Universe: Stars And Galaxies
Universe: Stars And Galaxies
6th Edition
ISBN: 9781319115098
Author: Roger Freedman, Robert Geller, William J. Kaufmann
Publisher: W. H. Freeman
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Chapter 6, Problem 40Q
To determine

Whether or not the Hubble Space Telescope can distinguish any feature on Pluto.

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Tutorial You want to resolve 9.5 m features on Mercury with a 2 m telescope using 550 nm light. How close (in km) do you need to be? How does the orbital velocity (in km/s) at this altitude on Mercury compare to the orbital velocity at this altitude on Earth? (MẸ = 5.97 x 1024 kg, Re = 6.38 x 10 km, M = 3.30 x 1023 kg, R = 2440 km.) Part 1 of 4 The small angle formula tells us how distance and linear size are related to the angular size of an object. 2.06 x 105 D And the diameter of a telescope is related to the resolving power by: a- 2.06 x 105 diameter Part 2 of 4 First we should determine the resolving power of our 2 m telescope. a = 2.06 x 10 What is the wavelength you are trying to observe at? m diameter arc seconds
A telescope with diameter of 300 m observes in the radio part of the EM spectrum. What is the theoretical separation distance that can be resolved on the surface of Jupiter with 3 cm radio waves? Assume the distance to Jupiter is 928 million km.
The Mars Reconnaissance Orbiter (MRO) flies at an average altitude of 280km above the Martian Surface. If its cameras have an angular resolution of 0.2 arc seconds, what is the size of the smallest objects that the MRO can detect on the Martian surface? Use the equation: S =x × d /  206265  arcseconds / radian , where S is the true size of the object, d is the distance from the detector to the object, and x is the angular size of the object. Your answer will be in km (you can ignore the radians unit (it should appear, but the equation made a simplifying assumption that dropped it out.
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