Concept explainers
Fifteen bacterial colonies growing on a complete medium are transferred to a minimal medium. Twelve of the colonies grow on minimal medium. a. Using terminology from the chapter, characterize the 12 colonies that grow on minimal medium and the 3 colonies that do not.
b. The three colonies that do not grow on minimal medium are transferred to minimal medium supplemented with the amino acid serine (min + Ser), and all three colonies grow. Characterize these three colonies.
c. The serine biosynthetic pathway is a three-step path-way in which each step is catalyzed by the enzyme product of a different gene, identified as enzymes A, B, and C in the diagram below.
Mutant 1 grows only on min
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Genetic Analysis: An Integrated Approach (3rd Edition)
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- What will be the results of the following experiment with explanations: A. Gram-positive bacteria and Gram-negative bacteria were placed into 0.2% NaCl solution. B. Gram-negative bacterial isolate was placed into 0. 3% NaCl solution containing only Lysozyme enzyme. C. Gram-positive bacteria and Gram-negative bacteria were placed into 0.09% NaCl solution containing only Penicillin?arrow_forwardUsing a schematic diagram, summarize the following steps in preparing competent cells for transformation: Inoculate a single colony of E. coli into 5 ml LB broth and incubate overnight at 37°C with moderate shaking (250 rpm). Add 200 μl of the culture into 50 ml LB broth and incubate overnight at 37°C with moderate shaking (250 rpm) to an OD600 = 1.3 to 1.5. Aliquot culture into five 15-ml pre-chilled, conical tubes. Leave tube on ice 5 to 10 min. Centrifuge cells 7 min at 1,600 × g (3,000 rpm), 4°C. Pour off supernatant and resuspend each pellet in 10 ml ice-cold CaCl2 solution (50 mM CaCl2), perform resuspension very gently, and keep on ice. Centrifuge cells 5 min at 1,100 × g (2,500 rpm), 4°C. Discard supernatant and resuspend each pellet in 10 ml ice-cold CaCl2 solution. Keep resuspended on ice for 30 min. Centrifuge cells 5 min at 1,100 × g, 4°C. Discard supernatant and resuspend each pellet in 10 ml ice-cold CaCl2 solution. Dispense cells (250 μl) into pre-chilled, sterile…arrow_forwardA bacterial culture is initially composed of 100 cells. After 1 hour the number of bacteria is 1.5 times the initial population. a. If the rate of growth is proportional to the number of bacteria present, determine the time necessary for the number of bacteria to triple. b. What is the time required for a culture with 1x106 of the same bacteria to triple? Explain your results. c. Under what conditions would the answers obtained in (b) be invalid?arrow_forward
- You have several different media onto which you inoculated eight strains of yeast (A-H). The media include a rich medium, an unsupplemented minimal medium, and minimal media each supplemented with one vitamin. Of the yeast strains, one is a prototroph and seven are auxotrophs for a vitamin. After overnight incubation, the following results were observed (tan patches represent growth): D plate 1 (A) B DE F GH plate 5 plate 4 plate 6 Which plate contains an unsupplemented minimal medium? [Select] Which plate contains a rich medium? [Select] plate 2 Which strain is a prototroph? [Select] Strain E is an auxotroph for niacin. Which plate reveals this specific auxotrophy? [ Select] plate 3 plate 7 One strain is an auxotroph for both choline and pantothenic acid. Which one is this most likely to be? [Select]arrow_forwardIn your laboratory, you have an F− strain of E. coli that is resistantto streptomycin and is unable to metabolize lactose, but it can metabolizeglucose. Therefore, this strain can grow on a medium thatcontains glucose and streptomycin, but it cannot grow on a mediumcontaining lactose. A researcher has sent you two E. colistrains in two separate tubes. One strain, let’s call it strain A, hasan F′ factor (an F prime factor) that carries the genes that are requiredfor lactose metabolism. On its chromosome, it also has thegenes that are required for glucose metabolism. However, it is sensitiveto streptomycin. This strain can grow on a medium containinglactose or glucose, but it cannot grow if streptomycin is addedto the medium. The second strain, let’s call it strain B, is an F−strain. On its chromosome, it has the genes that are required forlactose and glucose metabolism. Strain B is also sensitive to streptomycin.Unfortunately, when strains A and B were sent to you, thelabels had fallen…arrow_forwardWhat is the attached enzyme in this assay and its corresponding substrate? A. Horseradish peroxidase and OPD (o-phenylenediamine dihydrochloride) B. Horseradish peroxidase and PNPP (p-Nitrophenyl Phosphate, Disodium Salt) C. Horseradish peroxidase and TMB (3,3',5,5'-tetramethylbenzidine) D. Horseradish peroxidase and ABTS (2,2'-azinobis-3-ethylbenzothiazoleine-6- sulfonic acid)arrow_forward
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