Concept explainers
A male and a female mouse are each from pure-breeding albino strains. They have a litter of
a. Using clearly defined allele symbols of your own c hoosing, give the genotypes of parental and
b. What genetic phenomenon explains the
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Genetic Analysis: An Integrated Approach (3rd Edition)
- Pigment in mouse fur is only produced when the C allele is present. Individuals of the cc genotype are white. If color is present, it may be determined by the A, a alleles. AA or Aa results in agouti color, while aa results in black coats. (a) What F1 and F2 genotypic and phenotypic ratios are obtained from a cross between AACC and aacc mice? (b) In three crosses between agouti females whose genotypes were unknown and males of the aacc genotype, the following phenotypic ratios were obtained: (1) 8 agouti (2) 9 agouti (3) 4 agouti 8 white 10 black 5 black 10 white What are the genotypes of these female parents?arrow_forwardIn com, male sterility is controlled by maternal cytoplasmic elements. However, the presence of a nuclear fertility restorer gene (F_) restores fertility to male sterile lines. a. What are the crosses male sterile female x FF male? Give the genotypes and phenotypes of the offspring in each cross. Explain.arrow_forwardThe normal color of snapdragons is red. Some pure lines showing the variations of flower color have been found. When these lines were crossed, they gave the results attached. A. From the data given, determine if alleles of one, two, or three genes are generating these traits and why? B. Define the results of cross #5 with gene symbols and a complete explanation of ratios and any relevant genetic terms.arrow_forward
- In an autotetraploid Chinese primrose (Primula sinensis L.), the gene controlling stigma color is very near the centromere of the chromosome carrying it. The allele G for green stigma is dominant to g for red stigmas. A homozygous green autotetraploid strain is crossed with a homozygous red autotetraploid strain. a. What phenotypic ratio of green to red is expected if: i. The F1’s are intercrossed? ii. The F1’s are crossed with red plants b. If the G locus were 50 or more map units from the centromere, what types and proportions of gametes would the F1 be expected to produce? Derive the expected F2 phenotypic ratio.arrow_forwardIn an autotetraploid Chinese primrose (Primula sinensis), the gene controlling stigma color is very near the centromere of the chromosome carrying it. The allele G for green stigma is dominant to g for red stigmas. A homozygous green autotetraploid strain is crossed with a homozygous red autotetraploid strain. a. What phenotypic ratio of green to red is expected if: The F1’s are intercrossed? The F1’s are crossed with red plantsarrow_forwardMost flour beetles are black, but several color variants are known. Crosses of pure-breeding parents produced the following results (see table) in the F1 generation, and intercrossing the F1 from each cross gave the ratios shown for the F2 generation. The phenotypes are abbreviated Bl, black; Br, brown; Y, yellow; and W, white. a. From these results, deduce and explain the inheritance of these colors. b. Write the genotypes of each of the parents, the F1, and the F2 in all crosses.arrow_forward
- Multiple crosses were made between true-breeding lines of black and yellow Labrador retrievers. All the F1 progeny were yellow. When these progeny were intercrossed, they produced an F2 consisting of 121 yellow, 9 black and 30 chocolate. What epistatic ratio and what kind of epistasis is approximated in the F2? Propose a biochemical pathway for coat color in Labrador retrievers based on the type of epistasis. Correlate each genotype with the phenotype that would occur in your pathway. Also show the frequency of each genotype. A-B- A-bb aaB- aabbarrow_forwardA Neurospora cross was made between a strain that carried the mating-type allele A and the mutant allele arg-1and another strain that carried the mating-type allele aand the wild-type allele for arg-1 (+). Four hundred linear octads were isolated, and they fell into the sevenclasses given in the table below. (For simplicity, they areshown as tetrads.)a. Deduce the linkage arrangement of the mating-typelocus and the arg-1 locus. Include the centromere orcentromeres on any map that you draw. Label all intervalsin map units.b. Diagram the meiotic divisions that led to class 6. Labelclearlyarrow_forwardDeduce the phenotypic proportions in the progeny of thefollowing crosses of autotetraploids in which the a+/a locus is very close to the centromere. (Assume that the fourhomologous chromosomes of any one type pair randomly two by two and that only one copy of the a+ allele isnecessary for the wild-type phenotype.)a. a+/a+/a/a × a/a/a /ab. a+/a/a /a × a/a/a/ac. a+/a/a /a × a+/a/a /ad. a+/a+/a /a × a+/a/a /aarrow_forward
- Rabbits may be classified as agouti, chinchilla, Himalayan, or albino according to coat color. A cross between CC h x C ch c produced 5 agouti, 3 chinchilla and 2 Himalayans. a. What are the phenotypes of the parent rabbits? Copy the genotypes then write the corresponding phenotype beside each. b. What are the genotypes of the F1s? c. What mode of inheritance is exhibited? d. If the two F1 agouti genotypes will be crossed, what percentage of theiroffspring will have the same phenotype? e. What will be the genotypes of the rabbits in (d)?arrow_forwardThree genes in fruit flies affect a particular trait, and at least one dominant allele of each gene is necessary to get a wild-type phenotype. a. What phenotypic ratio would you predict among the progeny if you crossed triply heterozygous flies? b. You cross a particular wild-type male in succession with three tester strains. In the cross with one tester strain (AA bb cc), only 1/4 of the progeny are wild type. In the crosses involving the other two tester strains (aa BB cc and aa bb CC), half of the progeny are wild type. What is the genotype of the wild-type male? (Pls help asap!!)arrow_forward. a. A mouse cross A/a ⋅ B/b × a/a ⋅ b/b is made, and inthe progeny there are25% A/a ⋅ B/b, 25% a/a ⋅ b/b,25% A/a ⋅ b/b, 25% a/a ⋅ B/bExplain these proportions with the aid of simplifiedmeiosis diagrams.b. A mouse cross C/c ⋅ D/d × c/c ⋅ d/d is made, and inthe progeny there are45% C/c ⋅ d/d, 45% c/c ⋅ D/d,5% c/c ⋅ d/d, 5% C/c ⋅ D/dExplain these proportions with the aid of simplifiedmeiosis diagrams.arrow_forward
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