Chapter 5, Problem 136AE

a.

Interpretation Introduction

Interpretation: The empirical formula of Z compound under given conditions needs to be calculated.

Concept Introduction: The chemical proportions of atoms of each element that are present in the compound is given by its chemical formula.

The simplest positive integer ratio of atoms of each element that are present in the compound is given by its empirical formula.

b.

Interpretation Introduction

Interpretation: The molar mass of Z compound needs to be calculated.

Concept Introduction:The molar of the compound is calculated using formula from Graham’s law:

  $\frac{\text{effusion rate of compound 1}}{\text{effusion rate of compound 2}}=\sqrt{\frac{{\text{M}}_2}{{\text{M}}_1}}$

Where M represents molar mass.

c.

Interpretation Introduction

Interpretation: The molecular formula of Z compound needs to be calculated.

Concept Introduction: The chemical proportions of atoms of each element that are present in the compound is given by its chemical formula.

d.

Interpretation Introduction

Interpretation: The mole ratio of Z to Ar needs to be calculated when sample of gas is obtained by five effusion steps.

Concept Introduction:The mole ratio of Z to Ar can be calculated using Z:Ar ratio of the first mixture and ratio of effusion rates as:

  ${\left(\frac{\text{Z}}{\text{Ar}}\right)}_{\text{N}}\text{=}{\left(\frac{\text{effusion rate of Z}}{\text{effusion rate of Ar}}\right)}^{\text{N}}\text{×}{\left(\frac{\text{Z}}{\text{Ar}}\right)}_{\text{1}}$

Where N represents the number of effusion steps.