(b)

Interpretation Introduction

Interpretation: To calculate the no. of filled p-orbitals in the element.

Concept introduction:

The electron configuration of an element defines how its electrons are arranged throughout its atomic orbitals. Standard notation is used to represent atomic electron configurations, placing all electron-containing atomic subshells in sequential order. The number of electrons held by the subshell is indicated by superscript.

(b)

Expert Solution
Check Mark

Answer to Problem 100A

3

Explanation of Solution

The element is phosphorous. Its atomic number is 15 and its configuration is as shown,

  P15:1s22s22p63s23p3

So, the filled p-orbital is 3.

(c)

Interpretation Introduction

Interpretation: To calculate the no. of filled p-orbitals in the element.

Concept introduction:

The electron configuration of an element defines how its electrons are arranged throughout its atomic orbitals. Standard notation is used to represent atomic electron configurations, placing all electron-containing atomic subshells in sequential order. The number of electrons held by the subshell is indicated by superscript.

(c)

Expert Solution
Check Mark

Answer to Problem 100A

3

Explanation of Solution

The element is oxygen. Its atomic number is 8 and its configuration is as shown,

  O8:1s22s22p4

So, filled p-orbital is 3.

(d)

Interpretation Introduction

Interpretation: To calculate the no. of filled p-orbitals in the element.

Concept introduction:

The electron configuration of an element defines how its electrons are arranged throughout its atomic orbitals. Standard notation is used to represent atomic electron configurations, placing all electron-containing atomic subshells in sequential order. The number of electrons held by the subshell is indicated by superscript.

(d)

Expert Solution
Check Mark

Answer to Problem 100A

3

Explanation of Solution

The element is nitrogen. Its atomic number is 7 and its configuration is as shown,

  N7:1s22s22p3

So, filled p-orbital is 3.

Chapter 6 Solutions

Chemistry 2012 Student Edition (hard Cover) Grade 11

Ch. 6.2 - Prob. 11LCCh. 6.2 - Prob. 12LCCh. 6.2 - Prob. 13LCCh. 6.2 - Prob. 14LCCh. 6.2 - Prob. 15LCCh. 6.2 - Prob. 16LCCh. 6.2 - Prob. 17LCCh. 6.3 - Prob. 18LCCh. 6.3 - Prob. 19LCCh. 6.3 - Prob. 20LCCh. 6.3 - Prob. 21LCCh. 6.3 - Prob. 22LCCh. 6.3 - Prob. 23LCCh. 6.3 - Prob. 24LCCh. 6.3 - Prob. 25LCCh. 6 - Prob. 26ACh. 6 - Prob. 27ACh. 6 - Prob. 28ACh. 6 - Prob. 29ACh. 6 - Prob. 30ACh. 6 - Prob. 31ACh. 6 - Prob. 32ACh. 6 - Prob. 33ACh. 6 - Prob. 34ACh. 6 - Prob. 35ACh. 6 - Prob. 36ACh. 6 - Prob. 37ACh. 6 - Prob. 38ACh. 6 - Prob. 39ACh. 6 - Prob. 40ACh. 6 - Prob. 41ACh. 6 - Prob. 42ACh. 6 - Prob. 43ACh. 6 - Prob. 44ACh. 6 - Prob. 45ACh. 6 - Prob. 46ACh. 6 - Prob. 47ACh. 6 - Prob. 48ACh. 6 - Prob. 49ACh. 6 - Prob. 50ACh. 6 - Prob. 51ACh. 6 - Prob. 52ACh. 6 - Prob. 53ACh. 6 - Prob. 54ACh. 6 - Prob. 55ACh. 6 - Prob. 56ACh. 6 - Prob. 57ACh. 6 - Prob. 58ACh. 6 - Prob. 59ACh. 6 - Prob. 60ACh. 6 - Prob. 61ACh. 6 - Prob. 62ACh. 6 - Prob. 65ACh. 6 - Prob. 66ACh. 6 - Prob. 67ACh. 6 - Prob. 68ACh. 6 - Prob. 69ACh. 6 - Prob. 70ACh. 6 - Prob. 71ACh. 6 - Prob. 72ACh. 6 - Prob. 74ACh. 6 - Prob. 75ACh. 6 - Prob. 76ACh. 6 - Prob. 78ACh. 6 - Prob. 80ACh. 6 - Prob. 81ACh. 6 - Prob. 82ACh. 6 - Prob. 83ACh. 6 - Prob. 85ACh. 6 - Prob. 86ACh. 6 - Prob. 87ACh. 6 - Prob. 88ACh. 6 - Prob. 89ACh. 6 - Prob. 90ACh. 6 - Prob. 91ACh. 6 - Prob. 92ACh. 6 - Prob. 93ACh. 6 - Prob. 94ACh. 6 - Prob. 95ACh. 6 - Prob. 96ACh. 6 - Prob. 97ACh. 6 - Prob. 98ACh. 6 - Prob. 99ACh. 6 - Prob. 100ACh. 6 - Prob. 1STPCh. 6 - Prob. 2STPCh. 6 - Prob. 3STPCh. 6 - Prob. 4STPCh. 6 - Prob. 5STPCh. 6 - Prob. 9STPCh. 6 - Prob. 10STPCh. 6 - Prob. 11STPCh. 6 - Prob. 12STP
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