Chapter 5, Problem 5.56P

Interpretation Introduction

Interpretation: The ratio of effusion rates for the ${\text{O}}_{\text{2}}$ and $\text{Kr}$ gas needs to be determined.

Concept Introduction:

Graham's Law of effusion of gases states that at same conditions, the effusion rate of two gases vary inversely with the square roots of molar masses of the gases. The mathematical expression for the Graham’s law for two gases ‘a’ and ‘b’ can be written as:

  $\frac{{\text{Rate}}_{\text{(a)}}}{{\text{Rate}}_{\text{(b}}{}_{\text{)}}}=\sqrt{\frac{{\text{Molar mass }}_{\text{(b)}}}{{\text{Molar mass}}_{\text{(a}}{}_{\text{)}}}}$