Concept explainers
(a)
Interpretation:
Whether the peroxide is present or not, the structure of a six-carbon
Concept introduction:
The addition of one or more than one halogen atom in an
(b)
Interpretation:
The structure of four compounds of formula
Concept introduction:
The addition of
(c)
Interpretation:
The structure of two alkenes that give
Concept introduction:
The oxymercuration reaction is an electrophilic addition reaction that converts an alkene into an alcohol and an
(d)
Interpretation:
The structure of an alkene with one double bond that would give only one product after ozonolysis followed by hydrogen peroxide is to be stated.
Concept introduction:
In oxidative cleavage both the sigma and pi bond of the alkene is broken and two carbonyl compounds are formed. When ozone is added to the alkene, unstable intermediate molozonide is formed which rearranges to ozonide.
(e)
Interpretation:
The structure of two stereoisomeric alkenes that would give
Concept introduction:
Hydroboration reaction is a two step reaction, which involves conversion of alkene into alcohol. This type of reaction follows anti-Markovnikov rule.
Anti markovinkov rule states that the positive part of acid attached to that carbon atom in
(f)
Interpretation:
The structure of an alkene with five carbons that would give the same product as a result of either oxymercuration-reduction or hydroboration-oxidation is to be drawn.
Concept introduction:
Hydroboration reaction is a two step reaction, which involves conversion of alkene into alcohol. This type of reaction follows anti-Markovnikov rule.
Anti markovinkov rule states that the positive part of acid attached to that carbon atom in
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Organic Chemistry
- (a) rate at which the following alcohols undergo dehydration to form alkenes in sulfuric acid OH OH OH (b) rate at which the following alkenes undergo addition with HBr to form an alkyl halidearrow_forwardArrange the alkenes in each set in order of increasing rate of reaction with HI and explain the basis for your ranking. Draw the structural formula of the major product formed in each case. (a) and (b) H3CH₂CHC=CH₂ and (H3C) 2C=CHCH3arrow_forwardWrite the structure for the major product of the following reaction.arrow_forward
- Name the following aldehydes and ketones: (a) (b) CH2CH2CHO CH3CH2CCHCH3 CH3 Draw structures corresponding to the following names: (b) 4-Chloropentan-2-one (e) 3-Methylbut-3-enalarrow_forward(S)-2-butanol reacts with potassium dichromate (K2CrO4) in aqueous sulfuric acid to give A(C4H3O). Treatment of A with ethylmagnesium bromide in anhydrous ether gives B(C,H140). Draw the structure of B.arrow_forwardTreatment of a hydrocarbon A (molecular formula C9H18) with Br2 in the presence of light forms alkyl halides B and C, both having molecular formula C9H17Br. Reaction of either B or C with KOC(CH3)3 forms compound D (C9H16) as the major product. Ozonolysis of D forms cyclohexanone and acetone. Identify the structures of A–D.arrow_forward
- (a) Give an acceptable name for compound A. (b) Draw the organic products formed when A is treated with each reagent: [1] H3O+; [2] −OH, H2O; [3] CH3CH2CH2MgBr (excess), then H2O; [4] LiAlH4, then H2O.arrow_forwardCompound A and compound B both have molecular formula C6H12. Both compounds produce epoxides when treated with a peroxy acid (RCO3H). The epoxide resulting from compound A was treated with aqueous acid (H3O+) and the resulting diol has no chiral centers. Identify the two possible structures for compound A (enter two numbers separated by commas with no spaces, e.g. "1,2") The epoxide resulting from compound B was treated with (H3O*) and the resulting diol was a meso compound. Identify compound B 2 3 potn 7 1 5 6 4 8arrow_forwardGive reasons for the following :(i) Ethyl iodide undergoes SN2 reaction faster than ethyl bromide.(ii) (±) 2-Butanol is optically inactive.(iii) C—X bond length in halobenzene is smaller than C—X bond length in CH3—X.arrow_forward
- (S)-2-butanol reacts with potassium dichromate (K2CrO4) in aqueous sulfuric acid to give A(C,HgO). Treatment of A with ethylmagnesium bromide in anhydrous ether gives B(C,H140). Draw the structure of B.arrow_forward2-bromo-2-methylbutane undergoes hydrolysis reaction with water, H2O toform compound W. Compound X and compound Y are produced when 2-bromo-2-methylbutane undergoes elimination reaction with alcoholic ofsodium hydroxide, NaOH. (ii) What is the type of reaction involved in the formation of compound W? (iii) Identify the major product of the elimination reaction between compound Xand compound Y based on Zaitsev’s rule.arrow_forwardDraw the structure of each product from the reaction of benzene with 2-chloro-1-methylcyclohexane using AlCl 3 as the catalyst and Identify the major product.arrow_forward