Concept explainers
The value that the spring constant k should have so that passengers undergo an acceleration no more than
Answer to Problem 43P
Solution:
Explanation of Solution
Given:
Height of elevator above the top of spring
Maximum acceleration
Total mass of the elevator and passengers= M
FormulaUsed: Conservation of mechanical energy
Initial potential energy:
Final potential energy:
Initial kinetic energy:
Final kinetic energy:
Newton’s second law of motion:
Mass is m , a is acceleration and
Spring force:
Where, k is the spring constant and x is the extension.
Potential energy stored in spring:
k : spring constant
x : deformation in spring
Calculation:
Let maximum compression in spring be
Initial potential energy:
Initial kinetic energy:
Because lift is at test during breaking of cable:
Final potential energy:
Apply conservation of energy:
Apply condition of maximum acceleration
Substitute value of
Conclusion:
Spring constant of spring should be equal to
Chapter 6 Solutions
Physics: Principles with Applications
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