Part (a)
Speed of artist when he lands
Part (a)
Answer to Problem 38P
Solution:
Explanation of Solution
Given Info:
Mass of artist is 62 kg.
Vertical speed of artist is 4.5 m/s.
The artist lands 2 m below the trampoline.
Spring constant of trampoline is
Formula used: Kinetic energy of an object can be obtained by:
Potential Energy of spring can be obtained by:
Where m is mass, v velocity, x is elongation, K is spring constant.
Gravitational potential energy of an object can be obtained by:
Where, m is the mass, g is the gravitational acceleration and h is the height.
Calculation:
Applying conservation of energy, we equate the initial Potential energy to Kinetic energy when he lands on trampoline
Conclusion:
The speed of artist is 6.26 m/s when he lands.
Part (b)
Depression of trampoline
Part (b)
Answer to Problem 38P
Solution:
Explanation of Solution
Given:
Mass of artist is 62 kg.
Vertical speed of artist is 4.5 m/s.
The artist lands 2 m below the trampoline.
Spring constant of trampoline is
Formula used: Kinetic energy of an object is given by
Potential Energy of spring is given by
Where m is mass, v velocity, x is elongation, K is spring constant.
Calculation:
Applying conservation of energy, we equate the initial Potential energy to energy stored in trampoline at maximum depression
Substituting values:
Conclusion:
From the above calculation the depression of trampoline is 0.204 m.
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Physics: Principles with Applications
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